a) Ta có :

\(-\dfrac{8}{31}=\dfrac{-8\cdot101}{31\cdot101}=\dfrac{-808}{3131}< \dfrac{-789}{3131}\)

BCNN(31,3131)=3131

-8/31=-8.101/31.101                           -789/3131=-789/3131

-8/31=-808/3131 

Vì -789/3131>-808/3131 nên -789/3131>-8/31

\(\dfrac{-8}{31}>\dfrac{-789}{3131}\)

\(\dfrac{2727}{3131}=\dfrac{27.101}{31.101}=\dfrac{27}{31}\)

⇒\(\dfrac{27}{31}=\dfrac{2727}{3131}\)

\(\dfrac{27}{31}=\dfrac{27\times101}{31\times101}=\dfrac{2727}{3131}\)

-2525/2929 > -217/245

-2525/2929 > -217/245

-2525/2929 < -217/245

ta có: \(\frac{1717}{2525}=\frac{17}{25}\)

\(\frac{515151}{727272}=\frac{51}{72}=\frac{17}{24}>\frac{17}{25}\)

\(\Rightarrow\frac{1717}{2525}< \frac{515151}{727272}\)

Ta có:

\(\frac{1717}{2525}=\frac{17}{25}\)

\(\frac{515151}{727272}=\frac{51}{72}=\frac{17}{24}\)

Mà: \(\frac{17}{25}< \frac{17}{24}\)

\(\Rightarrow\frac{1717}{2525}< \frac{515151}{727272}\)

tks 2 bạn nha

\(\frac{1717}{2525}=\frac{17}{25};\frac{515151}{727272}=\frac{51}{72}\)

Ta có : \(\frac{17}{25}

\(\frac{1717}{2525}=\frac{17}{25}\)

\(\frac{515151}{727272}=\frac{17}{24}\)

Cùng tử, ta có : 25 > 24

=> \(\frac{17}{25}

1/Vì 179/197<1 ; 971/917>1

=>179/197<971/917

2/Vì 183/184<1 ; 184/183>1

=>183/184<184/183

3/Ta có : -3/31=-3*101/31*101=-303/3131

Vì -303>-789 =>-303/3131>-789/3131 =>-3/31>-789/3131

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Duyệt lẹ !Duyệt lẹ !Duyệt lẹ !

`#3107.101107`

`a)`

Ta có:

\(\dfrac{2727}{3131}=\dfrac{2727\div27}{3131\div31}=\dfrac{27}{31}\)

Vì \(\dfrac{27}{31}=\dfrac{27}{31}\)

\(\Rightarrow\dfrac{27}{31}=\dfrac{2727}{3131}\)

`b)`

Ta có:

\(\dfrac{11}{31}=1-\dfrac{20}{31}=1-\dfrac{200}{310}\)

\(\dfrac{111}{311}=1-\dfrac{200}{311}\)

Vì \(\dfrac{200}{310}>\dfrac{200}{311}\)

\(\Rightarrow1-\dfrac{200}{310}< 1-\dfrac{200}{311}\)

\(\Rightarrow\dfrac{11}{31}< \dfrac{111}{311}.\)

27/31 = 2727/3131

11/31 bé hơn 111/311

3535/4848=5*707/8*606=5/8

=>3535/4848=5/8

\(\frac{3535}{4848}=\frac{5.707}{8.606}=\frac{5}{8}.\frac{707}{606}\)

vì \(\frac{707}{606}>1\Rightarrow\frac{5}{8}.\frac{707}{606}>\frac{5}{8}\)(nhân 2 vế cho \(\frac{5}{8}\))

vậy \(\frac{3535}{4848}>\frac{5}{8}\)