Tìm số nguyên x, biết:
a) \(\dfrac{-28}{35}=\dfrac{16}{x};\) b) \(\dfrac{x+7}{15}=\dfrac{-24}{36}.\)
\(\dfrac{-2}{9}\)và\(\dfrac{6}{-27}\) b:\(\dfrac{-1}{-5}\)và\(\dfrac{4}{25}\)
Các cặp phân số sau có bằng nhau ko?vì sao?
Bài3: Tìm số nguyên X biết
a)\(\dfrac{-28}{35}\)=\(\dfrac{16}{x}\)
b)\(\dfrac{x+7}{15}\)=\(\dfrac{-24}{36}\)
giúp mình với ae cứu tôi ae cứu tôi :((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((
Bài 2:
a: -2*(-27)=54
6*9=54
=>Hai phân số này bằng nhau
b: -1/-5=1/5=5/25<>4/25
Bài 3:
a: =>16/x=-4/5
=>x=-20
b: =>(x+7)/15=-2/3
=>x+7=-10
=>x=-17
a) \(\dfrac{-2}{9}\) và \(\dfrac{6}{-27}\)
\(\dfrac{6}{-27}=\dfrac{6:\left(-3\right)}{\left(-27\right):\left(-3\right)}=\dfrac{-2}{9}\)
Vậy \(\dfrac{-2}{9}=\dfrac{6}{-27}\)
b) \(\dfrac{-1}{-5}\) và \(\dfrac{4}{25}\)
\(\dfrac{-1}{-5}=\dfrac{\left(-1\right).\left(-5\right)}{\left(-5\right).\left(-5\right)}=\dfrac{5}{25}\)
Do \(5\ne4\Rightarrow\dfrac{5}{25}\ne\dfrac{4}{25}\)
Vậy \(\dfrac{-1}{-5}\ne\dfrac{4}{25}\)
Bài 3
a) \(\dfrac{-28}{35}=\dfrac{16}{x}\)
\(x=\dfrac{35.16}{-28}\)
\(x=-20\)
b) \(\dfrac{x+7}{15}=\dfrac{-24}{36}\)
\(\left(x+7\right).36=15.\left(-24\right)\)
\(36x+252=-360\)
\(36x=-360-252\)
\(36x=-612\)
\(x=\dfrac{-612}{36}\)
\(x=-17\)
\(\dfrac{-28}{35}\)=\(\dfrac{16}{x}\)
\(\dfrac{x+7}{15}\)=\(\dfrac{-24}{36}\)
giúp mình
a: \(\Leftrightarrow\dfrac{16}{x}=\dfrac{-4}{5}\)
hay x=-20
b: =>x+7=-10
hay x=-17
\(-\dfrac{28}{35}=\dfrac{16}{x}\Leftrightarrow-\dfrac{4}{5}=\dfrac{16}{x}\)
\(\Rightarrow-4x=5\cdot16\)
\(\Rightarrow-4x=80\)
\(\Rightarrow x=-20\)
\(\dfrac{x+7}{15}=-\dfrac{24}{36}\Leftrightarrow\)\(\dfrac{x+7}{15}=-\dfrac{2}{3}\)
\(\Rightarrow3\left(x+7\right)=-2\cdot15\)
\(x+7=-30\div3\)
x+7=-10
x=-10-7
x=-17
Tìm số nguyên X biết :
a,-28/35 = 16/x
b,x+7/15=-24/36
a: =>16/x=-4/5
hay x=-20
b: =>x+7/15=-2/3
=>x+7=-10
hay x=-17
tìm số nguyên x,y :
a.\(\dfrac{3}{x}=\dfrac{y}{28}=\dfrac{-39}{91}\)
Ta có: \(\dfrac{3}{x}=\dfrac{y}{8}=\dfrac{-39}{91}\)
\(\Rightarrow\) \(\dfrac{3}{x}=\dfrac{y}{8}=\dfrac{-3}{7}\)
\(\Rightarrow\) \(\dfrac{-3}{-x}=\dfrac{\dfrac{y}{4}}{7}=\dfrac{-3}{7}\)
\(\Rightarrow\) \(\left\{{}\begin{matrix}-x=7\\\dfrac{y}{4}=-3\end{matrix}\right.\)
\(\Rightarrow\) \(\left\{{}\begin{matrix}x=-7\\y=-12\end{matrix}\right.\) (TM)
Vậy x = -7; y = -12
Chúc bn học tốt!
