Tìm x : 3\(^{\left|x-1\right|+1}\) -18x+2x\(\times3^{\left|x-1\right|}\)− 27 = 0
Những câu hỏi liên quan
Tìm x :
a) \(3^{x+1}+2x.3^x-18x-27=0\)
b) \(\dfrac{1}{2}\left|2x+5\right|-\dfrac{5}{4}\left|4x+10\right|+\dfrac{7}{3}\left|-20-8x\right|=\dfrac{1}{6}\)
a: \(\Leftrightarrow3^x\cdot3+2x\cdot3^x-18x-27=0\)
\(\Leftrightarrow3^x\left(2x+3\right)-9\left(2x+3\right)=0\)
\(\Leftrightarrow\left(2x+3\right)\left(3^x-9\right)=0\)
=>x=2 hoặc x=-3/2
b: \(\Leftrightarrow\left|2x+5\right|\cdot\dfrac{1}{2}-\dfrac{5}{4}\cdot2\cdot\left|2x+5\right|+\dfrac{7}{3}\cdot4\cdot\left|2x+5\right|=\dfrac{1}{6}\)
\(\Leftrightarrow\left|2x+5\right|=\dfrac{1}{44}\)
=>2x+5=1/44 hoặc 2x+1=-1/44
=>x=-219/88 hoặc x=-221/88
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tìm x biết: \(3^{|x-1|+1}-18x+2x\times3^{|x-1|}-27=0\)
Tìm x
a, \(9x^2-49=0\) b, \(\left(x+3\right)\left(x^2-3x+9\right)-x\left(x-1\right)-27=0\)
c, (x-1)(x+2)-x-2=0 d, \(x\left(3x+2\right)+\left(x+1\right)^2-\left(2x-5\right)\left(2x+5\right)=0\)
e, (4x+1)(x-2)-(2x-3)(2x+1)=7
Tìm x biết:
\(a.\left(x+1\right)\left(x^2-x+1\right)-x\left(x^2-5\right)=71\)
\(b.\left(2x-3\right)^3-8x\left(x-1\right)^2+4x\left(4x+1\right)+27=0\)
Giải bpt sau
a, left(x+3right)^2-left(x-3right)^2le3left(x+1
right)
b, 2left(x+3right).left(x+4right)left(x-2right)^2+left(x-1right)^2
c, 5x^2-18x+19-left(2x-3right)^20
d, dfrac{left(3x-2right)^2}{4}-dfrac{3left(x-2right)}{8}-1dfrac{-15xleft(5-3xright)}{2}
e, 2x^2+2x+2-dfrac{15left(x-1right)}{2}-12xleft(x-2,75right)
g, dfrac{5x^2-3}{5}+dfrac{3x-1}{4} dfrac{xleft(2x+3right)}{2}-5
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Giải bpt sau
a, \(\left(x+3\right)^2-\left(x-3\right)^2\le3\left(x+1
\right)\)
b, \(2\left(x+3\right).\left(x+4\right)>\left(x-2\right)^2+\left(x-1\right)^2\)
c, \(5x^2-18x+19-\left(2x-3\right)^2>0\)
d, \(\dfrac{\left(3x-2\right)^2}{4}-\dfrac{3\left(x-2\right)}{8}-1>\dfrac{-15x\left(5-3x\right)}{2}\)
e, \(2x^2+2x+2-\dfrac{15\left(x-1\right)}{2}-1>2x\left(x-2,75\right)\)
g, \(\dfrac{5x^2-3}{5}+\dfrac{3x-1}{4}< \dfrac{x\left(2x+3\right)}{2}-5\)
mọi người giúp nhé cần gấp
\(\left(x-7\right)^{x+1}-\left(x-7\right)^{x+11}=0\)
\(\frac{2}{3}\times3^{x+1}-7\times3^x=-405\)
\(\frac{3}{1-2x}=\frac{-5}{3x-2}\)
\(\left(x-3\right)^{4^{ }}=\frac{16}{81}\)
Tìm x bt1) 3.left(2x-1right).left(3x-1right)-left(2x-3right).left(9x-1right)-3-3-32) 3x-1.left(2x+7right)-x+1.left(6x-5right)x+2-left(x-5right)3) 3xy.left(x+yright)-left(x+yright).left(x^2+y^2+2xyright)+y^3274) 5.x+1.left(1-xright).left(2x^2+3right)0giúp mk vs mai mk đi hk rùi
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Tìm x bt
1) \(3.\left(2x-1\right).\left(3x-1\right)-\left(2x-3\right).\left(9x-1\right)-3=-3\)\(-3\)
2) \(3x-1.\left(2x+7\right)-x+1.\left(6x-5\right)=x+2-\left(x-5\right)\)
3) \(3xy.\left(x+y\right)-\left(x+y\right).\left(x^2+y^2+2xy\right)+y^3=27\)
4) \(5.x+1.\left(1-x\right).\left(2x^2+3\right)=0\)
giúp mk vs mai mk đi hk rùi
1.Tìm x:
left(x-1right)^3+left(2x+1right)^3+left(x+2right)^33left(x-1right).left(2x+1right).left(x+2right)
2. Cho a+b+c0 . C/m: a^3+b^3+c^33abc
3. Tìm x:
a, left(x+1right)^3+left(2x-3right)^3+left(2-3xright)^30
