. cíu với mn ơi pls
Tìm số nguyên âm x thỏa mãn: (-5^3) . x^2 = -1125(−53).x2=−1125.
Đáp số: x=
giúp mik vs ạ
Các bạn ơi cíu mình với, thanks mn nha
1 lived
2 wasn't hearing - was thinking
3 walked - was
4 were you doing - phoned
5 was reading - heard
6 was walking - saw
7 had watched - wrote
8 met
9 had you done - moved
10 was - didn't attend
II
1 when we were having lunch
2 had read the instruction, I started the machine
3 went out for a rest, we had finished our assignment
4 she left, it was raining
5 learning English
6 to help me
7 the man to open the briefcase
8 my friend break the bottle
9 him fall off the bike
10 a foreign language in a short time is not easy
2.3x-1=53
cíu nhanh mn ớiii
\(2\cdot3^x-1=53\\ \Leftrightarrow2\cdot3^x=54\\ \Leftrightarrow3^x=27\\ \Leftrightarrow x=3\)
\(2\cdot3^x-1=53\\ 2\cdot3^x=54\\ 3^x=27\\ 3^x=3^3=>x=3\)
\(...\Rightarrow2.3^x=54\)
\(\Rightarrow3^x=27\)
\(\Rightarrow3^x=3^3\)
\(\Rightarrow x=3\)
mn ơi giúp mình với pls
Mn ơi, cíu mk
Cíu em mn ơi TvT
cíu bé vs mn ơi
\(A=\left\{x\in Z|\left(x^2-9\right)\left(x^2-7\right)\left(3x+5\right)=0\right\}\)
Giải pt \(\left(x^2-9\right)\left(x^2-7\right)\left(3x+5\right)=0\) \(\left(dk:x\in Z\right)\)
\(\Leftrightarrow\left[{}\begin{matrix}x^2-9=0\\x^2-7=0\\3x+5=0\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}x=\pm3\left(tm\right)\\x=\pm\sqrt{7}\left(ktm\right)\\x=-\dfrac{5}{3}\left(ktm\right)\end{matrix}\right.\)
Vậy \(A=\left\{-3;3\right\}\)
Cíu mình dới mn ơi huhu
cần chi tiết ko bạn
hay mỗi đáp án nhợ
Ta có:\(\sqrt{14-2\sqrt{33}}\)=1,584573983
\(\sqrt{33-4\sqrt{33}}\)=3,165714677
=>1,584573983\(-\)3,165714677=-1,581140694
nhé bạn
z2988436533485_b5b7ea58fd38dab451eedf42dd7b7c56 (1) cíu mik mn ơi