\(2^{x+1}-2^x=3^2\)

\(\Rightarrow2^x\cdot\left(2-1\right)=9\)

\(\Rightarrow2^x=9\)

\(\Rightarrow x\in\varnothing\)

\(2^{x+1}-2^x=3^2\)

=>2^x*2-2^x=9

=>2^x=9

=>\(x\in\varnothing\)

=-77.16

=-1232

\(\sqrt{19+6\sqrt{2}}=\sqrt{\left(\sqrt{18}+1\right)^2}=\sqrt{18}+1\)

\(\sqrt{19+6\sqrt{2}}=3\sqrt{2}+1\)

\(9+4\sqrt{2}=\left(2\sqrt{2}+1\right)^2\)

\(\Rightarrow6x-36=72\\ \Rightarrow6x=108\\ \Rightarrow x=18\)

6x-36=72

6x=72+36

6x=108

x=108:6

x=18

\(x=18\)

\(3^{x+1}=\left(\dfrac{1}{81}\right)^2=\left(3^{-4}\right)^2=3^{-8}\)

\(\Rightarrow x+1=-8\Rightarrow x=-9\)

\(\dfrac{2x}{14}-\dfrac{x}{14}=-\dfrac{21}{14}\)

\(2x-x=-21\)

\(x=-21\)

x=-21

(1 + 2 + 3 + ... + 31 + 32) : 11 + 2

= [(32 + 1).(32 - 1 + 1) : 2] : 11 + 2

= (33 . 32 : 2) : 11 + 2

= 33 . 16 : 11 + 2

= 3 . 16 + 2

= 48 + 2

= 50

Đặt A = 1 + 2 + ... + 31 + 32

Số số hạng trong A là: (32 - 1) : 1 + 1 = 32 (số)

Tổng A bằng : (32 + 1).32 : 2 = 528

Thay A = 528 vào biểu thức (1 + 2 + 3 +...+ 31 + 32) : 11 + 2, ta được:

528 : 11 + 2

= 48 + 2 = 50

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