Tìm số nguyên x, biết: ( \(\dfrac{31}{20}-\dfrac{26}{45}\) ) . \(\dfrac{-36}{35}< x< \left(\dfrac{51}{56}+\dfrac{8}{21}+\dfrac{1}{3}\right).\dfrac{8}{13}\)
=\(\dfrac{35}{36}.\dfrac{-36}{35}< x< \dfrac{13}{8}.\dfrac{8}{13}\)
= -1 < x < 1
vậy x = 0
\(\dfrac{-28}{35}=\dfrac{16}{x}\)
giúp mình với mình cần gấp
\(\dfrac{-28}{35}=\dfrac{16}{x}\\ \Rightarrow-28\cdot x=35\cdot16=560\\ x=560:-28\\ x=-20\)
\(A.\dfrac{-15}{28}x\dfrac{7}{25}\\ B.\dfrac{-5}{14}x\dfrac{7}{-3}\\ C.\dfrac{-1}{5}-\dfrac{7}{15}x\dfrac{9}{35}\\ D.\dfrac{-3}{4}-(\dfrac{-1}{2})^2\\ E.\dfrac{-4}{5}-\dfrac{-4}{5}x\dfrac{15}{16}\\F.(\dfrac{3}{4}+\dfrac{-7}{2})x(\dfrac{2}{11}+\dfrac{12}{22})\)
a: \(A=\dfrac{-7}{28}\cdot\dfrac{15}{25}=\dfrac{-1}{4}\cdot\dfrac{3}{5}=\dfrac{-3}{20}\)
b: \(B=\dfrac{-5\cdot7}{14\cdot\left(-3\right)}=\dfrac{35}{42}=\dfrac{5}{6}\)
c: \(C=\dfrac{-1}{5}-\dfrac{1}{5}\cdot\dfrac{3}{5}=\dfrac{-1}{5}-\dfrac{3}{25}=\dfrac{-8}{25}\)
d: \(D=\dfrac{-3}{4}-\dfrac{1}{4}=-1\)
e: \(E=\dfrac{-4}{5}\left(1-\dfrac{15}{16}\right)=\dfrac{-4}{5}\cdot\dfrac{1}{16}=\dfrac{-1}{20}\)
f: \(F=\dfrac{6-7}{4}\cdot\dfrac{4+12}{22}=\dfrac{-1}{4}\cdot\dfrac{8}{11}=\dfrac{-2}{11}\)
Tìm \(x\)
a) \(\dfrac{2-x}{4}=\dfrac{3x-1}{3}\)
b) \(\dfrac{x}{7}=\dfrac{x+16}{35}\)
c) \(\sqrt{x^2+1}=3\)
Lời giải:
a. $\frac{2-x}{4}=\frac{3x-1}{3}$
$\Rightarrow 3(2-x)=4(3x-1)$
$\Rightarrow 6-3x=12x-4$
$\Rightarrow 6+4=12x+3x$
$\Rightarrow 10=15x$
$\Rightarrow x=\frac{10}{15}=\frac{2}{3}$
b.
$\frac{x}{7}=\frac{x+16}{35}$
$\Rightarrow \frac{5x}{35}=\frac{x+16}{35}$
$\Rightarrow 5x=x+16$
$\Rightarrow 4x=16$
$\Rightarrow x=4$
c.
$\sqrt{x^2+1}=3$
$\Rightarrow x^2+1=9$
$\Rightarrow x^2=8\Rightarrow x=\pm \sqrt{8}=\pm 2\sqrt{2}$
Bài 9: Tìm \(x\) biết
1) \(\dfrac{9}{x}=\dfrac{-35}{105}\) 2) \(\dfrac{12}{5}=\dfrac{32}{x}\) 3) \(\dfrac{x}{2}=\dfrac{32}{x}\) 4) \(\dfrac{x-2}{4}=\dfrac{x-1}{5}\)
Bài 10: Cho biểu thức \(A=\dfrac{3}{n+2}\)
a) Số nguyên n phài thỏa mãn điều kiện gì để A là phân số? b) Tìm phân số A khi n = 0? n = 2? n = -7?
Bài 10:
a: Để A là phân số thì n+2<>0
hay n<>-2
b: Khi n=0 thì A=3/2
Khi n=2 thì A=3/(2+2)=3/4
Khi n=-7 thì A=3/(-7+2)=-3/5
Bài 9:
1)9/x = -35/105 2) 12/5 = 32/x 3)x/2 = 32/x x = 9. (-35)/105 x.12/5 = x.32/x 2x.x/2 = 2x.32/x
x = -3 x.12/5=32 xx = 2.32
x= 32:12/5 x^2 = 2.32
x = 40/3 x^2 = 64
x = 8
4) x-2/4 = x-1/5
5(x-2) = 4(x-1)
5x - 10 = 4x - 4
5x - 4x = 10 - 4
x = 6
Bài 10:Cho biểu thức