`a)17/7-3/8+4/7-3/5`

`=(17/7+4/7)-(3/8+3/5)`

`=21/7-(15/40+24/40)=3-39/40=120/40-39/40=81/40`

`b)15/11xx2001/2005-3/11xx2001/2005-1/11xx2001/2005`

`=2001/2005xx(15/11-3/11-1/11)`

`=2001/2005xx11/11`

`=2001/2005`

\(\dfrac{5}{9}\times\dfrac{5}{11}+\dfrac{5}{11}\times\dfrac{4}{9}\)
\(=\left(\dfrac{5}{9}+\dfrac{4}{9}\right)\times\dfrac{5}{11}\)
\(=1\times\dfrac{5}{11}\)
\(=\dfrac{5}{11}\)
#NoSimp

    \(\dfrac{5}{9}\) \(\times\) \(\dfrac{5}{11}\) + \(\dfrac{5}{11}\) \(\times\) \(\dfrac{4}{9}\)

=   \(\dfrac{5}{11}\) \(\times\) ( \(\dfrac{5}{9}\) + \(\dfrac{4}{9}\))

= \(\dfrac{5}{11}\) \(\times\) \(\dfrac{9}{9}\)

= \(\dfrac{5}{11}\)

    5995​ $\times$ 511115​ + 511115​ $\times$ 4994​

=   511115​ $\times$ ( 5995​ + 4994​)

= 511115​ $\times$ 9999​

= 511115​

`4/5 +4+11/5`

`=(4/5 +11/5)+4`

`= 15/5 +4`

`=3+4`

`=7`

\(\dfrac{4}{5}+4+\dfrac{11}{5}\\ =\left(\dfrac{4}{5}+\dfrac{11}{5}\right)+4\\ =\dfrac{11+4}{5}+4\\ =\dfrac{15}{5}+4\\ =3+4=7\)

\(\dfrac{4}{5}\) + 4 + \(\dfrac{11}{5}\)

= ( \(\dfrac{4}{5}\) + \(\dfrac{11}{5}\)) + 4

= \(\dfrac{15}{5}\) + 4

= 3 + 4

= 7

7/11 : 3/5 + 4/11 : 3/5

= (7/11 + 4/11) : 3/5

=1:3/5=5/3

\(\left(\dfrac{7}{11}+\dfrac{4}{11}\right):\dfrac{3}{5}=\dfrac{11}{11}:\dfrac{3}{5}=\dfrac{1}{1}:\dfrac{3}{5}=\dfrac{1}{1}\times\dfrac{5}{3}=\dfrac{5}{3}\)

= (7/11 + 4/11) : 3/5

=1:3/5=5/3

\(-\dfrac{5}{14}:\dfrac{7}{17}-\dfrac{5}{14}:\dfrac{7}{11}-\dfrac{6}{7}=\dfrac{5}{14}:\left(-\dfrac{7}{17}\right)-\dfrac{5}{14}:\dfrac{7}{11}-\dfrac{6}{7}\)

\(=\dfrac{5}{14}.\left(-\dfrac{17}{7}\right)-\dfrac{5}{14}.\dfrac{11}{7}-\dfrac{6}{7}=\dfrac{5}{14}.\left(-\dfrac{17}{7}-\dfrac{11}{7}\right)-\dfrac{6}{7}\)

\(=\dfrac{5}{14}.\left(-4\right)-\dfrac{6}{7}=-\dfrac{10}{7}-\dfrac{6}{7}=-\dfrac{16}{7}\)

\(-\dfrac{5}{14}\) hay \(\dfrac{5}{14}\) vậy

giúp mk với

(23/11+10/11) + 1/5

= 3 + 1/5 

= 16/5

    \(\dfrac{23}{11}+\left(\dfrac{1}{5}+\dfrac{10}{11}\right)\)

\(=\dfrac{23}{11}+\dfrac{1}{5}+\dfrac{10}{11}\)

\(=\left(\dfrac{23}{11}+\dfrac{10}{11}\right)+\dfrac{1}{5}\)

\(=3+\dfrac{1}{5}=\dfrac{3}{1}+\dfrac{1}{5}\)

\(=\dfrac{15}{5}+\dfrac{1}{5}\) \(=\dfrac{15+1}{5}=\dfrac{16}{5}\)

`5/9+5/11+4/9+4/11+2/11`

`=(5/9+4/9)+(5/11+4/11+2/11)`

`=9/9+11/11`

`=1+1`

`=2`

= (5/9 + 4/9) + (5/11 + 4/11 + 2/11)

= 9/9 + 11/11 = 2

= 2

`a) 5 / 13 xx 4 / 15 xx 13 = [ 5 xx 4 xx 13 ] / [ 13 xx 5 xx 3 ] = 4 / 3`

`b) ( 3 / 7 + 5 / 2 ) xx 7 / 5 = 3 / 7 xx 7 / 5 + 5 / 2 xx 7 / 5 = 3 / 5 + 7 / 2 = 6 / 10 + 35 / 10 = 41 / 10`

`c) 1 / 5 xx 11 / 18 + 11 / 18 xx 3 / 5 = 11 / 18 xx ( 1 / 5 + 3 / 5 ) = 11 / 18 xx 4 / 5 = [ 11 xx 2 xx 2 ] / [ 2 xx 9 xx 5 ] = 22 / 45`

\(a,\dfrac{5}{13}\times\dfrac{4}{15}\times13=\dfrac{4}{3}\)

\(b,\left(\dfrac{3}{7}+\dfrac{5}{2}\right)\times\dfrac{7}{5}=\left(\dfrac{6}{14}+\dfrac{35}{14}\right)\times\dfrac{7}{5}=\dfrac{41}{14}\times\dfrac{7}{15}=\dfrac{41}{30}\)

\(c,\dfrac{1}{5}\times\dfrac{11}{18}+\dfrac{11}{18}\times\dfrac{3}{5}=\dfrac{11}{18}\times\left(\dfrac{1}{5}+\dfrac{3}{5}\right)=\dfrac{11}{18}\times\dfrac{4}{5}=\dfrac{22}{45}\)