\(-\dfrac{5}{7}+\dfrac{8}{11}+\left(-\dfrac{2}{7}\right)+\dfrac{1}{4}+\dfrac{3}{11}.\\ =\left(\dfrac{-5}{7}+\dfrac{-2}{7}\right)+\left(\dfrac{8}{11}+\dfrac{3}{11}\right)+\dfrac{1}{4}.\\ =-\dfrac{7}{7}+\dfrac{11}{11}+\dfrac{1}{4}.\\ =-1+1+\dfrac{1}{4}.\\ =0+\dfrac{1}{4}=\dfrac{1}{4}.\)

\(\dfrac{2}{7}.\dfrac{5}{13}+\dfrac{2}{7}\dfrac{6}{13}-\dfrac{2}{7}.1\dfrac{11}{13}.\\ =\dfrac{2}{7}.\dfrac{5}{13}+\dfrac{2}{7}\dfrac{6}{13}-\dfrac{2}{7}.\dfrac{24}{13}.\\ =\dfrac{2}{7}\left(\dfrac{5}{13}+\dfrac{6}{13}-\dfrac{24}{13}\right).\\ =\dfrac{2}{7}.\left(\dfrac{-13}{13}\right).\\ =\dfrac{2}{7}.\left(-1\right)=\dfrac{-2}{7}.\)

35 x 64-36 x 35-250

=35 x (64-36)-250

=35 x 28-250

=980-250

=730

35 x 64 - 36 x 35 - 250

= 35 x ( 64 - 36 ) - 250

= 35  x 28 - 250

= 980 - 250

= 730

35 x ( 64 - 36 ) - 250

= 35 x 28 - 250

= 980 -250

= 730 

Tính giá trị của biểu thức sau ( hợp lí nếu có thể ):

a) \(\left(-25\right)\times\left(-5\right)\times\left(-0,4\right)\times\left(-0,2\right)\)

\(=\left[25\times\left(-0,2\right)\right]\times\left[5\times\left(-0,4\right)\right]\)

\(=\left(-5\right)\times2\)

\(=-10\)

b) \(\left(-0,25\right)\times0,02\times40\times\left(-50\right)\times\left(-201,43\right)\)

\(=\left(-0,25\times40\right)\times\left(-50\times0,02\right)\times\left(-201,43\right)\)

\(=\left(-10\right)\times\left(-1\right)\times\left(-201,43\right)\)

\(=10\times\left(-201,43\right)\)

\(=-2014,3\)

Tách ít ra thôi bn.

Tách ít ra thôi bn.

8: =156x200=31200

10: =-1945-567+1945=-567

Bài 5

a) A = -x³ + 6x² - 12x + 8

= -x³ + 3.(-x)².2 - 3.x.2² + 2³

= (-x + 2)³

= (2 - x)³

Thay x = -28 vào A ta được:

A = [2 - (-28)]³

= 30³

= 27000

b) B = 8x³ + 12x² + 6x + 1

= (2x)³ + 3.(2x)².1 + 3.2x.1² + 1³

= (2x + 1)³

Thay x = 1/2 vào B ta được:

B = (2.1/2 + 1)³

= 2³

= 8

Bài 6

a) 11³ - 1 = 11³ - 1³

= (11 - 1)(11² + 11.1 + 1²)

= 10.(121 + 11 + 1)

= 10.133

= 1330

b) Đặt B =  x³ - y³ = (x - y)(x² + xy + y²)

= (x - y)(x² - 2xy + y² + 3xy)

= (x - y)[(x - y)² + 3xy]

Thay x - y = 6 và xy = 9 vào B ta được:

B = 6.(6² + 3.9)

= 6.(36 + 27)

= 6.63

= 378

Bài 6 :

a) \(11^3-1=\left(11-1\right)\left(11^2+11+1^2\right)\)

\(\)\(=10.\left(121+12\right)\)

\(=10.133\)

\(=1330\)

b) \(\left\{{}\begin{matrix}x-y=6\\xy=9\end{matrix}\right.\)

\(\Leftrightarrow\left\{{}\begin{matrix}x^2+y^2-2xy=36\\xy=9\end{matrix}\right.\)

\(\Leftrightarrow\left\{{}\begin{matrix}x^2+y^2-2.18=36\\xy=9\end{matrix}\right.\)

\(\Leftrightarrow\left\{{}\begin{matrix}x^2+y^2=72\\xy=9\end{matrix}\right.\)

Ta có :

\(x^3-y^3=\left(x-y\right)\left(x^2+y^2+xy\right)\)

\(=6.\left(72+9\right)\)

\(=6.81\)

\(=486\)

a. 12x5+12x95=12x(5+95)=12x100=1200

b. 10x20x5x10=(10x10)x(20x5)=100x100=10000

tk nha

a, 12.5+12.95=12.(5+95)

                       =12.100

                       =1200

b,10.20.5.10=(10.10).(20.5)

                    =100.100

                     =10000

a)  \(12\times5+12\times95\)

\(=12\times\left(5+95\right)\)

\(=12\times100\)

\(=1200\)

chúc bạn học tốt

ta có :

99³+1+3(99²+99)

=99³+1+3.99²+3.99

=99³+3.99².1+3.99.1²+1³

= (99+1)³

a, A = 27.36+73.99+27.14 - 49.73

= 27(36+14)+73(99 - 49)

= 27.50 + 73.50 = 50(27+73) = 50.100 = 5000

b, B =  4 5 . 10 . 5 6 + 25 5 . 2 8 : 2 8 . 5 4 + 5 7 . 2 5

Ta có: 4 5 = 2 2 5 = 2 2 . 5 = 2 10 ; 25 5 = 5 2 5 = 5 2 . 5 = 5 10

=>  4 5 . 10 . 5 6 + 25 5 . 2 8 = 2 10 . 2 . 5 . 5 6 + 5 10 . 2 8 =  2 11 . 5 7 + 5 10 . 2 8 =  2 8 . 2 3 . 5 7 + 5 7 . 5 3 . 2 8 =  2 8 . 5 7 . 2 3 + 5 3

Ta lại có:  2 8 . 5 4 + 5 7 . 2 5 = 2 5 . 2 3 . 5 4 + 5 4 . 5 3 . 2 5 =  2 5 . 5 4 . 2 3 + 5 3

Suy ra B =  2 8 . 5 7 . 2 3 + 5 3 :[ 2 5 . 5 4 . 2 3 + 5 3 ] =  2 8 . 5 7 : 2 5 . 5 4

=  2 8 : 2 5 . 5 7 : 5 4 =  2 3 . 5 3 = 2 . 5 3 = 10 3 = 1000