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Câu hỏi của Tran Mai - Toán lớp 6 | Học trực tuyến

sửa đề: \(\dfrac{4}{20}+\dfrac{16}{42}+\dfrac{6}{15}-\dfrac{3}{5}+\dfrac{2}{21}-\dfrac{10}{21}+\dfrac{3}{20}+\dfrac{42}{46}+\dfrac{250}{186}-\dfrac{2121}{2323}-\dfrac{125125}{143143}\)

\(\dfrac{4}{20}+\dfrac{16}{42}+\dfrac{6}{15}-\dfrac{3}{5}+\dfrac{2}{21}-\dfrac{10}{21}+\dfrac{3}{20}+\dfrac{42}{46}+\dfrac{250}{186}-\dfrac{2121}{2323}+\dfrac{125125}{143143}\\ =\dfrac{1}{5}+\dfrac{8}{21}+\dfrac{2}{5}-\dfrac{3}{5}+\dfrac{2}{21}-\dfrac{10}{21}+\dfrac{3}{20}+\dfrac{21}{23}+\dfrac{250}{186}-\dfrac{21}{23}+\dfrac{250}{286}\)\(=\left(\dfrac{1}{5}+\dfrac{2}{5}-\dfrac{3}{5}\right)+\left(\dfrac{8}{21}+\dfrac{2}{21}-\dfrac{10}{21}\right)+\left(\dfrac{21}{23}-\dfrac{21}{23}\right)+\left(\dfrac{250}{186}-\dfrac{250}{186}\right)+\dfrac{3}{20}\\ =\dfrac{3}{20}\)

tính theo cách hợp lý

a) \(\dfrac{4}{20}+\dfrac{16}{42}+\dfrac{6}{15}+\dfrac{-3}{5}+\dfrac{2}{21}+\dfrac{-40}{21}+\dfrac{3}{20}\)

\(=\dfrac{1}{5}+\dfrac{8}{21}+\dfrac{2}{5}+\dfrac{-3}{5}+\dfrac{2}{21}+\dfrac{-40}{21}+\dfrac{3}{20}\)

\(=\left(\dfrac{1}{5}+\dfrac{-3}{5}+\dfrac{2}{5}\right)+\left(\dfrac{8}{21}+\dfrac{2}{21}+\dfrac{-10}{21}\right)+\dfrac{3}{20}\)

\(=0+0+\dfrac{3}{20}\)

\(=\dfrac{3}{20}\)

b) \(\dfrac{42}{46}+\dfrac{250}{186}+\dfrac{-2121}{2323}+\dfrac{-125125}{143143}\)

\(=\dfrac{21}{23}+\dfrac{125}{93}+\dfrac{-21}{23}+\dfrac{-125}{143}\)

\(=\left(\dfrac{21}{23}-\dfrac{-21}{23}\right)+\dfrac{125}{93}+\dfrac{-125}{143}\)

\(=0+\dfrac{125}{93}+\dfrac{-125}{143}\)

\(=\dfrac{125}{93}+\dfrac{-125}{143}\)

\(=\dfrac{17875}{13299}+\dfrac{-11625}{13299}\)

\(=\dfrac{6250}{13299}\)

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\(\frac{42}{46}+\frac{250}{186}+\left(\frac{-2121}{2323}\right)+\left(\frac{-125125}{143143}\right)\)

\(=\frac{21}{23}+\frac{125}{93}+\left(\frac{-21}{23}\right)+\left(\frac{-125}{143}\right)\)

Đến chỗ này bạn xem lại đề nhé 

THANKS BẠN

\(\frac{42}{46}+\frac{250}{186}+\left(-\frac{2121}{2323}\right)+\left(-\frac{125125}{143143}\right)\)

\(=\frac{21}{23}+\frac{125}{93}+\left(-\frac{21}{23}\right)+\left(-\frac{125}{143}\right)\)

\(=\left(\frac{21}{23}-\frac{21}{23}\right)+\frac{125}{93}+\left(-\frac{125}{143}\right)\)

\(=0+\frac{125}{93}+\left(-\frac{125}{143}\right)\)

\(=\frac{6250}{13299}\)

ai giup minh de   minh cho

giúp nhanh với 

\(\frac{42}{46}+\frac{250}{186}+\frac{-2121}{2323}+\frac{-125125}{143143}\Leftrightarrow\frac{21}{23}+\frac{125}{93}+\frac{-21}{23}+\frac{-125}{143}\)

\(\Rightarrow\left(\frac{21}{23}+\frac{-21}{23}\right)+\left(\frac{125}{93}+\frac{-125}{143}\right)=\frac{17000}{3999}\)

\(\frac{4}{46}+\frac{250}{186}+\frac{-2121}{2323}+\frac{-125125}{143143}=\frac{2}{23}+\frac{125}{93}-\frac{21}{23}-\frac{125}{143}\)

\(=-0,36\)

Nhơ nha bạn.Tích mình mình tích lại

a, 4/20+16/42+6/15+-3/5+2/2+-10/21=1/5+8/21+2/5+-3/5+2/2+-16/21=(1/5+2/5+-3/5)+(8/21=-16/21)+1=-2/21+1=-19/21                       b,42/46+250/186+-2121/2323+-125125/143143                                                                                                                                =21/23+125/93+-21/23+-125/143                                                                                                                                                   =(21/23+-21/23)+(-125/143+125/93)                                                                                                                                              =6250/13299                                                             

`Answer:`

\(\frac{4}{20}+\frac{16}{42}+\frac{6}{15}-\left(-\frac{3}{21}\right)+\left(-\frac{10}{21}\right)+\frac{3}{20}\)

\(=\left(\frac{4}{20}+\frac{3}{20}+\frac{6}{15}\right)+\left(\frac{8}{21}+\frac{3}{21}-\frac{10}{21}\right)\)

\(=\frac{3}{4}+\frac{1}{21}\)

\(=\frac{67}{84}\)

\(\frac{42}{46}+\frac{250}{186}+\left(-\frac{2121}{2323}\right)+\left(-\frac{125125}{143143}\right)\)

\(=\frac{21}{23}+\frac{125}{93}+\left(-\frac{21}{23}\right)+\left(-\frac{125}{43}\right)\)

\(=\left(\frac{21}{23}+-\frac{21}{23}\right)+\left(\frac{125}{93}+-\frac{125}{43}\right)\)

\(=\frac{6250}{13299}\)

Đề sai rồi bạn đề đúng đây :

\(\frac{42}{46}+\frac{250}{286}+\left(-\frac{2121}{2323}\right)+\left(-\frac{125125}{143143}\right)\)

\(=\frac{21}{23}+\frac{125}{143}+\left(-\frac{21}{23}\right)+\left(-\frac{125}{143}\right)\)

\(=\frac{21}{23}+\frac{125}{143}-\frac{21}{23}-\frac{125}{143}\)

\(=0\)

giờ mình biết lí do tại sao mình khồn làm được rồi