\(\frac{3x-2}{3}=\frac{2y+1}{4}=\frac{z-6}{5}=\frac{6x+10y+2y-11}{11x+3}\)
\(\dfrac{3x-2}{3}=\dfrac{2y+1}{4}=\dfrac{z-6}{5}=\dfrac{6x+10y+2z-11}{11x+3}\)
Giúp với !!!
5,thực hiện phép tính
1,\(\frac{4y^2}{11x^4}.\left(-\frac{3x^2}{8y}\right)\)
2,\(\frac{4x^2}{5y^2}:\frac{6x}{5y}:\frac{2x}{3y}\)
3,\(\frac{x^2-4}{3x+12}.\frac{x+4}{2x-4}\)
4,\(\frac{5x+10}{4x-8}.\frac{4-2x}{x+2}\)
5,\(\frac{x^2-36}{2x+10}.\frac{3}{6-x}\)
6,\(\frac{x^2-9y^2}{x^2y^2}.\frac{3xy}{2x-6y}\)
7,\(\frac{3x^2-3y^2}{5xy}.\frac{15x^2y}{2y-2x}\)
1, \(\frac{4y^2}{11x^4}.\left(-\frac{3x^2}{8y}\right)\)\(=\frac{4y.y}{11x^2.x^2}.\frac{-3x^2}{2.4y}\)\(=\frac{y}{11x^2}.\frac{-3}{2}=\frac{-3y}{22x^2}\)
2, \(\frac{4x^2}{5y^2}:\frac{6x}{5y}:\frac{2x}{3y}\)\(=\frac{4x^2}{5y^2}.\frac{5y}{6x}.\frac{3y}{2x}\)\(=\frac{2x.2x}{5y.y}.\frac{5y}{3.2x}.\frac{3y}{2x}\)\(=\frac{2x}{y}.\frac{1}{3}.\frac{3y}{2x}\)
\(\frac{2x}{3y}.\frac{3y}{2x}=1\)
3, \(\frac{x^2-4}{3x+12}.\frac{x+4}{2x-4}\)\(=\frac{\left(x-2\right)\left(x+2\right)}{3\left(x+4\right)}.\frac{x+4}{2\left(x-2\right)}\)\(=\frac{\left(x+2\right)}{3}.\frac{1}{2}=\frac{x+2}{6}\)
4, \(\frac{5x+10}{4x-8}.\frac{4-2x}{x+2}\)\(=\frac{5\left(x+2\right)}{4\left(x-2\right)}.\left(-\frac{2\left(x-2\right)}{x+2}\right)=\frac{5}{4}.\frac{-2}{1}=-\frac{5}{2}\)
5, \(\frac{x^2-36}{2x+10}.\frac{3}{6-x}=\frac{\left(x-6\right)\left(x+6\right)}{2\left(x+5\right)}.\frac{3}{-\left(x-6\right)}=\frac{x+6}{2\left(x+5\right)}.\frac{-3}{1}=\frac{-3\left(x+6\right)}{2\left(x+5\right)}\)
6, \(\frac{x^2-9y^2}{x^2y^2}.\frac{3xy}{2x-6y}=\frac{\left(x-3y\right)\left(x+3y\right)}{\left(xy\right)^2}.\frac{3xy}{2\left(x-3y\right)}=\frac{x+3y}{xy}.\frac{3}{2}=\frac{3\left(x+3y\right)}{2xy}\)
7, \(\frac{3x^2-3y^2}{5xy}.\frac{15x^2y}{2y-2x}=\frac{3\left(x-y\right)\left(x+y\right)}{5xy}.\frac{5xy.3x}{-2\left(x-y\right)}=\frac{3\left(x+y\right)}{1}.\frac{3x}{-2}=\frac{-9x\left(x+y\right)}{2}\)
bài 1 : thực hiện các phép tính
a. \(\frac{4x-1}{3x^2y}-\frac{7x-1}{3x^2y}\)
b.\(\frac{4x+1}{2}-\frac{3x+2}{3}\)
c.\(\frac{5x^2-y^2}{xy}-\frac{3x-2y}{y}\)
d.\(\frac{3x}{5x+5y}-\frac{x}{10x-10y}\)
e.\(\frac{x+3}{x}-\frac{x}{x-3}+\frac{9}{x^2-3x}\)
f.\(\frac{x+3}{x^2-1}-\frac{1}{x^2+x}\)
g.\(\frac{1}{3x-2}-\frac{4}{3x+2}-\frac{-10x+8}{9x^2-4}\)
h.\(\frac{x+9y}{x^2-9y^2}-\frac{3y}{x^2+3xy}\)
i.\(\frac{3}{2x+6}-\frac{x-6}{2x^2+6x}\)
bài 1: Thực hiện các phép tính
a.\(\frac{4x-1}{3x^2y}-\frac{7x-2}{3x^2y}\)
b.\(\frac{4x+1}{2}-\frac{3x+2}{3}\)
c.\(\frac{5x^2-y^2}{xy}-\frac{3x-2y}{y}\)
