\(\left(2^3\cdot9^4+9^3\cdot45\right):\left(9^2\cdot10-9^2\right)\)

\(=\left(2^3\cdot3^8+3^6\cdot5\cdot3^2\right):\left[9^2\cdot\left(10-1\right)\right]\)

\(=\left(2^3\cdot3^8+3^8\cdot5\right):\left(9^2\cdot9\right)\)

\(=\left[3^8\cdot\left(2^3+5\right)\right]:9^3\)

\(=3^8\cdot13:3^6\)

\(=3^2\cdot13\)

\(=117\)

\(\left(2^3.9^4+9^3.45\right):\left(9^2.10-9^2\right)\)

\(=\left(2^3.3^8+3^6.3^2.5\right):\left(3^4.10-3^4\right)\)

\(=\left(2^3.3^8+3^8.5\right):\left(3^4.\left(10-1\right)\right)\)

\(=3^8\left(2^3+5\right):3^4.9=3^8\left(2^3+5\right):3^6\)

\(=3^2.13=9.13=117\)

`(64×15×9)/(72×45×6) `

`=(8xx8×3xx5×9)/(8xx9×5xx9×2xx3) `

`=8/(9×2) `

`= 4/9`

11/9 + 18/5 -2/9 -3/5

= 11/9  - 2/ 9  + 18/5 - 3/5

= 9/9 + 15/5

= 1+ 3

= 4

=11/9-2/9+18/5-3/5=9/9+15/5

                               =1+3=4

11/9 + 18/5 -2/9 -3/5

= 11/9  - 2/ 9  + 18/5 - 3/5

= 9/9 + 15/5

= 1+ 3

= 4

= ( 0,25 x 4 ) x ( 1,25 x 8 )

= 1 x 10

= 10

10

chỉnh sửa a 18.17-3.6.7

a) 18.17-36.7

= 18.17-18.2.7

=18.(17-14)

=18.3

=54

b) 54-6.(17+9)

=54-6.26

=6.9-6.26

=6.(9-26)

=6.(-17)

=-102

a) 18. 17 - 3.6.7

  = 18 .17 - 18 .7

  = 18.(17- 7)

  = 18. 10

  = 180

=7/11+5/6+4/11-1/6

=(7/11+4/11)+(5/6-1/6)

=1+2/3

=5/3

\(A,\dfrac{7}{11}+\dfrac{5}{6}-\dfrac{-4}{11}-\dfrac{1}{6}\)

\(= (\dfrac{7}{11}+\dfrac{-4}{11})-(\dfrac{5}{6}-\dfrac{1}{6})\)

\(=\dfrac{3}{11}-\dfrac{2}{3}\)

\(= \dfrac{9}{33}-\dfrac{22}{33}\)

\(= \dfrac{-13}{33}\)

\(B,\dfrac{5}{9}.\dfrac{7}{3}+\dfrac{5}{9}.\dfrac{9}{13}-\dfrac{5}{9}:\dfrac{13}{5}\)

\(=(\dfrac{5}{9}.\dfrac{5}{9}:\dfrac{5}{9}).\dfrac{7}{3}+\dfrac{9}{13}-\dfrac{13}{5}\)

\(=(\dfrac{5}{9}.\dfrac{7}{3})+(\dfrac{9}{13}-\dfrac{13}{5})\)

\(=(\dfrac{5}{9}.\dfrac{21}{9})+(\dfrac{45}{65}-\dfrac{169}{65})\)

\(=\dfrac{35}{27}+\dfrac{-124}{65}\)

\(=\dfrac{2275}{1755}+\dfrac{-3348}{1755}\)

\(=\dfrac{-1073}{1755}\)

1+5+3+9+5+7=30

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