\(PTK_{Mg\left(OH\right)_2}=24+\left(16+1\right).2=58\left(đvC\right)\)

\(PTK_{Ca\left(H_2PO_4\right)_2}=40+\left(1.2+31+16.4\right).2=234\left(đvC\right)\)

\(PTK_{Ba_3\left(PO_4\right)_2}=137.3+\left(31+16.4\right).2=601\left(đvC\right)\)

\(PTK_{Al_2\left(SO_4\right)_3}=27.2+\left(32+16.4\right).3=342\left(đvC\right)\)

\(PTK_{Ca\left(HCO_3\right)_2}=40+\left(1+12+16.3\right).2=162\left(đvC\right)\)

\(PTK_{Fe\left(NO_3\right)_2}=56+\left(14+16.3\right).2=180\left(đvC\right)\)

\(PTK_{Mg\left(OH\right)_2}=24+\left(16+1\right)\cdot2=58\left(đvC\right)\\ PTK_{Ca\left(H_2PO_4\right)_2}=40+\left(2+31+16\cdot4\right)\cdot2=234\left(đvC\right)\\ PTK_{Ba_3\left(PO_4\right)_2}=137\cdot3+\left(31+16\cdot4\right)\cdot2=601\left(đvC\right)\\ PTK_{Al_2\left(SO_4\right)_3}=27\cdot2+\left(32+16\cdot4\right)\cdot3=342\left(đvC\right)\\ PTK_{Ca\left(HCO_3\right)_2}=40+\left(1+12+16\cdot3\right)\cdot2=162\left(đvC\right)\\ PTK_{Fe\left(NO_3\right)_2}=56+\left(14+16\cdot3\right)\cdot2=180\left(đvC\right)\)

1. \(Fe+H_2SO_4\rightarrow FeSO_4+H_2\)

2. \(Zn+H_2SO_4\rightarrow ZnSO_4+H_2\)

3. \(Mg+H_2SO_4\rightarrow MgSO_4+H_2\)

4. \(Al_2O_3+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+3H_2O\)

5. \(ZnO+2HNO_3\rightarrow Zn\left(NO_3\right)_2+H_2O\)

6. \(BaO+H_2SO_4\rightarrow BaSO_4+H_2O\)

7. \(Fe\left(OH\right)_3+3HCl\rightarrow FeCl_3+3H_2O\)

8. \(Al\left(OH\right)_3+3HNO_3\rightarrow Al\left(NO_3\right)_3+3H_2O\)

9. \(Ca\left(OH\right)_2+H_2SO_4\rightarrow CaSO_4+2H_2O\)

10. \(Cu\left(OH\right)_2+H_2SO_4\rightarrow CuSO_4+2H_2O\)

-Khối lượng mol của SO₂:

\(M_{SO_2}\)=32+16.2=64(g/mol)

-Khối lượng mol của FeCl₂:

\(M_{FeCl_2}\)=56+35,5.2=127(g/mol)

-Khối lượng mol của CuSO₄:

\(M_{CuSO_4}\)=64+32+16.4=160(g/mol)

-Khối lượng mol của Fe₂(SO₄)₃:

\(M_{Fe_2\left(SO_4\right)_3}\)=56.2+32.3+16.12=368(g/mol)

Giải:

Khối lượng mol của lần lượt các chất là:

\(M_{SO_2}=NTK_{SO_2}\left(=32+16.2=64\right)\left(g/mol\right)\)

\(M_{FeCl_2}=NTK_{FeCl_2}\left(=56+35,5.2=127\right)\left(g/mol\right)\)

\(M_{CuSO_4}=NTK_{CuSO_4}\left(=64+4.96=448\right)\left(g/mol\right)\)

\(M_{Fe_2\left(SO_4\right)_3}=NTK_{Fe_2\left(SO_4\right)_3}\left(=2.56+3.96=400\right)\left(g/mol\right)\)

\(M_{Zn\left(NO_3\right)_2}=NTK_{Zn\left(NO_3\right)_2}\left(=65+62.3=251\right)\left(g/mol\right)\)

Các chất còn lại tính theo công thức tính nguyên tử khối

a.

