*Rút gọn :

`(8.5-8.2)/16=(8.(5-2))/(8.2)=(8.3)/(8.2)=3/2`

`(11.4-11)/(2-13)=(11.(4-1))/(-11)=(11.3)/(-1.11)=3/(-1)=-3`

*Quy đồng :

- Ta có : `-3=(-3)/1`

UCLN(2,1)=2

$\to\begin{cases} \dfrac32=\dfrac32\\\dfrac{-3}1=\dfrac{-6}2\end{cases}$

\(\frac{8.5-8.2}{16}\)

\(=\frac{8.\left(5-2\right)}{8.2}=\frac{8.3}{8.2}=\frac{3}{2}\)

\(\frac{8.5-8.2}{16}\)

\(=\frac{8.\left(5-2\right)}{16}\)

\(=\frac{8.3}{16}\)

\(=\frac{4.2.3}{4.4}\)

\(=\frac{6}{4}=\frac{3}{2}\)

\(\frac{8.5-8.2}{16}=\frac{8.\left(5-2\right)}{8.2}=\frac{8.3}{8.2}=\frac{1.3}{1.2}\)

                                                                       =  \(\frac{3}{2}\)

Hoc tốt

8.5+49/

=50/3

=8.(5+2 1/6)

=8.7 1/6

=8.43/6

=152/3

8.5+8.2 1/6

=8.(5+13/6)

=8.43/6

=152/3

Ta có: \(\dfrac{8.5-8.2}{16}=\dfrac{8\left(5-2\right)}{16}=\dfrac{8.3}{16}=\dfrac{3}{2}\) 

           \(\dfrac{11.4-11}{2-13}=\dfrac{11\left(4-1\right)}{-11}=\dfrac{11.3}{-11}=-3\)

a) \(\dfrac{8,5-8,2}{16}=\dfrac{0,3}{16}=\dfrac{0,3\cdot10}{16\cdot10}=\dfrac{3}{160}\)

b) \(\dfrac{17\cdot5-17}{3-20}=\dfrac{17\cdot\left(5-1\right)}{-17}=\dfrac{1\cdot4}{-1}=-4\)

a)

\(\dfrac{8\cdot5-8\cdot2}{16}=\dfrac{8\left(5-2\right)}{16}=\dfrac{3}{2}\)

b)

\(\dfrac{17\cdot5-17}{3-20}=\dfrac{17\left(5-1\right)}{-17}=\dfrac{4}{-1}=-4\)

\(\frac{8,5-8,2}{16}\)=\(\frac{0,3}{16}\)= \(\frac{3}{160}\)=0,01875

\(\frac{11,4-11}{2-13}\)=\(\frac{0,4}{-11}\)=\(\frac{-2}{55}\)

học tốt 

\(\dfrac{-63}{72}=\dfrac{-7}{8}\)

\(\dfrac{20}{-140}=\dfrac{-1}{7}\)

\(\dfrac{3.10}{5.24}=\dfrac{30}{120}=\dfrac{1}{4}\)

\(\dfrac{3.7.11}{22.9}=\dfrac{231}{198}=\dfrac{7}{6}\)

\(\dfrac{8.5-8.2}{16}=\dfrac{24}{16}=\dfrac{3}{2}\)

\(\dfrac{11.4-11}{2-13}=\dfrac{33}{-11}=-3\)

D

B

a. \(\dfrac{8,5-8,2}{16}=\dfrac{0,3}{16}=\dfrac{3}{160}\)

b. \(\dfrac{2\cdot14}{7\cdot8}=\dfrac{1\cdot2}{1\cdot4}=\dfrac{2}{4}=\dfrac{1}{2}\)

c. \(\dfrac{11\cdot4-11}{2-13}=\dfrac{11\left(4-1\right)}{-11}=\dfrac{1\cdot3}{-1}=-3\)

d. \(\dfrac{49+7\cdot49}{49}=\dfrac{49\cdot\left(1+7\right)}{49}=\dfrac{8}{1}=8\)