\(\sqrt{49}+\sqrt{36}-\sqrt{25}+\sqrt{100}=?\)
\(\sqrt{36}+\sqrt{10000}-\sqrt{4}+\sqrt{25}-\sqrt{36}+\sqrt{49}-\sqrt{10000000000}\)
\(\sqrt{36}+\sqrt{10000}-\sqrt{4}+\sqrt{25}-\sqrt{36}+\sqrt{49}-\sqrt{10000000000}\)
\(=6+100-2+5-6+7-100000\)
\(\text{=-99890}\)
=6+100-2+5-6+7-100000
=-99890
Mình có việc bận nên bạn tự làm tiếp nha, mk chỉ ghi kết quả thôi.
\(\sqrt{36.}\sqrt{49}-\sqrt{225}:\sqrt{25}\)
\(\sqrt{36}.\sqrt{49}-\sqrt{225}:\sqrt{25}=6.7-15:5=39\)
\(=\sqrt{6^2}.\sqrt{9^2}-\sqrt{15^2}:\sqrt{5^2}=6.9-15:5=54-3=51\)=51
tính
a) \(\sqrt{16}.\sqrt{25}+\sqrt{196}:\sqrt{49}\)
b) 36 : \(\sqrt{2.3^2.18}-\sqrt{169}\)
c) \(\sqrt{\sqrt{81}}\)
d) \(\sqrt{3^2+4^2}\)
a: \(=4\cdot5+14:7\)
=20+2
=22
a,\(\sqrt{1}+\sqrt{9}+\sqrt{25}+\sqrt{49}+\sqrt{81}\) c\(\sqrt{0,04}+\sqrt{0,09}+\sqrt{0,16}\)
b,\(\sqrt{\dfrac{1}{4}}+\sqrt{\dfrac{1}{9}}+\sqrt{\dfrac{1}{36}}+\sqrt{\dfrac{1}{16}}\) e\(\sqrt{2^2}+\sqrt{4^2}+\sqrt{\left(-6^2\right)}+\sqrt{\left(-8^2\right)}\)
j,\(\sqrt{1,44}-\sqrt{1,69}+\sqrt{1,96}\)
g, \(\sqrt{\dfrac{4}{25}}+\sqrt{\dfrac{25}{4}}+\sqrt{\dfrac{81}{100}}+\sqrt{\dfrac{9}{16}}\)
d\(\sqrt{81}-\sqrt{64}+\sqrt{49}\)
a)\(\sqrt{1}\)+\(\sqrt{9}\)+\(\sqrt{25}\)+\(\sqrt{49}\)+\(\sqrt{81}\)
=1+3+5+7+9
=25
b)=\(\dfrac{1}{2}\)+\(\dfrac{1}{3}\)+\(\dfrac{1}{6}\)+\(\dfrac{1}{4}\)
=\(\dfrac{6}{12}\)+\(\dfrac{4}{12}\)+\(\dfrac{2}{12}\)+\(\dfrac{3}{12}\)
=\(\dfrac{15}{12}\)
c) =0,2+0.3+0,4
= 0.9
d) =9-8+7
=8
j) =1,2-1,3+1.4
= (-0,1)+1,4
=1,4
g) \(\dfrac{2}{5}\)+\(\dfrac{5}{2}\)+\(\dfrac{9}{10}\)+\(\dfrac{3}{4}\)
= (\(\dfrac{4}{10}\)+\(\dfrac{15}{10}\)+\(\dfrac{9}{10}\))+\(\dfrac{3}{4}\)
= \(\dfrac{14}{5}\)+\(\dfrac{3}{4}\)
=\(\dfrac{56}{20}\)+\(\dfrac{15}{20}\)
= \(\dfrac{71}{20}\)
Nhớ tick cho mk nha~
\(\sqrt{36+\sqrt{25+\sqrt{49+\sqrt{81}}}}\) = ?
\(\sqrt{\frac{16}{36}}+\sqrt{\frac{9}{49}}+\sqrt{\frac{121}{25}}\)
= 2/3+3/7+11/5
=23/21+11/5
=346/105
Xin lỗi bn máy mình ko viết được căn
\(\sqrt{\frac{16}{36}}+\sqrt{\frac{9}{49}}+\sqrt{\frac{121}{25}}=\frac{2}{3}+\frac{3}{7}+\frac{11}{5}=\frac{346}{105}\)
Bài 2: Tính:
a.\(\sqrt{81}\)
b. \(\sqrt{8100}\)
c. \(\sqrt{64}\)
d. \(\sqrt{\dfrac{49}{100}}\)
e . \(\sqrt{\dfrac{4}{25}}\)
Tính giá trị của các biểu thức sau :
a/ \(A=\dfrac{1}{\sqrt{25}}+\dfrac{\sqrt{49}}{\sqrt{36}}-\dfrac{2}{\sqrt{100}}\)
b/ \(B=\sqrt{\dfrac{0,01}{1,21}}+3.\dfrac{2}{\sqrt{10^2}+2^2+40}-\dfrac{3}{4}\)
a) \(A=\dfrac{1}{\sqrt{25}}+\dfrac{\sqrt{49}}{\sqrt{36}}-\dfrac{2}{\sqrt{100}}.\)
\(=\dfrac{1}{5}+\dfrac{7}{6}-\dfrac{1}{5}.\)
\(=\left(\dfrac{1}{5}-\dfrac{1}{5}\right)+\dfrac{7}{6}.\)
\(=0+\dfrac{7}{6}=\dfrac{7}{6}.\)
Vậy \(A=\dfrac{7}{6}.\)
b) \(B=\sqrt{\dfrac{0,01}{1,21}}+3.\dfrac{2}{\sqrt{10^2}+2^2+40}-\dfrac{3}{4}.\)
\(=\dfrac{1}{11}+3.\dfrac{2}{10+4+40}-\dfrac{3}{4}.\)
\(=\dfrac{1}{11}+3.\dfrac{1}{37}-\dfrac{3}{4}.\)
\(=\dfrac{1}{11}+\dfrac{1}{9}-\dfrac{3}{4}.\)
\(=\dfrac{36}{396}+\dfrac{44}{396}-\dfrac{297}{296}.\)
\(=-\dfrac{217}{396}.\)
Vậy \(B=-\dfrac{217}{396}.\)
1 tính
\(\left(-\dfrac{1}{3}+\dfrac{5}{6}\right)^2-\dfrac{\sqrt{25^2-\sqrt{49^2}}}{\sqrt{36^2+\sqrt{38^2}}}\)