\(y+\frac{5}{7}-\frac{2}{5}=\frac{38}{35}\)

\(y+\frac{5}{7}=\frac{38}{35}+\frac{2}{5}\)

\(y+\frac{5}{7}=\frac{52}{35}\)

\(y=\frac{52}{35}-\frac{5}{7}\)

\(y=\frac{27}{35}\)

27/35

9: =3/2*5/12+3/16

=15/24+3/16

=5/8+3/16

=13/16

35 . 34 + 35 . 38 + 65 . 75 + 65 . 45 + 35 . 34 = 

= 35 . 34 + 35 . 38 + 35 . 34 + 65 . 75 + 65 . 45 

= 35 . ( 34 + 38 + 34 ) + 65 . ( 75 + 45 )

=  35 . 110  + 65 . 110 

= 110 . ( 35 + 65 ) 

= 110 . 100

= 11000

Hok tốt!!!!!!!!!!!!!

a) Tính bằng cách hợp lí nhất :

35 . 34 + 35 . 38 + 65 . 75 + 65 . 45 + 35 . 34

= 35 . 34 + 35 . 38 + 35 . 34 + 65 . 75 + 65 . 45

= 35 . ( 34 + 38 + 34 ) + 65 . ( 75 + 45 )

= 35 . 106 + 65 . 120

= 3710 + 7800

= 11510

3 . 25 . 8 + 4 . 37 . 6 + 2 . 38 . 12

= 3 . 8 . 25 + 4 . 6 . 37 + 2 . 12 . 38

= 24 . 25 + 24 . 37 + 24 . 38

= 24 . ( 25 + 37 + 38 )

= 24 . 100

= 2400

b) Tìm số tự nhiên x, biết :

( x - 5 ) ( x + 7 ) = 0

\(\Rightarrow\orbr{\begin{cases}x-5=0\\x+7=0\end{cases}\Rightarrow\orbr{\begin{cases}x=5\\x=-7\end{cases}}}.\)

Vậy .......

3 . 25 . 8 + 4 . 37 . 6 + 2 . 38 . 12 = 

= 3 . 8 . 25 +  4 . 6 . 37 + 2 . 12 . 38

= 24 . 25 + 24 . 37 + 24 . 38

= 24 . ( 25 + 37 + 38 )

= 24 . 100 

= 2400

Hok tốt!!!!!!!!!!!

\(\left(\frac{a}{b}+\frac{5}{7}\right).\frac{4}{5}=\frac{38}{35}\)

\(\left(\frac{a}{b}+\frac{5}{7}\right)=\frac{38}{35}:\frac{4}{5}\)

\(\left(\frac{a}{b}+\frac{5}{7}\right)=\frac{19}{14}\)

\(\frac{a}{b}=\frac{19}{14}-\frac{5}{7}\)

\(\frac{a}{b}=\frac{9}{14}\)

Vậy \(\frac{a}{b}=\frac{9}{14}\)

60) \(\sqrt{7-3\sqrt{5}}=\dfrac{\sqrt{14-6\sqrt{5}}}{\sqrt{2}}=\dfrac{\left(3-\sqrt{5}\right)}{\sqrt{2}}=\dfrac{3\sqrt{2}-\sqrt{10}}{2}\)

59) \(\sqrt{6+\sqrt{35}}=\dfrac{\sqrt{12+2\sqrt{35}}}{\sqrt{2}}=\dfrac{\sqrt{7}+\sqrt{5}}{\sqrt{2}}=\dfrac{\sqrt{14}+\sqrt{10}}{2}\)

61) \(\sqrt{23+3\sqrt{5}}=\dfrac{\sqrt{46+6\sqrt{5}}}{\sqrt{2}}=\dfrac{3\sqrt{5}+1}{\sqrt{2}}=\dfrac{3\sqrt{10}+\sqrt{2}}{2}\)

