\(\dfrac{4^2.25^2+32.125}{2^3.5^2}=\dfrac{2^4.5^4+2^5.5^3}{2^3.5^2}=\dfrac{2^3.5^2\left(2.5^2+2^2.5\right)}{2^3.5^2}=2.5^2+2^2.5=50+20=70\)

\(\dfrac{4^2.25^2+32.125}{2^3.5^2}\)

\(=\dfrac{\left(2^2\right)^2.\left(5^2\right)^2+2^5.5^3}{2^3.5^2}\)

\(=\dfrac{2^4.5^4+2^5.5^3}{2^3.5^2}\)

\(=\dfrac{2^3.5^2\left(2.5^2+2^2.5\right)}{2^3.5^2}\)

\(=2.5^2+2^2.5\)

\(=2.25+4.5=50+20=70\)

=\(\dfrac{\left(2^2\right)^2.\left(5^2\right)^2+2^5.5^2}{2^3.5^2}\)

=\(\dfrac{2^4.5^4+2^5.5^2}{2^3.5^2}\)

=\(\dfrac{2^3.\left(2.5^4+2^2.5^2\right)}{2^3.5^2}\)

=\(\dfrac{5^2.\left(2.5^2+2^2\right)}{5^2}\)

=\(2.5^2+2^2=54\)

\(\dfrac{4^2.25^2+32.125}{2^3.5^2}=\dfrac{2^4.5^4+2^5.5^3}{2^3.5^2}=\dfrac{2^4.5^3\left(5+2\right)}{2^3.5^2}=2.5\left(5+2\right)=10.7=70\)

a: \(\left(0.5\right)^3\cdot2^3=1\)

b: \(\left(0.25\right)^2\cdot16=1\)

c: \(\left(\dfrac{3}{5}\right)^3:\left(-\dfrac{27}{1000}\right)=\dfrac{3^3}{5^3}\cdot\dfrac{-1000}{27}=\dfrac{-1000}{125}=-8\)

\(A=\dfrac{4^2.25^2+32.125}{2^3.5^2}\)

\(A=\dfrac{\left(2^2\right)^2.\left(5^2\right)^2+2^5.5^3}{2^3.5^2}\)

\(A=\dfrac{2^4.5^4+2^5.5^3}{2^3.5^2}\)

\(A=\dfrac{2^4.2^5+5^4.5^3}{2^3.5^2}\)

\(A=\dfrac{2^{4+5}+5^{4+3}}{2^3.5^2}\)

\(A=\dfrac{2^9.5^7}{2^3.5^2}=2^6.5^5\)

Làm 

\(\frac{4^2.25^2+32.125}{2^3.5^2}=\frac{2^4.5^4+2^5.5^3}{2^3.5^2}=\frac{2^4.5^3\left(5+2\right)}{2^3.5^2}=2.5.7=70\)

\(A=\dfrac{4^2.25^2+32.125}{2^3.5^2}=\dfrac{2^4.5^4+2^5.5^3}{2^3.5^2}\)

\(=\dfrac{2^4.5^3\left(5+2\right)}{2^3.5^2}=10.7=70\)

\(B=\dfrac{4^6.9^5+6^4.120}{8^4.3^{12}-6^{11}}=\dfrac{2^{12}.3^{10}+2^4.3^4.2^3.3.5}{2^{12}.3^{12}-2^{11}.3^{11}}\)

\(=\dfrac{2^{12}.3^{10}+2^7.3^5.5}{2^{11}.3^{11}\left(2.3-1\right)}=\dfrac{2^7.3^5\left(2^5.3^5+5\right)}{2^{11}.3^{11}\left(2.3-1\right)}\)

\(=\dfrac{2^5.3^5+5}{2^4.3^6.5}=\dfrac{2}{3.5}+\dfrac{5}{2^4.3^6.5}=\dfrac{2}{15}+\dfrac{1}{11664}\)

\(=\dfrac{7781}{58320}\)

Chúc bạn học tốt!!!

Cạn lời Hiếu bđ

\(PHUCDZ=\dfrac{4^2.25^2+32.125}{2^3.5^2}\)

\(PHUCDZ=\dfrac{\left(2^2\right)^2.\left(5^2\right)^2+2^5.5^3}{2^3.5^2}\)

\(PHUCDZ=\dfrac{2^4.5^4+2^5.5^3}{2^3.5^2}\)

\(PHUCDZ=\dfrac{2^3.2.5^2.5^2+2^3.4.5^2.5}{2^3.5^2}\)

\(PHUCDZ=\dfrac{2^3.5^2\left(2.5^2+4.5\right)}{2^3.5^2}\)

\(PHUCDZ=2.5^2+4.5=70\)

\(PHUCMAXDZ=\dfrac{4^6.9^5+6^4.120}{8^4.3^{12}-6^{11}}\)

\(PHUCMAXDZ=\dfrac{\left(2^2\right)^6.\left(3^2\right)^5+\left(2.3\right)^4.2^2.3.5}{\left(2^3\right)^4.3^{12}-6^{11}}\)

\(PHUCMAXDZ=\dfrac{2^{12}.3^{10}+2^4.3^4.2^2.3.5}{2^{12}.3^{12}-6^{11}}\)

\(PHUCMAXDZ=\dfrac{2^{12}.3^{10}+2^6.3^5.5}{6^{12}-6^{11}}\)

\(PHUCMAXDZ=\dfrac{2^{12}.3^{10}+2^6.3^5.5}{6^{11}\left(6-1\right)}\)

\(PHUCMAXDZ=\dfrac{2^{12}.3^{10}+2^6.3^5.5}{6^{11}.5}\)

\(PHUCMAXDZ=\dfrac{2^2.2^{10}.3^{10}+2^5.3^5.3.5}{6^{11}.5}\)

\(PHUCMAXDZ=\dfrac{4.6^{10}+6^5.15}{6^{11}.5}\)

\(PHUCMAXDZ=\dfrac{6^5.6^4.4+6^5.15}{6^{11}.5}\)

\(PHUCMAXDZ=\dfrac{6^5.5184+6^5.15}{6^5.6^6.5}\)

\(PHUCMAXDZ=\dfrac{6^5\left(5184+15\right)}{6^5\left(6^6.5\right)}\)\(=\dfrac{5199}{233280}\)