1>
a) (x^3 - 8) : (x^2 + 2x + 4)
b) (3x^2 - 6x) : (2 - x)
c)10x(x - y) - 6y(y - x)
phân tích đa thức thành nhân tử
\(a)3x^3+6x^2y \)
\(b)2x^3-6x^2\)
\(c)18x^2-20xy\)
\(d)xy+y^2-x-y \)
\(e)(x^2y^2-8)^2-1\)
\(f)x^2-7x-8\)
\(g)10x^2(2x-y)+6xy(y-2x)\)
\(h)x^2-2x+1-y^2\)
\(i)2x(x+2)+x^2(-x-2)\)
\(k)-9+6x-x^2\)
\(l)8xy-2x^2-8y^2\)
\(m)3x^2+5x-3y^2-5y\)
a) 3x³ + 6x²y
= 3x².(x + 2y)
b) 2x³ - 6x²
= 2x².(x - 2)
c) 18x² - 20xy
= 2x.(9x - 10y)
d) xy + y² - x - y
= (xy + y²) - (x + y)
= y(x + y) - (x + y)
= (x + y)(y - 1)
e) (x²y² - 8)² - 1
= (x²y² - 8 - 1)(x²y² - 8 + 1)
= (x²y² - 9)(x²y² - 7)
= (xy - 3)(xy + 3)(x²y² - 7)
f) x² - 7x - 8
= x² - 8x + x - 8
= (x² - 8x) + (x - 8)
= x(x - 8) + (x - 8)
= (x - 8)(x + 1)
a: \(3x^3+6x^2y\)
\(=3x^2\cdot x+3x^2\cdot2y=3x^2\left(x+2y\right)\)
b: \(2x^3-6x^2=2x^2\cdot x-2x^2\cdot3=2x^2\left(x-3\right)\)
c: \(18x^2-20xy=2x\cdot9x-2x\cdot10y=2x\left(9x-10y\right)\)
d: \(xy+y^2-x-y\)
\(=y\left(x+y\right)-\left(x+y\right)\)
\(=\left(x+y\right)\left(y-1\right)\)
e: \(\left(x^2y^2-8\right)^2-1\)
\(=\left(x^2y^2-8-1\right)\left(x^2y^2-8+1\right)\)
\(=\left(x^2y^2-7\right)\left(x^2y^2-9\right)\)
\(=\left(x^2y^2-7\right)\left(xy-3\right)\left(xy+3\right)\)
f: \(x^2-7x-8\)
\(=x^2-8x+x-8\)
\(=x\left(x-8\right)+\left(x-8\right)=\left(x-8\right)\left(x+1\right)\)
g: \(10x^2\left(2x-y\right)+6xy\left(y-2x\right)\)
\(=2x\cdot\left(2x-y\right)\cdot5x-2x\cdot\left(2x-y\right)\cdot3y\)
\(=2x\left(2x-y\right)\left(5x-3y\right)\)
h: \(x^2-2x+1-y^2\)
\(=\left(x-1\right)^2-y^2\)
\(=\left(x-1-y\right)\left(x-1+y\right)\)
i: \(2x\left(x+2\right)+x^2\left(-x-2\right)\)
\(=2x\left(x+2\right)-x^2\left(x+2\right)\)
\(=\left(x+2\right)\left(2x-x^2\right)=x\cdot\left(x+2\right)\left(2-x\right)\)
k: \(-x^2+6x-9=-\left(x^2-6x+9\right)\)
\(=-\left(x^2-2\cdot x\cdot3+3^2\right)=-\left(x-3\right)^2\)
l: \(-2x^2+8xy-8y^2\)
\(=-2\left(x^2-4xy+4y^2\right)\)
\(=-2\left(x-2y\right)^2\)
m: \(3x^2+5x-3y^2-5y\)
\(=3\left(x^2-y^2\right)+5\left(x-y\right)\)
\(=3\left(x-y\right)\left(x+y\right)+5\left(x-y\right)\)
\(=\left(x-y\right)\left(3x+3y+5\right)\)
g) 10x²(2x - y) + 6xy(y - 2x)
= 10x²(2x - y) - 6xy(2x - y)
= 2x(2x - y)(5x - 3y)
h) x² - 2x + 1 - y²
= (x² - 2x + 1) - y²
= (x - 1)² - y²
= (x - y - 1)(x + y - 1)