62) \(\sqrt{7-\sqrt{33}}=\dfrac{\sqrt{14-2\sqrt{33}}}{\sqrt{2}}=\dfrac{\sqrt{11}-\sqrt{3}}{\sqrt{2}}=\dfrac{\sqrt{22}-\sqrt{6}}{2}\)

63) \(\sqrt{8+\sqrt{55}}=\dfrac{\sqrt{16+2\sqrt{55}}}{\sqrt{2}}=\dfrac{\sqrt{11}+\sqrt{5}}{\sqrt{2}}=\dfrac{\sqrt{22}+\sqrt{10}}{2}\)

   35 . 34 + 35 . 38 +5 .28 .7

= 35 . 34 + 35 . 38 + 35 . 28 

=  35  .( 34+38+28)

=35.100

=3500

\(a,\) Số số hạng là \(\left(40-2\right):2+1=20\left(số\right)\)

Tổng là \(\left(40+2\right)\times20:2=420\)

\(b,\) Số số hạng là \(\left(39-1\right):2+1=20\left(số\right)\)

Tổng là \(\left(39+1\right)\times20:2=400\)

a) 2 + 4 + 6 + 8 + ... + 34 + 36 + 38 + 40

= ( 2 + 42 ) + ( 4 + 38 ) + .... + ( 20 + 22 )

= 42 \(\times\) 10

= 420

b) 1 + 3 + 5 + 7 + ... + 35 + 37 + 39

= ( 1 + 39 ) + ( 3 + 37 ) + ...+ ( 19 + 21 )

= 40 \(\times\) 10

= 400

57.\(\sqrt{8-\sqrt{55}}=\sqrt{\dfrac{16-2.\sqrt{5}.\sqrt{11}}{2}}=\sqrt{\dfrac{\sqrt{11}^2-2.\sqrt{5}.\sqrt{11}+\left(\sqrt{5}\right)^2}{2}}\)

\(=\sqrt{\dfrac{\left(\sqrt{11}-\sqrt{5}\right)^2}{2}}=\dfrac{\left|\sqrt{11}-\sqrt{5}\right|}{\sqrt{2}}=\dfrac{\sqrt{11}-\sqrt{5}}{\sqrt{2}}\)

58. \(\sqrt{7+\sqrt{33}}=\sqrt{\dfrac{14+2\sqrt{3}.\sqrt{11}}{2}}=\sqrt{\dfrac{\left(\sqrt{11}\right)^2+2\sqrt{3}.\sqrt{11}+\left(\sqrt{3}\right)^2}{2}}\)

\(=\sqrt{\dfrac{\left(\sqrt{11}+\sqrt{3}\right)^2}{2}}=\dfrac{\left|\sqrt{11}+\sqrt{3}\right|}{\sqrt{2}}=\dfrac{\sqrt{11}+\sqrt{3}}{\sqrt{2}}\)

mấy câu dưới bạn cũng làm tương tự thôi

60) \(\sqrt{7-3\sqrt{5}}=\dfrac{\sqrt{14-6\sqrt{5}}}{\sqrt{2}}=\dfrac{3-\sqrt{5}}{\sqrt{2}}=\dfrac{3\sqrt{2}-\sqrt{10}}{2}\)

61) \(\sqrt{23+3\sqrt{5}}=\dfrac{\sqrt{46+6\sqrt{5}}}{\sqrt{2}}=\dfrac{3\sqrt{5}+1}{\sqrt{2}}=\dfrac{3\sqrt{10}+\sqrt{2}}{2}\)

62) \(\sqrt{7-\sqrt{33}}=\dfrac{\sqrt{14-2\sqrt{33}}}{\sqrt{2}}=\dfrac{\sqrt{11}-\sqrt{3}}{\sqrt{2}}=\dfrac{\sqrt{22}-\sqrt{6}}{2}\)

63) \(\sqrt{8+\sqrt{55}}=\dfrac{\sqrt{16+2\sqrt{55}}}{\sqrt{2}}=\dfrac{\sqrt{11}+\sqrt{5}}{\sqrt{2}}=\dfrac{\sqrt{22}+\sqrt{10}}{2}\)

C

B

C