d.\(\frac{3x}{5x+5y}-\frac{x}{10x-10y}\)
e. \(\frac{x+3}{x}-\frac{x}{x-3}+\frac{9}{x^2-3x}\)
f..\(\frac{x+3}{x^2-1}-\frac{1}{x^2+x}\)
g. \(\frac{1}{3x-2}-\frac{4}{3x+2}-\frac{-10x+8}{9x^2-4}\)
h.\(\frac{x+9y}{x^2-9y^2}-\frac{3y}{x^2+3xy}\)
i.\(\frac{3}{2x+6}-\frac{x-6}{2x^2+6x}\)
a)Cho \(\frac{3x-2y}{4}=\frac{2z-4x}{3}=\frac{4y-3z}{2}\)và 3x-2y+z=40.Tìm x,y,z
b)Tìm x,y biết \(\frac{2x+1}{5}=\frac{3y-2}{7}=\frac{2x+3y-1}{6x}\)
Giúp mik với!help me~~~
1, Thực hiện tính cộng, trừ, nhân, chia các phân thức sau:
a,\(\frac{2x-7}{10x-4}-\frac{3x+5}{4-10x}\)
b,\(\frac{2x+3}{4x^2y^2}:\frac{6x+9}{10x^2y}\)
c,\(\frac{x^2-y^2}{6x^2y^2}:\frac{x+y}{3xy}\)
d,\(\left(\frac{3x}{1-3x}+\frac{2x}{3x+1}\right):\frac{6x^2+10x}{1-6x+9x^2}\)
a) \(\frac{2x-7}{10x-4}-\frac{3x+5}{4-10x}\)
\(=\frac{2x-7}{10x-4}-\frac{-\left(3x+5\right)}{-\left(4-10x\right)}\)
\(=\frac{2x-7}{10x-4}-\frac{5-3x}{10x-4}\)
\(=\frac{2x-7-\left(5-3x\right)}{10x-4}\)
\(=\frac{2x-7-5+3x}{10x-4}\)
\(=\frac{5x-12}{10x-4}\)
Tìm x , y , z :
a) \(\frac{x-1}{2}=\frac{y-2}{3}=\frac{z-3}{4}\) và 2x + 3y - z = 50
b) \(\frac{x-1}{2}=\frac{y+3}{4}=\frac{x-5}{6}\)và 5x - 3y - 4z = 46
c) \(\frac{2x}{5}=\frac{3y}{10}=\frac{z}{12}\)và x + y + z = 107
d) \(\frac{5z-6y}{4}=\frac{6x-4z}{5}=\frac{4y-5z}{6}\)và 3x - 2y + 5z = 96
a
Đặt \(\frac{x-1}{2}=\frac{y-2}{3}=\frac{z-3}{4}=k\)
\(\Rightarrow x=2k+1;y=3k+2;z=4k+3\)
Thay vào,ta được:
\(2\left(2k+1\right)+3\left(3k+2\right)-\left(4k+3\right)=50\)
\(\Leftrightarrow4k+2+9k+6-4k-3=50\)
\(\Leftrightarrow9k+5=50\)
\(\Leftrightarrow9k=45\)
\(\Leftrightarrow k=5\)
\(\frac{x-1}{2}=\frac{y+3}{4}=\frac{z-5}{6}=\frac{5x-5}{10}=\frac{3y+9}{12}=\frac{4z-20}{24}\)
\(=\frac{5x-5-3y-9-4z+20}{10-12-24}=\frac{\left(5x-3y-4z\right)+\left(20-5-9\right)}{26}=\frac{46+6}{26}=2\)
\(\Rightarrow x=2\cdot2+1=5\)
\(y=4\cdot2-3=5\)
\(z=2\cdot6+5=17\)
Câu c tương tự như câu 1
\(c,\frac{2x}{5}=\frac{3y}{10}=\frac{z}{12}\)và x + y + z = 107
Ta có : \(\frac{2x}{5}=\frac{3y}{10}=\frac{z}{12}\Leftrightarrow\frac{x}{\frac{5}{2}}=\frac{y}{\frac{10}{3}}=\frac{z}{12}=\frac{x+y+z}{\frac{5}{2}+\frac{10}{3}+12}=\frac{107}{\frac{107}{6}}=107\cdot\frac{6}{107}=6\)
Vậy : \(\hept{\begin{cases}\frac{2x}{5}=6\\\frac{3y}{10}=6\\\frac{z}{12}=6\end{cases}}\Leftrightarrow\hept{\begin{cases}x=15\\x=20\\z=72\end{cases}}\)
1,Thực hiện phép tính
a,\(\frac{3}{2x^2+2x}+\frac{2x-1}{x^2-1}-\frac{2}{x}\)
b,\(\frac{3x}{5x+5y}-\frac{x}{10x-10y}\)
c,\(\frac{5x^2-y^2}{xy}-\frac{3x-2y}{y}\)
