Giai phuong trinh :
(3x-1) . (x2+2) = (3x-1) . (7x-10)
Cac bn giup minh vs nha . Thanks nhieu
giup minh bai nay:
giai phuong trinh:
x(x+1)(x-1)(x+2)=24
2x(8x-1)^2(3x+2)(2x+1)=3
thanks!
a) [x(x+1].[(x-1)(x+2)]=24
(x2+x)(x2+x+2)=24
Dat x2+x=a , ta dc: a(a+2)=24
=> a2+2a-24=0
=> (a-4)(a+6)=0
=> a=4 hoac a=-6
Thay vao roi tu tim x nha
b)
giai phuong trinh (x-1)^2016+(x-2)^2016=1
cac ban lam giup bai nay cho minh vs. minh dang can gap. thank you nhiu
cam on ban nha. ban hoc truong nao vay?
giai cac phuong trinh va bat phuong trinh sau:
2(x-1)-5=3(5-3x)
2( x - 1 ) - 5 = 3( 5 - 3x)
2x - 2 - 5 = 15 - 9x
2x - 7 = 15 - 9x
2x + 9x = 15 + 7
11x = 22
x = 2
Vậy x = 2
\(2\left(x-1\right)-5=3\left(5-3x\right)\)
\(\Leftrightarrow2x-2-5=15-9x\)
\(\Leftrightarrow2x-\left(2+5\right)=15-9x\)
\(\Leftrightarrow2x-7=15-9x\)
\(\Leftrightarrow2x+9x=15+7\)
\(\Leftrightarrow11x=22\)
\(\Leftrightarrow x=22\div11\)
\(\Leftrightarrow x=2\)
\(\text{Vậy }x=2\)
2( x - 1 ) - 5 = 3( 5 - 3x)
2x - 2 - 5 = 15 - 9x
2x - 7 = 15 - 9x
2x + 9x = 15 + 7
11x = 22
x = 2
Giai giup minh cac phuong trinh nay voi a !!!! hepl pls
a) P = \(\left\{x\in R|x^4-3x^3-6x^2+3x+1=0\right\}\)
b) Q=\(\left\{x\in R|\text{x^4 + 6x^3 + 6x^2 -6x +1 = 0 }\right\}\)
Giup em voi a
Giai cac bat phuong trinh sau va bieu dien tap nghiem cua bat phuong trinh tren truc so:
a. 2(3x-1)-2x<2x-1
b. 4x-8≥3(3x-2)+4-2x
c. 3(x-2)(x+2)<3x²+x
d. (x+4)(5x-1)>5x²+16x+2
a: =>6x-2-2x<2x-1
=>4x-2<2x-1
=>2x-1<0
=>x<1/2
b: =>4x-8>=9x-6+4-2x
=>4x-8>=7x-2
=>-3x>=6
=>x<=-2
c: =>3x^2-12<3x^2+x
=>x>-12
d: =>5x^2-x+20x-4>5x^2+16x+2
=>19x-4>16x+2
=>3x>6
=>x>2
Giai phuong trinh giup minh voi:
\(\frac{\left(3x+1\right)\left(3x-2\right)}{3}+5\left(3x-1\right)=\frac{2\left(2x+1\right)\left(3x+1\right)}{3}+2x\left(3x+1\right)\)
\(\left|3x-2\right|>7\)
giai bat phuong trinh
ai giup tui vs
TH1: 3x-2>7. ĐK:\(x\ge\frac{2}{3}\)
<=>x>3(thỏa)
TH2: 3x-2<7. Đk: x<2/3
<=>x<3. kh đk => x<2/3
kl:...
giai cac phuong trinh sau
a, (3x-1)(4x-8)=0
b,(x-2)(1-3x)=0
c,(x-3)(x+4)-(x-3)(2x-1)=0
d,(x+1)(x+2)=2x(x+2)
a)(3x-1)(4x-8)=0
⇔3x-1=0 hoặc 4x-8=0
1.3x-1=0⇔3x=1⇔x=1/3
2.4x-8=0⇔4x=8⇔x=2
phương trình có 2 nghiệm:x=1/3 và x=2
b)(x-2)(1-3x)=0
⇔x-2=0 hoặc 1-3x=0
1.x-2=0⇔x=2
2.1-3x=0⇔-3x=1⇔x=-1/3
phương trình có 2 nghiệm:x=2 và x=-1/3
c)(x-3)(x+4)-(x-3)(2x-1)=0
⇔(x+4)(2x-1)=0
⇔x+4=0 hoặc 2x-1=0
1.x+4=0⇔x=-4
2.2x-1=0⇔2x=1⇔x=1/2
phương trình có hai nghiệm:x=-4 và x=1/2
d)(x+1)(x+2)=2x(x+2)
⇔(x+1)(x+2)-2x(x+2)=0
⇔2x(x+1)=0
⇔2x=0 hoặc x+1=0
1.2x=0⇔x=0
2.x+1=0⇔x=-1
phương trình có 2 nghiệm:x=0 và x=-1
giari cac phuong trinh tich
3x2-7x +8 =0
3x2+7x+2=0
4x2- 12x +9 =0
x2 -10x-2000
jup mk nha
\(b,3x^2+7x+2=0\\ \Leftrightarrow3x^2+x+6x+2=0\\ \Leftrightarrow x\left(3x+1\right)+2\left(3x+1\right)=0\\ \Leftrightarrow\left(3x+1\right)\left(x+2\right)=0\\ \Leftrightarrow\left\{{}\begin{matrix}3x+1=0\\x+2=0\end{matrix}\right.\\ \Leftrightarrow\left\{{}\begin{matrix}x=-\dfrac{1}{3}\\x=-2\end{matrix}\right.\)
\(c,4x^2-12x+9=0\\ \Leftrightarrow\left(2x-3\right)^2\Leftrightarrow2x-3=0\\ \Leftrightarrow x=\dfrac{3}{2}\)
\(d,x^2-10x-2000=0\\ \Leftrightarrow\left(x-50\right)\left(x+40\right)=0\\ \Leftrightarrow\left\{{}\begin{matrix}x-50=0\\x+40=0\end{matrix}\right.\\ \Leftrightarrow\left\{{}\begin{matrix}x=50\\x=-40\end{matrix}\right.\)
ý a, hình như sai đề bn kiểm tra lại ik nha!