\(\sqrt{\left(7+2\sqrt{6}\right)^2}-\sqrt{\left(7-2\sqrt{6}\right)^2}\)

\(=7+2\sqrt{6}-7+2\sqrt{6}\)

\(=4\sqrt{6}\)

cho tau mới giải cho

Giúp mình đi

\(\dfrac{53}{9-2\sqrt{7}}+2\sqrt{7}-5\)

\(=9+2\sqrt{7}+2\sqrt{7}-5\)

\(=4+4\sqrt{7}\)

Câu 1:\(\frac{6}{5}\)
Câu 2:  X =  \(\frac{13}{16}\)

\(\frac{3}{2}:\frac{5}{4}=\frac{3}{2}\times\frac{4}{5}=\frac{12}{20}=\frac{3}{5}\)

X x 18/5 = 7/10 + 3/5 

X x 18/5 =  13/10

X            = 13/10 : 18/5

 X            = 13/36 

k cho mik với 

NGU DỐT

=4x^2-4x+1+x^2+6x+9-5x^2+245

=2x+255

=3x^2+7-3x^2-5x+1=-5x+8

\(\left|3x^2+7\right|-3x^2-5x+1\\ =3x^2+7-3x^2-5x+1\\ =\left(3x^2-3x^2\right)-5x+\left(7+1\right)\\ =-5x+8\)

 \(\dfrac{3}{5}+\dfrac{1}{2}-\dfrac{7}{10}=\dfrac{6}{10}+\dfrac{5}{10}-\dfrac{7}{10}=\dfrac{11}{10}-\dfrac{7}{10}=\dfrac{4}{10}=\dfrac{2}{5}\)

\(\dfrac{4}{7}:\dfrac{8}{11}=\dfrac{4}{7}\times\dfrac{11}{8}=\dfrac{44}{56}=\dfrac{11}{14}\)

\(\dfrac{6}{10}+\dfrac{5}{10}-\dfrac{7}{10}=\dfrac{4}{10}=\dfrac{2}{5}\)

\(\dfrac{4}{7}x\dfrac{11}{8}=\dfrac{44}{56}=\dfrac{11}{14}\)

\(\dfrac{3}{5}+\dfrac{1}{2}-\dfrac{7}{10}=\dfrac{6}{10}+\dfrac{5}{10}-\dfrac{7}{10}=\dfrac{4}{10}=\dfrac{2}{5}\)

\(\dfrac{4}{7}:\dfrac{8}{11}=\dfrac{4}{7}\times\dfrac{11}{8}=\dfrac{44}{56}=\dfrac{11}{14}\)

\(\left(3x+2\right)^2+\left(2x-7\right)^2-2\left(3x+2\right)\left(2x-7\right)\)

\(=\left(3x+2-2x+7\right)^2\)

\(=\left(x+9\right)^2\)

\(\dfrac{6^6+2^7.3^6+2^6.3^7}{4.2^3.3^2.2^2}\)

\(=\dfrac{\left(2^2.3\right)^6+2^7.3^6+2^6.3^7}{2^2.2^3.3^2.2^2}\)\(=\dfrac{2^{12}.3^6+2^7.3^6+2^6.3^7}{2^7.3^2}\)

\(=\dfrac{2^6.3^6.\left(2^6+2+3\right)}{2^7.3^2}\)\(=\dfrac{3^4.69}{2}=\dfrac{5589}{2}\)