1/4+1/3xX=1/2
mn lm nhanh giúp mik vs
3xX+X=20
mn lm nhanh giúp mik vs
3 x X + X = 20
(3+1) x X =20
4 x X = 20
X= 20:4
X=5
3/4xX-1=1/2xX
mn lm nhanh giúp mik vs
\(\dfrac{3}{4}\times X-1=\dfrac{1}{2}\times X\\ \dfrac{3}{4}\times X-\dfrac{1}{2}\times X=1\\ \left(\dfrac{3}{4}-\dfrac{1}{2}\right)\times X=1\\ \dfrac{1}{4}\times X=1\\ X=1:\dfrac{1}{4}\\ X=4\)
\(\dfrac{3}{4}\times x-1=\dfrac{1}{2}\times x\\ \dfrac{3}{4}\times x-\dfrac{1}{2}\times x=1\\ x\times\left(\dfrac{3}{4}-\dfrac{1}{2}\right)=1\\ x\times\dfrac{1}{4}=1\\ x=1:\dfrac{1}{4}\\x=4\)
D=1/1.5+1/5.9+...+1/41.45 Mn lm nhanh giúp mik vs ạ
D=1/1.5+1/5.9+...+1/41.45
4D=4/1.5+4/5.9+...+4/41.45
4D=1-1/5+1/5-1/9+...+1/41-1/45
4D=1-1/45
D=44/45:4=11/45
1/6+1/12+1/20+1/30+...+1/420 mn lm nhanh giúp mik vs
\(A=\dfrac{1}{6}+\dfrac{1}{12}+\dfrac{1}{20}+...+\dfrac{1}{420}\\ \Rightarrow A=\dfrac{1}{2\times3}+\dfrac{1}{3\times4}+...+\dfrac{1}{20\times21}\\ \Rightarrow A=\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+...+\dfrac{1}{20}-\dfrac{1}{21}\\\Rightarrow A=\dfrac{1}{2}-\dfrac{1}{20}=\dfrac{9}{20}\)
X+X:0,5=27
mn lm nhanh giúp mik vs ak
\(X+X:0,5=27\)
\(\Rightarrow X\left(1+\dfrac{1}{0,5}\right)=27\)
\(\Rightarrow X\left(1+2\right)=27\)
\(\Rightarrow3X=27\Rightarrow X=27:3=9\)
tính nhanh
4 phần 5 + 19 phần 18 - 1 phần 2 + 1 phần 5 - 10 phần 8
ai bt lm thì lm đầy đủ giúp mik nhanh ạ
\(\dfrac{4}{5}+\dfrac{19}{18}-\dfrac{1}{2}+\dfrac{1}{5}-\dfrac{10}{8}\)
\(=\left(\dfrac{4}{5}+\dfrac{1}{5}\right)-\left(\dfrac{4}{8}+\dfrac{10}{8}\right)+\dfrac{19}{18}\)
\(=\dfrac{5}{5}-\dfrac{14}{8}+\dfrac{19}{18}\)
\(=1-\dfrac{7}{4}+\dfrac{19}{18}\)
\(=-\dfrac{3}{4}+\dfrac{19}{18}=\dfrac{11}{36}\)
\(\dfrac{4}{5}+\dfrac{19}{18}-\dfrac{1}{2}+\dfrac{1}{5}-\dfrac{10}{8}=\dfrac{4}{5}+\dfrac{19}{18}-\dfrac{1}{2}+\dfrac{1}{5}-\dfrac{5}{4}=\left(\dfrac{4}{5}+\dfrac{1}{5}\right)+\left(\dfrac{19}{18}-\dfrac{1}{2}\right)-\dfrac{5}{4}=1+\dfrac{5}{9}-\dfrac{5}{4}=\dfrac{36}{36}+\dfrac{20}{36}-\dfrac{45}{36}=\dfrac{11}{36}\)
(x+1)2=(x+1)4
Mik cần gấp lm nhanh hộ mik vs
\(\left(x+1\right)^2=\left(x+1\right)^4\)
\(\Rightarrow\left(x+1\right)^4-\left(x+1\right)^2=0\)
\(\Rightarrow\left(x+1\right)^2\left[\left(x+1\right)^2-1\right]=0\)
\(\Rightarrow\orbr{\begin{cases}\left(x+1\right)^2=0\\\left(x+1\right)^2-1=0\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x+1=0\\\left(x+1\right)^2=1\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=-1\\x+1=\pm1\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=-1\\x=0\text{ or }x=-2\end{cases}}\)
2 . ( x³ -1)-2x²(x+2x⁴) +(4x⁵+4)x=6. 3. (X²-4x+16)(x+4)-x(x+1)(x+2)+3x²= 0 4 . ( 8x +2 ) (1-3x) + ( 6x-1)(4x-10) =-50 Đề bài là tìm x nha mn Nhanh giúp mik vs
2:
=>x^3-1-2x^3-4x^6+4x^6+4x=6
=>-x^3+4x-7=0
=>x=-2,59
4: =>8x-24x^2+2-6x+24x^2-60x-4x+10=-50
=>-62x+12=-50
=>x=1