Tìm X
2^4.x-3 + 74 = 106
Tìm x biết (x-2) (x-5) > 0
2^4x-3 +74 =106
1) x={6;7;8;...} hoặc x={0;-1;-2;...}
2) 2^4x-3+74=106
16x-3+74=106
16x=35
x=35/16
thử lại câu 1 mik ko chắc
sai thì chỉ giùm
2.3x + 4.52= 154
24x-3+ 74 = 106
2 . 3 x + 4 . 5 2 = 154
2 . 3 x +100 = 154
2 . 3 x = 54
3 x = 27
3 x = 3 3
=> x = 3
2 4x - 3 + 74 = 106
2 4x - 3 = 32
2 4x - 3 = 2 5
=> 4x - 3 = 5
4x = 8
x = 2
Tìm x thuộc N :
Câu 1 : ( x - 41 ) nhân 109 = 74 nhân 215 -74 nhân 106
Các bạn giúp mình nha .Mình cảm ơn các bạn nhiều nha .
( x - 41 ) . 109 = 74 . 215 - 74 . 106
( x - 41 ) . 109 = 74 . ( 215 - 106 )
( x - 41 ) . 109 = 74 . 109
x - 41 = 74 . 109 : 109
x - 41 = 74
x = 74 + 41
x = 115
Vậy x = 115
=))
\(\left(x-41\right)\times109=74\times215-74\times106\)
\(\left(x-41\right)\times109=74\left(215-106\right)=74.109\)
Chia cả hai vế cho 109 \(\Rightarrow x-41=74\)
\(x=74-41=34\)
(x - 41) x 109 = 74 x 215 - 74 x 106
(x - 41) x 109 = 74 x (215 - 106)
(x - 41) x 109 = 74 x 109
=> x - 41 = 74
=> x = 74 + 41
=> x = 115.
Bạn k mik nha !!!
Tìm X:
a, 25 + 3 ( x-8 ) = 106
b, 3 mũ 2 ( x+4 ) - 5 mũ 2 = 5.2 mũ 2
Tìm X:
a, 25 + 3 ( x-8 ) = 106
b, 3 mũ 2 ( x+4 ) - 5 mũ 2 = 5.5 mũ 2
a. 25 + 3(x-8) = 106
3(x-8) = 106 - 25 = 81
x -8 = 81 : 3 = 27
x = 27 +8 = 35
b. 32(x +4) - 52 = 5.52
9(x+4) - 25 = 5.25 = 125
9(x+4) = 125 + 25 = 150(Đề sai)
Tìm X:
a, 25 + 3 ( x-8 ) = 106
b, 3 mũ 2 ( x+4 ) - 5 mũ 2 = 5.2 mũ 2
3.(x-8) = 106-25
3.(x-8) = 81
x-8 = 81:3
x-8 = 27
x=35
\(a,25+3\left(x-8\right)=106\\ 3\left(x-8\right)=81\\ x-8=27\\ x=35\)
32 . (x + 4 ) - 52 = 5 . 22
9 . ( x + 4 ) - 25 = 20
9 . ( x + 4 ) = 20 + 25
9 . ( x + 4 ) = 45
( x + 4 ) = 45 : 9
x + 4 = 5
x = 5 - 4
x = 1
TÌM X:
1, 4(x+3)^2 - 26 = 74
2, 2^2.(-2)^3 - (x+3) = 24
1) 4(x+3)2 - 26 = 74
4(x+3)2 = 100
(x+3)2 = 25 = 52 = (-5)2
th1: x + 3 = 5
=> x =2
th2: x + 3 = -5
=> x = -8
Câu 2 tương tự
Tính giá trị của biểu thức.
