1 My sister has learned English for 5 years

2 A supermarket was built near the airport last year

3 I spent three hours cleaning the house yesterday

6 The wall built three weeks ago fell down

7 Unless you leave me alone, I will call the police

8 The suspects are being followed by the police 

10 Nobody in this team is as good at playing football as Tom

khôn zị ai chơi lại-.-''

Thật là ít

Dài chia nhỏ ra mà hỏi may ra còn trl:v

\(14.B\\ 15.C\\ 16.C\\ 17.\text{Không có đáp án đúng}\\ 18.B\\ 19.D\\ 20.C\)

14. B

15.C 

16.C

17. Câu này em xem lại đáp án giúp anh nhé CO2 

18.B

19.D

20.C

c: Ta có: AM//BC

AE⊥BC

Do đó:AM⊥AE

Suy ra: \(\widehat{AME}+\widehat{AEM}=90^0\)

hay \(\widehat{AME}+\widehat{BAD}=90^0\)

`a)P(x)+Q(x)=x^5-2x^2+1`

`=>Q(x)=x^5-2x^2+1-P(x)`

`=>Q(x)=x^5-2x^2+1-x^4+3x^2-1/2+x`

`=>Q(x)=x^5-x^4+x^2+x+1/2`

______________________________________________

`b)P(x)-R(x)=x^3`

`=>R(x)=P(x)-x^3`

`=>R(x)=x^4-3x^2+1/2-x-x^3`

`=>R(x)=x^4-x^3-3x^2-x+1/2`

Ta có:

\(P\left(x\right)+Q\left(x\right)=x^5-2x^2+1\)

\(\Rightarrow Q\left(x\right)=P\left(x\right)-\left(x^5-2x^2+1\right)\)

\(=x^4-3x^2+\dfrac{1}{2}-x-x^5+2x^2-1\)

\(=-x^5+x^4-x^2-x-\dfrac{1}{2}\)

Vậy \(Q\left(x\right)=-5^2+x^4-x^2-x-\dfrac{1}{2}\)

a) <=> Q(x) = (x⁵ - 2x² + 1) - P(x)

= (x⁵ - 2x² + 1) - (x⁴ - 3x² + 1/2 - x)

= x⁵ - 2x² + 1 - x⁴ + 3x² + x - 1/2

= x⁵ - x⁴ + x² + x + 1/2

Vậy Q(x) = x⁵ - x⁴ + x² + x + 1/2