(-32).74-32.27+32

=32.(-74)-32.27+32

=32.[(-74)-27+1]

=32.(-100)

=-3200

\(-32\cdot74-32\cdot27+32\)

\(=32\left(-74-27+1\right)\)

\(=32\cdot\left(-100\right)\)

=-3200

(-32).74-32.27+32

= 32.(-74)-32.27+32

= 32.[(-74)-27+1]

= 32.(-100)

= -3200

Đáp số: 4700

32.27 + 47.73 + 27.15

= (32.27+27.15)+47.73

=27.(32+15)+47.73

= 27.47 + 47.73

= 47.(27+73)

= 47. 100

=4700

  32.27+154.69+73.32-69.54

= 32.27+73.32+154.69-69.54

= 32.(27+73)+(154-54).69

= 32.100 + 100.69

= (32+69).100

= 101.100

= 10100

32.27+154.69+73.32-69.54

=(32.27+73.32)+(69.154-69.54)

=32.100+69.100

=3200+6900

=10100

\(2.21.18+12.9+76.36\)

\(=36.21+36.3+76.36\)

\(=36.\left(21+3+76\right)\)

\(=36.100=3600\)

b)  \(32.27+154.69+73.32-69.54\)

\(=32.\left(27+73\right)+69.\left(154-54\right)\)

\(=32.100+69.100\)

\(=100.\left(32+69\right)\)

\(=100.101=10100\)

`a, (3x-1)^3-(3x+1)^3`

`= (3x-1-3x-1)(9x^2-6x+1+9x^2-1+9x^2+6x+1`

`= (-2)(27x^2 +1)`

`= -54x^2-2`.

`b, (1+3x)^3 - (1-3x)^3`

`= 1+ 9x + 27x^2 + 27x^3 - 1 + 9x - 27x^2 + 27x^3`

`= 54x^3 + 18x`.

`c, = 54x^3 + 18x -1 +9x^2`.

a: =27x^3-27x^2+9x-1-27x^3-27x^2-9x-1

=-54x^2-2

b: =27x^3+27x^2+9x+1-27x^3+27x^2-9x+1

=54x^2+2

c: =54x^2+2+(3x-1)(3x+1)

=54x^2+2+9x^2-1

=63x^2+1

\(3x^3+6x^2-3x\Rightarrow ChonD\)

D

hinh nhu la de bi sai 

Em kiểm tra lại đề bài, \(3^x+3^{x+2}+3^{x+2}\) hay \(3^x+3^{x+1}+3^{x+2}\)