\( \sqrt{ { x }^{ 2 } -10x+25 \phantom{\tiny{!}}} \)
Những câu hỏi liên quan
\sqrt{ 5+5 \sqrt[ 4 ]{ 5 \phantom{\tiny{!}}} +3 \times \sqrt[ 4 ]{ 25 \phantom{\tiny{!}}} + \sqrt[ 4 ]{ 125 \phantom{\tiny{!}}} }
\left( \dfrac{ 1 }{ \sqrt{ x \phantom{\tiny{!}}} -1 } - \dfrac{ 1 }{ \sqrt{ x \phantom{\tiny{!}}} } \right) \left( \dfrac{ \sqrt{ x \phantom{\tiny{!}}} +1 }{ \sqrt{ x \phantom{\tiny{!}}} -2 } - \dfrac{ \sqrt{ x \phantom{\tiny{!}}} +2 }{ \sqrt{ x \phantom{\tiny{!}}} -1 } \right)
Rút Gọn
Tìm x đễ biêu thức âm
\( \left( \dfrac{ 1 }{ \sqrt{ x \phantom{\tiny{!}}} -1 } - \dfrac{ 1 }{ \sqrt{ x \phantom{\tiny{!}}} } \right) \left( \dfrac{ \sqrt{ x \phantom{\tiny{!}}} +1 }{ \sqrt{ x \phantom{\tiny{!}}} -2 } - \dfrac{ \sqrt{ x \phantom{\tiny{!}}} +2 }{ \sqrt{ x \phantom{\tiny{!}}} -1 } \right) \)
\(=\left(\dfrac{\sqrt{x}}{\sqrt{x}\left(\sqrt{x}-1\right)}-\dfrac{\sqrt{x}-1}{\sqrt{x}\left(\sqrt{x}-1\right)}\right)\left(\dfrac{\left(\sqrt{x}+1\right)\left(\sqrt{x}-1\right)}{\left(\sqrt{x}-2\right)\left(\sqrt{x}-1\right)}-\dfrac{\left(\sqrt{x}-2\right)\left(\sqrt{x}+2\right)}{\left(\sqrt{x}-2\right)\left(\sqrt{x}-1\right)}\right)\)
\(=\dfrac{\sqrt{x}-\sqrt{x}+1}{\sqrt{x}\left(\sqrt{x}-1\right)}\left(\dfrac{x-1}{\left(\sqrt{x}-2\right)\left(\sqrt{x}-1\right)}-\dfrac{x-4}{\left(\sqrt{x}-2\right)\left(\sqrt{x}-1\right)}\right)\)
\(=\dfrac{1}{\sqrt{x}\left(\sqrt{x}-1\right)}.\dfrac{3}{\left(\sqrt{x}-2\right)\left(\sqrt{x}-1\right)}\)
\(=\dfrac{3}{\sqrt{x}\left(\sqrt{x}-2\right)\left(\sqrt{x}-1\right)^2}\)
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Rút gọn
C= \( \dfrac{ \dfrac{ x- \sqrt{ x \phantom{\tiny{!}}} }{ \sqrt{ x \phantom{\tiny{!}}} -1 } - \dfrac{ \sqrt{ x \phantom{\tiny{!}}} +1 }{ x+ \sqrt{ x \phantom{\tiny{!}}} } }{ \dfrac{ \sqrt{ x \phantom{\tiny{!}}} +1 }{ x } } \)
Lời giải:
Xét tử thức:
\(\frac{x-\sqrt{x}}{\sqrt{x}-1}-\frac{\sqrt{x}+1}{x+\sqrt{x}}=\frac{\sqrt{x}(\sqrt{x}-1)}{\sqrt{x}-1}-\frac{\sqrt{x}+1}{\sqrt{x}(\sqrt{x}+1)}=\sqrt{x}-\frac{1}{\sqrt{x}}=\frac{x-1}{\sqrt{x}}\)
\(\Rightarrow C=\frac{x-1}{\sqrt{x}}: \frac{\sqrt{x}+1}{x}=\frac{(\sqrt{x}-1)(\sqrt{x}+1)}{\sqrt{x}}.\frac{x}{\sqrt{x}+1}=\sqrt{x}(\sqrt{x}-1)\)
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Rút gọn: A=\( \dfrac{ x \sqrt{ x \phantom{\tiny{!}}} -8 }{ x+2 \sqrt{ x \phantom{\tiny{!}}} +4 } + \dfrac{ x \sqrt{ x \phantom{\tiny{!}}} +27 }{ x-3 \sqrt{ x \phantom{\tiny{!}}} +9 } \) với x lớn hơn hoặc bằng 0