Mg(HCO₃)₂ + 2HCl \(\rightarrow\) MgCl₂ + 2CO₂ + 2H₂O

Ag₂O + 2HCl \(\rightarrow\) 2AgCl + H₂O

AgNO₃ + HCl \(\rightarrow\) AgCl + HNO₃

Fe + 2HCl \(\rightarrow\) FeCl₂ + H₂O

MgO + 2HCl \(\rightarrow\) MgCl₂ + H₂O

Cu(OH)₂ + 2HCl \(\rightarrow\) CuCl₂ + 2H₂O

Mg + 2HCl \(\rightarrow\) MgCl₂ + H₂O

K₂S + 2HCl \(\rightarrow\) 2KCl + H₂S

NaHCO₃ + HCl \(\rightarrow\) NaCl + CO₂ + H₂O

CaSO₃ + 2HCl \(\rightarrow\) CaCl₂ + SO₂ + H₂O

Na₂O + 2HCl \(\rightarrow\) 2NaCl + H₂O

Fe₃O₄ + 8HCl \(\rightarrow\) FeCl₂ + 2FeCl₃ + 4H₂O

Ca(HSO₃)₂ + 2HCl \(\rightarrow\) CaCl₂ + 2SO₂ + 2H₂O

Al(OH)₃ + 3HCl \(\rightarrow\) AlCl₃ + 3H₂O

Zn + 2HCl \(\rightarrow\) ZnCl₂ + H₂

CuO + 2HCl \(\rightarrow\) CuCl₂ + H₂O

Ba(OH)₂ + 2HCl \(\rightarrow\) BaCl₂ + 2H₂O

Fe(NO₃)₂ + 2HCl \(\rightarrow\) FeCl₂ + 2HNO₃

MgCO₃ + 2HCl \(\rightarrow\) MgCl₂ + CO₂ + H₂O

b.

BaCl₂ + H₂SO₄ \(\rightarrow\) BaSO₄ + 2HCl

Mg(HCO₃)₂ + H₂SO₄ \(\rightarrow\) MgSO₄ + CO₂ + 2H₂O

Ag₂O + H₂SO₄ \(\rightarrow\) Ag₂SO₄ + H₂O

2AgNO₃ + H₂SO₄ \(\rightarrow\) Ag₂SO₄ + 2HNO₃

Fe + H₂SO₄ \(\rightarrow\) FeSO₄ + H₂

MgO + H₂SO₄ \(\rightarrow\) MgSO₄ + H₂O

Cu(OH)₂ + H₂SO₄ \(\rightarrow\) CuSO₄ + 2H₂O

Mg + H₂SO₄ \(\rightarrow\) MgSO₄ + H₂

K₂S + H₂SO₄ \(\rightarrow\) K₂SO₄ + H₂S

2NaHCO₃ + H₂SO₄ \(\rightarrow\) Na₂SO₄ + 2CO₂ + H₂O

CaSO₃ + H₂SO₄ \(\rightarrow\) CaSO₄ + SO₂ + H₂O

Na₂O + H₂SO₄ \(\rightarrow\) Na₂SO₄ + H₂O

Fe₃O₄ + 4H₂SO₄ \(\rightarrow\) FeSO₄ + Fe₂(SO₄)₃ + 4H₂O

Ca(HSO₃)₂ + H₂SO₄ \(\rightarrow\) CaSO₄ + SO₂ + 2H₂O

CaCl₂ + H₂SO₄ \(\rightarrow\) CaSO₄ + 2HCl

2Al(OH)₃ + 3H₂SO₄ \(\rightarrow\) Al₂(SO₄)₃ + 6H₂O

Zn + H₂SO₄ \(\rightarrow\) ZnSO₄ + H₂

CuO + H₂SO₄ \(\rightarrow\) CuSO₄ + H₂O

Ba(OH)₂ + H₂SO₄ \(\rightarrow\)BaSO₄ + H₂O

Fe(NO₃)₂ + H₂SO₄ \(\rightarrow\) FeSO₄ + 2HNO₃

MgCO₃ + H₂SO₄ \(\rightarrow\) MgSO₄ + CO₂ + H₂O

\(-PTK_{BaSO_4}=137+32+16.4=233\left(đvC\right)\)

\(-PTK_{Fe\left(OH\right)_3}=56+\left(16+1\right).3=107\left(đvC\right)\)

\(-PTK_{Na_2SO_3}=23.2+32+16.3=126\left(đvC\right)\)

\(-PTK_{Al_2\left(SO_4\right)_3}=27.2+\left(32+16.4\right).3=342\left(đvC\right)\)

\(-PTK_{C_{12}H_{22}O_{11}}=12.12+1.22+16.11=342\left(đvC\right)\)

\(-PTK_{Ca\left(NO_3\right)_2}=40+\left(14+16.3\right).2=164\left(đvC\right)\)

$a)  CaO + H_2O \to Ca(OH)_2$
$b) NaOH + HCl \to NaCl + H_2O$
$c) Ca(OH)_2 + 2HNO_3 \to Ca(NO_3)_2 + 2H_2O$
$d) AlCl_3 + 3NaOH \to Al(OH)_3 + 3NaCl$
$e) Mg(NO_3)_2 + Ca(OH)_2 \to Ca(NO_3)_2 + Mg(OH)_2$
$f) CuCl_2 + 2KOH \to Cu(OH)_2 + 2KCl$

$g) Fe(OH)_2 + H_2SO_4 \to FeSO_4 + 2H_2O$
$h) 2Fe(OH)_3 + 3H_2SO_4 \to Fe_2(SO_4)_3 + 6H_2O$
$i) Al_2(SO_4)_3 + 3BaCl_2 \to 3BaSO_4 + 2AlCl_3$