b, left(2x+1right)^3+left(x+2right)^327left(x+1right)^3
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1.Tìm x:
\(\left(x-1\right)^3+\left(2x+1\right)^3+\left(x+2\right)^3=3\left(x-1\right).\left(2x+1\right).\left(x+2\right)\)
2. Cho \(a+b+c=0\) . C/m: \(a^3+b^3+c^3=3abc\)
3. Tìm x:
a, \(\left(x+1\right)^3+\left(2x-3\right)^3+\left(2-3x\right)^3=0\)
b, \(\left(2x+1\right)^3+\left(x+2\right)^3=27\left(x+1\right)^3\)
2. \(a+b+c=0\)
\(\Leftrightarrow\)\(\left(a+b+c\right)^3=0\)
\(\Leftrightarrow a^3+b^3+c^3+3a^2b+3ab^2+3a^{2c}+3ac^2+3b^2c+3bc^2+6abc\)
\(\Leftrightarrow a^3+b^3+c^3+\left(3a^2b+3ab^2+3abc\right)+\left(3a^2c+3ac^2+3abc\right)+\left(3b^2c+3bc^2+3abc\right)-3abc\)
\(\Leftrightarrow a^3+b^3+c^3+3ab\left(a+b+c\right)+3ac\left(a+c+b\right)+3bc\left(b+c+a\right)-3abc\)
Ta có: \(a+b+c=0\)
\(a^3+b^3+c^3+3ab.0+3ac.0+3bc.0=3abc\)
\(\Leftrightarrow a^3+b^3+c^3=3abc\)
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Bài 2
\(a+b+c=0\Rightarrow a=-b-c\)
\(VT=a^3+b^3+c^3=\left(-b-c\right)^3+b^3+c^3\)
\(=\left(-b\right)^3-3\left(-b\right)^2c+3\left(-b\right)c^2-c^3+b^3+c^3\)
\(=\left(-b\right)^3-3b^2c-3bc^2-c^3+b^3+c^3\)
\(=-3b^2c-3bc^2=3bc\left(-b-c\right)=3abc=VP\)
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bài 2
ta có a+b+c=0
=>a+b=-c
=>c=-(a+b)
thay -(a+b)=c vào 2 vế ta đc
a3+b3-(a+b)3=3ab[-a-b)]
=>a3+b3-(a3+3a2b+3ab2+b3)=-3a2b-3ab2
=>a3+b3-a3-3a2b-3ab2-b2=-3ab(a-b)
=>(a3-a3)+(b3-b3)+(-3a2b-3ab2)=-3ab(a-b)
=>0+0-3ab(a-b)=-3ab(a-b)(đpcm)
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BÀI 6 tìm x1,2xleft(x-5right)-left(3x+2x^2right)0 2,xleft(5-2xright)+2xleft(x-1right)133,2x^3left(2x-3right)-x^2left(4x^2-6x+2right)0 4,5xleft(x-1right)-left(x+2right)left(5x-7right)65,6x^2-left(2x-3right)left(3x+2right)1 6,2xleft(1-xright)+59-2x^2
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BÀI 6 tìm x
1,\(2x\left(x-5\right)-\left(3x+2x^2\right)=0\) 2,\(x\left(5-2x\right)+2x\left(x-1\right)=13\)
3,\(2x^3\left(2x-3\right)-x^2\left(4x^2-6x+2\right)=0\) 4,\(5x\left(x-1\right)-\left(x+2\right)\left(5x-7\right)=6\)
5,\(6x^2-\left(2x-3\right)\left(3x+2\right)=1\) 6,\(2x\left(1-x\right)+5=9-2x^2\)
1: \(\Leftrightarrow2x^2-10x-3x-2x^2=0\)
=>-13x=0
=>x=0
2: \(\Leftrightarrow5x-2x^2+2x^2-2x=13\)
=>3x=13
=>x=13/3
3: \(\Leftrightarrow4x^4-6x^3-4x^3+6x^3-2x^2=0\)
=>-2x^2=0
=>x=0
4: \(\Leftrightarrow5x^2-5x-5x^2+7x-10x+14=6\)
=>-8x=6-14=-8
=>x=1
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`1)2x(x-5)-(3x+2x^2)=0`
`<=>2x^2-10x-3x-2x^2=0`
`<=>-13x=0`
`<=>x=0`
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`2)x(5-2x)+2x(x-1)=13`
`<=>5x-2x^2+2x^2-2x=13`
`<=>3x=13<=>x=13/3`
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`3)2x^3(2x-3)-x^2(4x^2-6x+2)=0`
`<=>4x^4-6x^3-4x^4+6x^3-2x^2=0`
`<=>x=0`
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`4)5x(x-1)-(x+2)(5x-7)=0`
`<=>5x^2-5x-5x^2+7x-10x+14=0`
`<=>-8x=-14`
`<=>x=7/4`
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`5)6x^2-(2x-3)(3x+2)=1`
`<=>6x^2-6x^2-4x+9x+6=1`
`<=>5x=-5<=>x=-1`
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`6)2x(1-x)+5=9-2x^2`
`<=>2x-2x^2+5=9-2x^2`
`<=>2x=4<=>x=2`
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