`A=2^{0}+2^{1}+2^{2}+....+2^{99}`

`=(1+2+2^{2}+2^{3}+2^{4})+(2^{5}+2^{6}+2^{7}+2^{8}+2^{9})+......+(2^{95}+2^{96}+2^{97}+2^{97}+2^{99})`

`=(1+2+2^{2}+2^{3}+2^{4})+2^{5}(1+2+2^{2}+2^{3}+2^{4})+.....+2^{95}(1+2+2^{2}+2^{3}+2^{4})`

`=31+2^{5}.31+....+2^{95}.31`

`=31(1+2^{5}+....+2^{95})\vdots 31`

\(A=2^0+2^1+2^2+2^3+2^4+2^5+2^6+...+2^{99}\)

\(=\left(2^0+2^1+2^2+2^3+2^4\right)+2^5\left(2^0+2^1+2^2+2^3+2^4\right)+...+2^{95}\left(2^0+2^1+2^2+2^3+2^4\right)=31+31.2^5+...+31.2^{95}=31\left(1+2^5+...+2^{95}\right)⋮31\)

A = 2⁰ + 2¹ + 2² + 2³ + 2⁴ + 2⁵ … + 2⁹⁹

^A=( 2⁰ + 2¹ + 2² + 2³ + 2⁴⁾ +( 2⁵ … + 2⁹⁹⁾

A= 2⁰.(2⁰ + 2¹ + 2² + 2³ + 2⁴)+2⁵.( 2⁵ … + 2⁹⁹⁾

A= 1. 31+ 2⁵.31… + 2⁹⁵.31

^A= 31. (1+2⁵...+2⁹⁵)

KL: ...... 

\(A=2^0+2^1+2^2+2^3+2^4+...+2^{99}=\left(2^0+2^1+2^2+2^3+2^4\right)+2^5\left(2^0+2^1+2^2+2^3+2^4\right)+...+2^{95}\left(2^0+2^1+2^2+2^3+2^4\right)=31+31.2^5+...+31.2^{95}=31\left(1+2^5+...+2^{95}\right)⋮31\)

A = 2⁰ + 2¹ + 2² + 2³ + 2⁴ + 2⁵ … + 2⁹⁹

A=( 2⁰ + 2¹ + 2² + 2³ + 2⁴⁾ +( 2⁵ … + 2⁹⁹⁾

A= 2⁰.(2⁰ + 2¹ + 2² + 2³ + 2⁴)+2⁵.( 2⁵ … + 2⁹⁹⁾

A= 1. 31+ 2⁵.31… + 2⁹⁵.31

A= 31. (1+2⁵...+2⁹⁵)

KL: ...... 

a) 17 + 23 = 40;   23 + 17 = 40

=> 17 + 23 = 23 + 17

b) (12 + 28) + 10 = 40 + 10 = 50

   12 + (28 + 10) = 12 + 38 = 50

=> (12 + 28) + 10 = 12 + (28 + 10)

c) 17.23 = 391;  23.17 = 391

=> 17.23 = 23.17

d) (5.6).3 = 30.3 = 90;  5.(6.3) = 5. 18 = 90

e) 23.(43+17) = 23. 60 = 1380

   23.43 + 23.17 = 989 + 391 = 1380

=> 23.(43+17) = 23.43 + 23.17

1/

Tổng A là tổng các số hạng cách đều nhau 4 đơn vị.

Số số hạng: $(101-1):4+1=26$

$A=(101+1)\times 26:2=1326$

2/

$B=(1+2+2^2)+(2^3+2^4+2^5)+(2^6+2^7+2^8)+(2^9+2^{10}+2^{11})$

$=(1+2+2^2)+2^3(1+2+2^2)+2^6(1+2+2^2)+2^9(1+2+2^2)$

$=(1+2+2^2)(1+2^3+2^6+2^9)$

$=7(1+2^3+2^6+2^9)\vdots 7$

3/
$C=1+2+2^2+2^3+...+2^{99}$

$2C=2+2^2+2^3+2^4+...+2^{100}$

$\Rightarrow 2C-C=2^{100}-1$

$\Rightarrow C=2^{100}-1$

Câu 20: B

Câu 23: C

Câu 25: C

Câu 28: A

\(A=2+2^3+...+2^{101}\)

\(4A=2^3+2^5+...+2^{101}+2^{103}\)

\(4A-A=2^{103}-2\)

\(3A=2^{103}-2\)

\(A=\dfrac{2^{103}-2}{3}\)

\(\Rightarrow1+2+2^3+...+2^{101}=A+1=\dfrac{2^{103}+1}{3}\)

\(20+21+22+23+24+25+26+27+28+29+30=275\)

(Nhớ k cho mình với nhé!)

cach tinh nhanh 

20+21+22+23+24+25+26+27+28+29+30=275

=(29+20)x5=49x5=245

tick đúng nha

ta thay 21+29=50

co 4 cap =50 

số ở giữa là

[29+21];2=25

tổng là 20+50x4+25=245

mn bày e gấp vs ạ,e đag cần gấp lắm

ôi bạn ơi

mik ko bt

a. 800-{50.[18-2³) : 2 + 3²]}

= 800 - {50.[18 - 8) : 2 + 9]}

= 800 - {50.[10 : 2 + 9]}

= 800 - [50.(5 +9)]

= 800 - (50 . 14)

= 700

= 100

b. 28.(231+69) + 72.(131+169)

= 28.300 + 72.300

= 300 . (28 + 72)

= 300 . 100

= 30000

A=20+30)+(21+29)+(28+22)+(27+23)+(26+24)+25

=>A=50+50+50+50+50+25

=>A=250+25

=>A=275

A=20+21+22+23+24+25+26+37+28+29+30

= (20+30)+(21+29)+(22+28)+(23+27)+(24+26)+25

=  50 + 50 + 50 + 50 + 50 + 25

= 100 + 50 + 50 + 50 + 25

= 150 + 50 + 50 + 25

= 200 + 50 +25

= 250 + 25

 A = 275

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