\(A=\frac{x\sqrt{x}-8}{x+2\sqrt{x}+4}+\frac{x\sqrt{x}+27}{x-3\sqrt{x}+9}\) \(=\frac{\left(\sqrt{x}-2\right)\left(x+2\sqrt{x}+4\right)}{x+2\sqrt{x}+4}+\frac{\left(\sqrt{x}+3\right)\left(x-3\sqrt{x+9}\right)}{x-3\sqrt{x}+9}\) \(=\sqrt{x}-2+\sqrt{x}+3=2\sqrt{x}+1\)
giải phương trình \( \sqrt{ - { x }^{ 2 } +6x-9 \phantom{\tiny{!}}} + { x }^{ 3 } = 27 \)
\(\sqrt{ { \left( x-3 \right) }^{ 2 } \left( 5-3x \right) \phantom{\tiny{!}}} +2x= \sqrt{ 3x-5+4 \phantom{\tiny{!}}} \)
\dfrac{ \sqrt{ y \phantom{\tiny{!}}} -2 }{ \sqrt{ y \phantom{\tiny{!}}} -3 } \times ( \dfrac{ \sqrt{ y \phantom{\tiny{!}}} }{ \sqrt{ y \phantom{\tiny{!}}} -3 } + \dfrac{ 6 \sqrt{ y \phantom{\tiny{!}}} }{ 9-y } - \dfrac{ 3 }{ \sqrt{ y \phantom{\tiny{!}}} +3 } )
\dfrac{ 1 }{ \sqrt{ x \phantom{\tiny{!}}} -3 } + \dfrac{ 4 }{ \sqrt{ x \phantom{\tiny{!}}} +3 } - \dfrac{ 9- \sqrt{ x \phantom{\tiny{!}}} }{ x-9 }
\( \dfrac{ 1 }{ \sqrt{ x \phantom{\tiny{!}}} -3 } + \dfrac{ 4 }{ \sqrt{ x \phantom{\tiny{!}}} +3 } - \dfrac{ 9- \sqrt{ x \phantom{\tiny{!}}} }{ x-9 } \)(ĐKXĐ: \(\left\{{}\begin{matrix}x>=0\\x< >9\end{matrix}\right.\))
\(=\dfrac{1}{\sqrt{x}-3}+\dfrac{4}{\sqrt{x}+3}+\dfrac{\sqrt{x}-9}{\left(\sqrt{x}-3\right)\left(\sqrt{x}+3\right)}\)
\(=\dfrac{\sqrt{x}+3+4\left(\sqrt{x}-3\right)+\sqrt{x}-9}{\left(\sqrt{x}-3\right)\cdot\left(\sqrt{x}+3\right)}\)
\(=\dfrac{2\sqrt{x}-6+4\sqrt{x}-12}{\left(\sqrt{x}-3\right)\left(\sqrt{x}+3\right)}=\dfrac{6\sqrt{x}-18}{\left(\sqrt{x}-3\right)\left(\sqrt{x}+3\right)}\)
\(=6\cdot\dfrac{\left(\sqrt{x}-3\right)}{\left(\sqrt{x}-3\right)\left(\sqrt{x}+3\right)}=\dfrac{6}{\sqrt{x}+3}\)
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Cho biểu thức A =\(\dfrac{ \dfrac{ 1 }{ \sqrt{ 1+x \phantom{\tiny{!}}} } + \sqrt{ 1-x \phantom{\tiny{!}}} }{ \dfrac{ 1 }{ \sqrt{ 1- { x }^{ 2 } \phantom{\tiny{!}}} } +1 } \)
a)Tìm x để A có nghĩa
b) Rút gon A .
c) Tính a với \(x= \dfrac{ \sqrt{ 3 \phantom{\tiny{!}}} }{ 2+ \sqrt{ 3 \phantom{\tiny{!}}} } \)
Rút gọn biểu thức
\(\sqrt{ 48-2 \sqrt{ 135 \phantom{\tiny{!}}} \phantom{\tiny{!}}} -\sqrt{ 45 \phantom{\tiny{!}}} +\sqrt{ 18 \phantom{\tiny{!}}} \)
Ta có: \(\sqrt{48-2\sqrt{135}}-\sqrt{45}+\sqrt{18}\)
\(=\sqrt{45-2\cdot\sqrt{45}\cdot\sqrt{3}+3}-\sqrt{45}+\sqrt{18}\)
\(=\sqrt{\left(\sqrt{45}-\sqrt{3}\right)^2}-\sqrt{45}+\sqrt{18}\)
\(=\sqrt{45}-\sqrt{3}-\sqrt{45}+\sqrt{18}\)
\(=\sqrt{18}-\sqrt{3}\)
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\sqrt[ 3 ]{ x-14 \phantom{\tiny{!}}} -\sqrt{ x-1 \phantom{\tiny{!}}} = 3
\(\sqrt[ 3 ]{ x-14 \phantom{\tiny{!}}} -\sqrt{ x-1 \phantom{\tiny{!}}} = 3\)
ý bạn là cái này hả :)?
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