a) 3 054 : 6 × 74 105 × 9 : 5 b) 5 106 × (27 : 3)24 048 : (4 × 2)
a) 3 054 : 6 × 7 = 509 × 7 = 3563
|
4105 × 9 : 5 = 36945 : 5 = 7389 |
b) 5106 × (27 : 3) = 5106 × 9 = 45954 |
24 048 : (4 × 2) = 24 048 : 8 = 3006 |
Tìm x biết
1) 8x ^ 3 - 12x ^ 2 + 6x - 1 = 0
2) x ^ 3 - 6x ^ 2 + 12x - 8 = 27
3) x ^ 2 - 8x + 16 = 5 * (4 - x) ^ 3
4) (2 - x) ^ 3 = 6x(x - 2)
5) (x + 1) ^ 3 - (x - 1) ^ 3 - 6 * (x - 1) ^ 2 = - 10
6) (3 - x) ^ 3 - (x + 3) ^ 3 = 36x ^ 2 - 54x
1) \(8x^3-12x^2+6x-1=0\)
\(\Leftrightarrow\left(2x\right)^2-3\cdot\left(2x\right)^2\cdot1+3\cdot2x\cdot1^2-1^3=0\)
\(\Leftrightarrow\left(2x-1\right)^3=0\)
\(\Leftrightarrow2x-1=0\)
\(\Leftrightarrow2x=1\)
\(\Leftrightarrow x=\dfrac{1}{2}\)
2) \(x^3-6x^2+12x-8=27\)
\(\Leftrightarrow x^3-3\cdot x^2\cdot2+3\cdot2^2\cdot x-2^3=27\)
\(\Leftrightarrow\left(x-2\right)^3=27\)
\(\Leftrightarrow\left(x-2\right)^3=3^3\)
\(\Leftrightarrow x-2=3\)
\(\Leftrightarrow x=3+2\)
\(\Leftrightarrow x=5\)
3) \(x^2-8x+16=5\left(4-x\right)^3\)
\(\Leftrightarrow\left(x-4\right)^2=5\left(4-x\right)^3\)
\(\Leftrightarrow\left(4-x\right)^2=5\left(4-x\right)^3\)
\(\Leftrightarrow5\left(4-x\right)=1\)
\(\Leftrightarrow4-x=\dfrac{1}{5}\)
\(\Leftrightarrow x=4-\dfrac{1}{5}\)
\(\Leftrightarrow x=\dfrac{19}{5}\)
4) \(\left(2-x\right)^3=6x\left(x-2\right)\)
\(\Leftrightarrow8-12x+6x^2-x^3=6x^2-12x\)
\(\Leftrightarrow-12x+6x^2-6x^2+12x=8-x^3\)
\(\Leftrightarrow8-x^3=0\)
\(\Leftrightarrow x^3=8\)
\(\Leftrightarrow x^3=2^3\)
\(\Leftrightarrow x=2\)
5) \(\left(x+1\right)^3-\left(x-1\right)^3-6\left(x-1\right)^2=-10\)
\(\Leftrightarrow x^3+3x^2+3x+1-x^3+3x^2-3x+1-6\left(x^2-2x+1\right)=-10\)
\(\Leftrightarrow\left(x^3-x^3\right)+\left(3x-3x\right)+\left(3x^2+3x^2\right)+\left(1+1\right)-6x^2+12x-6=-10\)
\(\Leftrightarrow0+0+0+\left(6x^2-6x^2\right)+12x-4=-10\)
\(\Leftrightarrow12x-4=-10\)
\(\Leftrightarrow12x=-10+4\)
\(\Leftrightarrow12x=-6\)
\(\Leftrightarrow x=\dfrac{-6}{12}\)
\(\Leftrightarrow x=-\dfrac{1}{2}\)
6) \(\left(3-x\right)^3-\left(x+3\right)^3=36x^2-54x\)
\(\Leftrightarrow27-27x+9x^2-x^3-x^3-9x^2-27x-27=36x^2-54x\)
\(\Leftrightarrow-54x-2x^3=36x^2-54x\)
\(\Leftrightarrow-2x^3=36x^2\)
\(\Leftrightarrow-2x^3-36x^2=0\)
\(\Leftrightarrow-2x^2\left(x+18\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}-2x^2=0\\x+18=0\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=-18\end{matrix}\right.\)