\(1,\sqrt{3}x-3=\sqrt{27}\)

\(\Leftrightarrow\sqrt{3}x-3=3\sqrt{3}\)

\(\Leftrightarrow\sqrt{3}\left(x-\sqrt{3}\right)=3\sqrt{3}\)

\(\Leftrightarrow x-\sqrt{3}=3\)

\(\Leftrightarrow x=3+\sqrt{3}\)

\(2,\sqrt{2}x-\sqrt{28}=\sqrt{32}\)

\(\Leftrightarrow\sqrt{2}x-2\sqrt{7}=4\sqrt{2}\)

\(\Leftrightarrow\sqrt{2}x=4\sqrt{2}+2\sqrt{7}\)

\(\Leftrightarrow x=\dfrac{\sqrt{2^2}\left(2\sqrt{2}+\sqrt{7}\right)}{\sqrt{2}}\)

\(\Leftrightarrow x=\sqrt{2}\left(2\sqrt{2}+\sqrt{7}\right)\)

\(\Leftrightarrow x=4+\sqrt{14}\)

\(3,\sqrt{6}x-2\sqrt{6}=\sqrt{54}\)

\(\Leftrightarrow\sqrt{6}\left(x-2\right)=3\sqrt{6}\)

\(\Leftrightarrow x-2=3\)

\(\Leftrightarrow x=5\)

\(4,\sqrt{3}x-\sqrt{2}x=\sqrt{3}+\sqrt{2}\)

\(\Leftrightarrow\left(\sqrt{3}-\sqrt{2}\right)x=\sqrt{3}+\sqrt{2}\)

\(\Leftrightarrow x=\dfrac{\sqrt{3}+\sqrt{2}}{\sqrt{3}-\sqrt{2}}\)

a) \(\left(x+1\right)\left(x+2\right)=272\)

\(\Rightarrow x^2+3x+2=272\)

\(\Rightarrow x^2+3x-270=0\)

\(\Rightarrow x^2+18x-15x-270=0\)

\(\Rightarrow x\left(x+18\right)-15\left(x+18\right)=0\)

\(\Rightarrow\left(x+18\right)\left(x-15\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}x+18=0\\x-15=0\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=-18\\x=15\end{matrix}\right.\)

d) \(\left(x+4\right)\left(x+5\right)=552\)

\(\Rightarrow x^2+9x+20=552\)

\(\Rightarrow x^2+9x-532=0\)

\(\Rightarrow x^2+28x-19x-532=0\)

\(\Rightarrow x\left(x+28\right)-19\left(x+28\right)=0\)

\(\Rightarrow\left(x+28\right)\left(x-19\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}x+28=0\\x-19=0\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=-28\\x=19\end{matrix}\right.\)

2 bạn sai rồi!!!

`-5(x+4) -3(x-2)=-114`

`=>-5x-20 - (3x-6)=-114`

`=> -5x-20 - 3x+6=-114`

`=> -8x -14=-114`

`=>-8x= -100`

`=>x=-100 : (-8)`

`=>x= 12,5`

giúp mik nha mik cần gấp

\(-5\left(x+4\right)-3\left(x-2\right)=-114\)

\(\Leftrightarrow-5x-20-3x+6=-114\)

\(\Leftrightarrow-5x-3x=-114+20-6\)

\(\Leftrightarrow-8x=-100\)

\(\Leftrightarrow x=\dfrac{-100}{-8}=\dfrac{100}{8}\)

\(2\left(x-3\right)+3x+0,5=\dfrac{3}{4}\\ \Leftrightarrow2x-6+3x+\dfrac{1}{2}=\dfrac{3}{4}\\ \Leftrightarrow x\left(2+3\right)=\dfrac{3}{4}-\dfrac{1}{2}+6\\ \Leftrightarrow5x=\dfrac{25}{4}\\ \Leftrightarrow x=\dfrac{25}{4}:5=\dfrac{5}{4}\\ ---\\ 4^{x+2}+4^x=272\\ \Leftrightarrow4^x\left(4^2+1\right)=272\\ \Leftrightarrow4^x.17=272\\ \Leftrightarrow4^x=\dfrac{272}{17}=16=4^2\\ Vậy:x=2\\ ----\\ \left(1,2-5x\right)\left(2\dfrac{1}{8}+\dfrac{1}{2}x\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}1,2-5x=0\\2,125+0,5x=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}5x=1,2\\0,5x=-2,125\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=\dfrac{1,2}{5}=0,24\\x=\dfrac{-2,125}{0,5}=-4,25\end{matrix}\right.\)

a) \(2\left(x-3\right)+3x+0,5=\dfrac{3}{4}\)

\(\Rightarrow2x-6+3x+\dfrac{1}{2}=\dfrac{3}{4}\)

\(\Rightarrow5x-6=\dfrac{3}{4}-\dfrac{1}{2}\)

\(\Rightarrow5x-6=\dfrac{1}{4}\)

\(\Rightarrow5x=\dfrac{1}{4}+6\)

\(\Rightarrow5x=\dfrac{25}{4}\)

\(\Rightarrow x=\dfrac{25}{4}:5\)

\(\Rightarrow x=\dfrac{5}{4}\)

b) \(4^{x+2}+4^x=272\)

\(\Rightarrow4^x\cdot4^2+4^x\cdot1=272\)

\(\Rightarrow4^x\cdot\left(16+1\right)=272\)

\(\Rightarrow4^x\cdot17=272\)

\(\Rightarrow4^x=16\)

\(\Rightarrow4^x=4^2\)

\(\Rightarrow x=2\)

c) \(\left(1,2-5x\right)\left(2\dfrac{1}{8}+\dfrac{1}{2}x\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}1,2-5x=0\\\dfrac{15}{8}+\dfrac{1}{2}x=0\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}5x=1,2\\\dfrac{1}{2}x=-\dfrac{15}{8}\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{1,2}{5}\\x=-\dfrac{15}{8}:\dfrac{1}{2}\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{6}{25}\\x=-\dfrac{15}{4}\end{matrix}\right.\)

\(2^x+2^{x+3}=114\)

\(\Leftrightarrow2^x.\left(1+2^3\right)=114\)

\(\Leftrightarrow2^x.9=114\)

\(\Leftrightarrow2^x=\dfrac{38}{3}\)

Đến đây tịt ngẩm :(

\(\left(x-2\right)^3=272\)

\(\text{Bài toán được giải trên tập số phức}\)

\(\text{Lời giải thu được}\)

\(2\sqrt[3]{34}+2\)

Đề như thế này à 2^x+2^x+4=272