i) 2x(x + 2) + x² (-x - 2)
= 2x(x + 2) - x²(x + 2)
= x(x + 2)(2 - x)
k) -9 + 6x - x²
= -(x² - 6x + 9)
= -(x - 3)²
l) 8xy - 2x² - 8y²
= -2(x² - 4xy + 4y²)
= -2(x - 2y)²
m) 3x² + 5x - 3y² - 5y
= (3x² - 3y²) + (5x - 5y)
= 3(x² - y²) + 5(x - y)
= 3(x - y)(x + y) + 5(x - y)
= (x - y)[3(x + y) + 5]
= (x - y)(3x + 3y + 5)
Làm phép chia:
a) (6x^3-7x^2-x+2):(2x+1)
b) (2x^4-10x^3-x^2+15x-3):(2x^2-3)
c) (x^2-y^2+6y-9):(x-y+3)
1. Điền biểu thức thích hợp vào dấu... để có hằng đẳng thức đúng
(+2)^2=x^2+...+4
(2x-...)^3=-12x^2+6x-1
2. Phân tích đa thức thành nhân tử
x^3-6x^2+9x x^2-8x+7
x^2-2xy+3x-6y
3. Làm tính chia
(2x^4-3x^3+3x^2-3x+1):(x^2+1)
4. CM -y^2+2y-4 < hoặc bằng với mọi số thực y
5. a) Thực hiện phép nhân, rút gọn, tính giá trị biểu thức
A=x(x^3+y )-x^2(x^2-y) -x^2(y-1) tại x=-10, y=5
b) Tìm x biết 5x^3-3x^2+10x-6=0
c) Tìm x ,y biết
x^2+y^2-2x+4y+5=0
6. Phân tích đa thức thành nhân tử
xy-3x+2y-6
x^2y+4Xy+4y-y^2
x^2+y^2+xz+yz+2xy
x^3+3x^2-3x-1
7. Thực hiện các phép chia
(13xy^2+17xy^3-18y^2):6y^2
(2x^2-9x^2+10x-3):(x-3)
8. Biết a+b+c=0. CM a^3+b^3+c^3=3abc
Bài 2:
a: \(=x\left(x^2-6x+9\right)=x\left(x-3\right)^2\)
b: \(=\left(x-1\right)\left(x-7\right)\)
c: \(=x\left(x-2y\right)+3\left(x-2y\right)=\left(x-2y\right)\left(x+3\right)\)
làm phép chia :
a) (x^4 -2x^3 + 2x -1) : (x^2 - 1)
b) (x^3 -8) : (x^2 + 2x +4)
c) (x^6 - 2x^5 + 2x^4 + 6x^3 - 4x^2)n: 6x^2
d) (-2x^5 + 3x^2 - 4x^3) :2x^2
e) (15x^3 - 10x^2 + x - 2) : (x - 2)
f) (2x^4 - 3x^3 - 3x^2 + 6x - 2) : (x^2 - 2)
b: =x-2
d: \(=-x^3+\dfrac{3}{2}-2x\)
giúp mình với ạ
Bài 1: Tìm giá trị nhỏ nhất A= (x² +5x)² + 10x² +50x +124
B= (x +2)(x+3)(X-7)(x-8) – 2021
C= \(x^4\) +6x³ +7x² +6x +11
D= 2x² +20 +10y² +2xy – 6x +6y +123
F= (x+3)²(3x+8)(3x+10) -201
К- (2х-1)(х-1)х-3)(2x+3) + 19
Bài 1: Phân tích đa thức thành nhân tử:
a) x(x+y)-6x-6y
b)x^3-x-y62-y
c)2x^3+16
d)x^4+2x^3+x^2
e)5x^2-10xy+5y^2-20z^2
f)16-x^2+2xy-y^2
G)3x^2y-6x^2y+3y
Bài 2: tìm x:
a)x^2-10x=-25
b) x^2(x-2)+x-2=0
c) (x-2)^2=(3x-5)^2
Bài 1 :
a,\(x\left(x+y\right)-6x-6y=x\left(x+y\right)-6\left(x+y\right)=\left(x+y\right)\left(x-6\right)\)
b, \(x^3-x-y^2-y??????????\)
c, \(2x^3+16=2\left(x^3+8\right)=2\left(x+3\right)\left(x^2-3x+9\right)\)
d, \(x^4+2x^3+x^2=x^2\left(x^2+2x+1\right)=x^2\left(x+1\right)^2\)
