\(6x\left(1-3x\right)+9x\left(2x-7\right)+171=0\)

\(\Leftrightarrow6x-18x^2+18x^2-63x+171=0\)

\(\Leftrightarrow-57x=-171\)

\(\Leftrightarrow x=3\)

\(\frac{x+1}{2015}+\frac{x+2}{2014}=\frac{x+3}{2013}+\frac{x+4}{2012}\)

\(\Leftrightarrow\left(\frac{x+1}{2015}+1\right)+\left(\frac{x+2}{2014}+1\right)-\left(\frac{x+3}{2013}+1\right)-\left(\frac{x+4}{2012}+1\right)=0\)

\(\Leftrightarrow\)\(\frac{x+2016}{2015}+\frac{x+2016}{2014}-\frac{x+2016}{2013}+\frac{x+2016}{2012}=0\)

\(\Leftrightarrow\left(x+2016\right)\left(\frac{1}{2015}+\frac{1}{2014}-\frac{1}{2013}-\frac{1}{2012}\right)=0\)

\(\Leftrightarrow x+2016=0\) ( vì \(\frac{1}{2015}+\frac{1}{2014}-\frac{1}{2013}-\frac{1}{2012}\ne0\) )

\(\Leftrightarrow x=-2016\)

\(\frac{2012+2013.2014}{2014.2015-2016}=\frac{2012+2013.2014}{2014.\left(2013+2\right)-2016}\)

                     \(=\frac{2012+2013.2014}{2014.2013+2014.2-2016}\)

                     \(=\frac{2012+2013.2014}{2014.2013+2028-2016}\)

                     \(=\frac{2012+2013.2014}{2014.2013+2012}=1\)

\(=1+\dfrac{1}{2012}-1-\dfrac{1}{2013}-\dfrac{1}{2012}+\dfrac{1}{2013}=0\)

= 0

\(\dfrac{1}{4050156}\) - \(\dfrac{1}{2012x2013}\)

=

`=`\(2012\times2014+2014\times1-2013\times2014\)

`=``2014`\(\times\left(2012+1-2013\right)\) 

`= 2014`\(\times0=0\)

`=2012×2014+2014-2013×2014×1=2014×(2012-2013+1)=2014×0=0`

\(2012\cdot2014+2014-2013\cdot2014\\ =2012\cdot2014+2014\cdot1-2013\cdot2014\\ =2014.\left(2012+1-2013\right)\\ =2014.0\\ =0\)

0, vô số số nói chung là ko đếm được

xong rùi đó tích mình đi

=(2012*2013+2013+1)/(2014*2015-2014-2)

=(2013*2013+1)/(2014*2014-2) dat thua so chung

nhin cung biet la 0 chia het.ra cai bai sai roi ban!

vuong que chi ,  Vũ Trí Dũng , Ng Hong Huan , nguyen hai nam, OoO nhóc ngu ngơ OoO dễ bị lừa,  I am your faith ,Lê Anh Tú  , Alan Walker , Kaneki Ken , le anh tu , Quách Kim Ngân , Lê Đình Đạt , Bùi Thị Cẩm Uyên , ...

\(\frac{1+\frac{1}{2}+\frac{1}{3}+...+\frac{1}{2012}}{\frac{2013}{1}+\frac{2014}{2}+\frac{2015}{3}+...+\frac{4024}{2012}-2012}\)

\(=\frac{1+\frac{1}{2}+\frac{1}{3}+...+\frac{1}{2012}}{\left(\frac{2013}{1}-1\right)+\left(\frac{2014}{2}-1\right)+\left(\frac{2015}{3}-1\right)+...+\left(\frac{4024}{2012}-1\right)}\)

\(=\frac{1+\frac{1}{2}+\frac{1}{3}+...+\frac{1}{2012}}{\frac{2012}{1}+\frac{2012}{2}+\frac{2012}{3}+...+\frac{2012}{2012}}\)

\(=\frac{1+\frac{1}{2}+\frac{1}{3}+...+\frac{1}{2012}}{2012.\left(1+\frac{1}{2}+\frac{1}{3}+...+\frac{1}{2012}\right)}\)

\(=\frac{1}{2012}\)

Ủng hộ mk nha ^_-

Đặt phân thức trên là D

=> D=(1+1+1+1+...+1+2013/2+2012/3+...+2/2013+1/2014)/(1/2+1/3+1/4+...+1/2014)

=> D=(1+2013/2+1+2012/3+1+2011/4+...+1+2/2013+1+1/2014+1)/(1/2+1/3+1/4+1/5+...+1/2014)

=> D=(2015/2+2015/3+2015/4+...+2015/2013+2015/2014+1)/(1/2+1/3+1/4+...+1/2014)

=> D=[2015*(1/2+1/3+1/4+1/5+....+1/2014)]/(1/2+1/3+1/4+1/5+...+1/2014)

=> D=2015

UwU

ư uwsuuuuuuuuuuuu kimochiiiiiiiiiiiiiiiiiiii

đùa thôi đáp án: 2015 nha bn

ư ư wsuuuuuuuuuuuuuuuuuuuuuuuuuu kimmmmmooooochiiiiiiiiiii

À quên nhớ FOLOW CHO TUI NHA!

d= 2015