d,\(\frac{3}{2x+6}-\frac{x-6}{2x^2+6x}\)
\(\frac{3x}{5x+5y}-\frac{x}{10x-10y}\)
\(=\frac{3x}{5\left(x+y\right)}-\frac{x}{10\left(x+y\right)}\)
\(=\frac{30x\left(x-y\right)-5x\left(x+y\right)}{5\left(x+y\right).10\left(x+y\right)}\)
\(=\frac{5x\left(5x-7y\right)}{50\left(x+y\right)\left(x-y\right)}\)
\(=\frac{x\left(5x-7y\right)}{\left(x+y\right)\left(x-y\right)}\)
chỗ cuối tớ sai
\(=\frac{x\left(5x-7y\right)}{10\left(x+y\right)\left(x-y\right)}\)
đây nha , e xin lỗi
a) \(\frac{3}{2x^2+2x}+\frac{2x-1}{x^2-1}-\frac{2}{x}=\frac{3}{2x\left(x+1\right)}+\frac{2x-1}{\left(x-1\right)\left(x+1\right)}-\frac{2}{x}\)
\(=\frac{3\left(x-1\right)+\left(2x-1\right)-2.2\left(x-1\right)\left(x+1\right)}{2x\left(x-1\right)\left(x+1\right)}\)
\(=\frac{3x-2x+4x^2-2x-4x^2+4x-4x+4}{2x\left(x-1\right)\left(x+1\right)}\)
\(=\frac{x+1}{2x\left(x-1\right)\left(x+1\right)}\)
\(=\frac{1}{2x\left(x-1\right)}\)
b) \(\frac{3x}{5x+5y}-\frac{x}{10x-10y}=\frac{3x}{5\left(x+y\right)}-\frac{x}{10\left(x-y\right)}\)
\(=\frac{3x.10\left(x-y\right)-x.5\left(x+y\right)}{50\left(x-y\right)\left(x+y\right)}\)
\(=\frac{30x\left(x-y\right)+5x\left(x+y\right)}{50\left(x-y\right)\left(x+y\right)}\)
\(=\frac{5x\left[6\left(x-y\right)-\left(x+y\right)\right]}{50\left(x-y\right)\left(x+y\right)}\)
\(=\frac{5x\left(5x-7y\right)}{50\left(x-y\right)\left(x+y\right)}\)
\(=\frac{x\left(5x-7y\right)}{10\left(x-y\right)\left(x+y\right)}\)
c) \(\frac{5x^2-y^2}{xy}-\frac{3x-2y}{y}=\frac{5x^2-y-x\left(3x-2y\right)}{xy}\)
\(=\frac{5x^2-y-3x^2+2xy}{xy}\)
\(=\frac{2x^2-y+2xy}{xy}\)
d) \(\frac{3}{2x+6}-\frac{x-6}{2x^2+6x}=\frac{3}{2\left(x+3\right)}-\frac{x-6}{2x\left(x+3\right)}\)
\(=\frac{3x-x+6}{2x\left(x+3\right)}\)
\(=\frac{2x+6}{2x\left(x+3\right)}\)
\(=\frac{2\left(x+3\right)}{2x\left(x+3\right)}\)
\(=\frac{2}{2x}=\frac{1}{x}\)
Tìm x,y,z biết:
a) \(\frac{x-3}{x+5}=\frac{5}{7}\)
b)\(\frac{x-1}{x+2}=\frac{x-2}{x+3}\)
c)\(\frac{x}{y}=\frac{3}{4};\frac{y}{z}=\frac{5}{7}\)
d)\(\frac{x}{2}=\frac{y}{5}=\frac{z}{6}\)và 3x + 2y - z = 50
e)\(\frac{x}{3}=\frac{y}{2}=\frac{z}{6}\)và 5.x2 y2 - z2 = 117
f) \(\frac{x-1}{2}=\frac{y+3}{4}=\frac{z-5}{6}\)và 5z - 3x - 4y = 50
g) \(\frac{1+2y}{18}=\frac{1+4y}{24}=\frac{1+6y}{6x}\)
h)\(\frac{1+3y}{12}=\frac{1+5y}{5x}=\frac{1+7y}{4x}\)
Các bạn chỉ cần trả lời 4 câu bất kì thôi nhé
Mình chỉ cần các bạn trả lời 4 câu nhanh nhất mình sẽ k.
a)x-3/x+5=5/7 suy ra 7.(x-3) = 5(x+5)
Tương đương : 7x - 21 = 5x + 25
7x - 5x = 25 + 21 = 46
2x = 46 suy ra : x = 46/2 = 23
Vậy x = 23