e, \(5x^2-10xy+5y^2-20z^2=5[\left(x-y\right)^2-\left(2z\right)^2]\)
\(=5\left(x-y-2z\right)\left(x-y+2z\right)\)
f, \(16-x^2+2xy-y^2=16-\left(x-y\right)^2=\left(4-x+y\right)\left(4+x-y\right)\)
g, Tương tự e
Bài 2 :
a,\(x^2-10x=-25< =>\left(x-5\right)^2=0< =>x=5\)
b,\(x^2\left(x-2\right)+x-2=0\)
\(\Leftrightarrow\left(x-2\right)\left(x^2+1\right)=0\)
\(x^2+1>0< =>x-2=0< =>x=2\)
c, \(\left(x-2\right)^2=\left(3x-5\right)^2\)
\(< =>\left[{}\begin{matrix}x-2=3x-5\\x-2=5x-3\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=1,5\\x=0,25\end{matrix}\right.\)
Tính giá trị biểu thức :
a) A = x^3+6x^2y+12xy^2+8y^3 biết x+2y=-5
b) B = 27y^3-27y^2x+9yx^2-x^3 biết y=1/3x
c) C = 26x^2+y.(2x+y)-10x.(x+y) biết x=0,25y
d) D = 50y^2+x.(x-2y)+14y.(x-y) biết x+6y=9
*** Mong mọi người làm hết đầy đủ giúp mình nha ***
b)B=27y^3-27y^2x+9yx^2-x^3
= 27 . (1/3x)^3 - 27.(1/3x)².x + 9.1/3.x.x^2 - x^3
= x^3 - 3x^3 + 3x^3 - x^3
= 0
d) D=50y^2+x(x-2y)+14y(x-y)
=50y^2 +x^2 -2xy +14xy -14y^2
=36y^2 +x^2 +12xy
=(6y + x)^2
=81
10 Phân tích các đa thức sau thành nhân tử:
a) 5xy(x-y)-2x+2y ; b) 6x-2y-x(y-3x)
c) x^2+4x-xy-4y ; d) 3xy+2z-6y-xz
11 Tìm x, biết: a) 4-9x^2=0 ; b) x^2+x+1/4=0 ; c) 2x(x-3)+(x-3)=0
d) 3x(x-4)-x+4=0 ; e) x^3-1/9x=0 ; f) (3x-y)^2-(x-y)^2=0
a) 5xy ( x - y ) - 2x + 2y
= 5xy ( x - y ) - 2 ( x - y )
= ( x - y ) ( 5xy - 2 )
b) 6x-2y-x(y-3x)
= 2 ( y - 3x ) - x ( y - 3x )
= ( y - 3x ( ( 2 - x )
c) x2 + 4x - xy-4y
= x ( x + 4 ) - y ( x + 4 )
( x + 4 ) ( x - y )
d) 3xy + 2z - 6y - xz
= ( 3xy - 6y ) + ( 2z - xz )
= 3y ( x - 2 ) + z ( x - 2 )
= ( x - 2 ) ( 3y + z )
a,5xy(x-y)-2x+2y=5xy(x-y)-2(x-y)=(x-y)(5xy-2)
b,6x-2y-x(y-3x)=-2(y-3x)-x(y-3x)=(y-3x)(-2-x)
c,x^2+4x-xy-4y=x(x+4)-y(x+4)=(x+4)(x-y)
d,3xy+2z-6y-xz=(3xy-6y)+(2z-xz)=3y(x-2)+z(2-x)=3y(x-2)-z(x-2)=(x-2)(3y-z)
11)
a,4-9x^2=0
(2-3x)(2+3x)=0
2-3x=0=>x=2/3 hoặc 2+3x=0=>x=-2/3
b,x^2 +x+1/4=0
(x+1/2)^2 =0
x+1/2=0
x=-1/2
c,2x(x-3)+(x-3)=0
(x-3)(2x+1)=0
x-3=0=>x=3 hoặc 2x+1=0=>x=-1/2
d,3x(x-4)-x+4=0
3x(x-4)-(x-4)=0
(x-4)(3x-1)=0
x-4=0=>x=4 hoặc 3x-1=0=>x=1/3
e,x^3-1/9x=0
x(x^2-1/9)=0
x(x+1/3)(x-1/3)=0
x=0 hoặc x+1/3=0=>x=-1/3 hoặc x-1/3=0=>x=1/3
f,(3x-y)^2-(x-y)^2 =0
(3x-y-x+y)(3x-y+x-y)=0
2x(4x-2y)=0
4x(2x-y)=0
x=0hoặc 2x-y=0=>x=y/2