4x-15=-75
tìm x
tìm x,biết
5-x-16=40+x
4x-10=15-x
15-x=4x-5
x-15=6+4x
-12+x=5x-20
7x-4=20+3x
5x-7=-21-2x
x+15=20-4x
17-x=7-6x
5-x-16=40+x
-x-x=40+16-5
(-x).2=51
-x=51/2=>x=51/2
15-x = 4x -5
15 + 5 = 4x + x
5x = 20
x= 4
x - 15 = 6 + 4x
-15 - 6 = 4x -x
3x = -21
x= -7
Tìm x biết :
(4x - 15 )2016 = (4x-15)2015
\(\left(4x-15\right)^{2016}=\left(4x-15\right)^{2015}\\ \Leftrightarrow\left[{}\begin{matrix}4x-15=0\\4x-15=1\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}4x=15\\4x=16\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=\dfrac{15}{4}\\x=4\end{matrix}\right.\)
Vậy \(x\in\left\{\dfrac{15}{4};4\right\}\)
Tìm max B biết B=15−4x−x2B=15-4x-x^2B=15−4x−x2
Tìm max B biết B=15−4x−x2B=15-4x-x^2B=15−4x−x2
tim x biet [ 4x - 15 ] ^ 2016 = [ 4x - 15 ] ^ 2015
\(\left(4.x-15\right)^{2016}=\left(4.x-15\right)^{2015}\)
=>\(\left(4.x-15\right)^{2016}-\left(4.x-15\right)^{2015}=0\)
=>\(\left(4.x-15\right)^{2015}.\left[\left(4.x-15\right)-1\right]=0\)
=>\(\hept{\begin{cases}\left(4.x-15\right)^{2015}=0\\\left(4.x-15\right)-1=0\end{cases}}\)=>\(\hept{\begin{cases}4x-15=0\\4.x-15-1=0\end{cases}}\)=>\(\hept{\begin{cases}4x=15\\4x=16\end{cases}}\)
=>\(\hept{\begin{cases}x=\frac{15}{4}\\x=4\end{cases}}\)
Vậy.................
(4x - 15)2016 = (4x - 15)2015
(4x - 5)2016 - (4x - 15)2015 = 0
(4x - 5)2015.(4x - 15) - (4x - 15)2015 = 0
(4x - 5)2015.[(4x - 15) - 1] = 0
=> \(\orbr{\begin{cases}\left(4x-5\right)^{2015}=0\\\left(4x-15\right)-1=0\end{cases}}\)=>\(\orbr{\begin{cases}4x-15=0\\4x-15=1\end{cases}}\)
=> \(\orbr{\begin{cases}4x=15\\4x=16\end{cases}}\)=>\(\orbr{\begin{cases}x=\frac{15}{4}\\x=4\end{cases}}\)
a) -12+x=5x-20
b) 4x-10=15-x
c) 7x-4=20+3x
d) 3x-6=5x+2
e) 5x-7=-21-2x
f) 15-x=4x-5
g) x+15=20-4x
a) -12+x=5x-20
-12+x -5x = -20
-12+ ( -4x) = -20
-4x= -20-(-12)
-4x=-8
x= -8: (-4)
x= 2
Vậy....
Ko chắc nha
b) 4x-10=15-x
4x-10 +x=15
5x -10=15
5x= 15+10
5x= 25
x=25:5
x=5
Vậy...
c) 7x-4=20+3x
7x -4 - 3x= 20
4x -4= 20
4x= 20+4
4x= 24
x= 24:4
x=6
Vậy...
(4x+1)(x-3)-(x-7)(4x-1)=15
\(\left(4x+1\right)\left(x-3\right)-\left(x-7\right)\left(4x-1\right)=15\\ \Leftrightarrow4x^2+x-12x-3-\left(4x^2-28x-x+7\right)-15=0\\ \Leftrightarrow4x^2-11x-3-4x^2+29x-7-15=0\\ \Leftrightarrow18x=25\\ \Leftrightarrow x=\dfrac{25}{18}\)
Vậy \(x=\dfrac{25}{18}\)
Lời giải:
$(4x+1)(x-3)-(x-7)(4x-1)=15$
$\Leftrightarrow (4x^2-11x-3)-(4x^2-29x+7)=15$
$\Leftrightarrow 18x-10=15$
$\Leftrightarrow 18x=25$
$\Leftrightarrow x=\frac{25}{18}$
tìm x biết:
a, 5x - 16 = 41 + x
b, 4x - 1 =15 - x
c, x - 15 = 6 + 4x
a, 5x - 16 = 41 + x
=> 5x - x = 41 + 16
=> 4x = 57
=> x = \(\frac{57}{4}\)
Vậy x = \(\frac{57}{4}\)
b) 4x - 1 =15 - x
=> 4x + x = 15 + 1
=> 5x = 16
=> \(x=\frac{16}{5}\)
Vậy \(x=\frac{16}{5}\)
c, x - 15 = 6 + 4x
=> -15 - 6 = 4x - x
=> 3x = - 21
=> x = -7
Vậy x = - 7
Có j sai mong bỏ qua
a, 5x - 16 = 41 + x b, 4x - 1 = 15 - x c, x - 15 = 6 + 4x
5x - x = 16 + 41 4x + x = 15 + 1 x - 4x = 15 + 6
4x = 57 5x = 16 - 3x = 21
x = \(\frac{57}{4}\) x = \(\frac{16}{5}\) x = - 7
Vậy x = \(\frac{57}{4}\) Vậy x = \(\frac{16}{5}\) Vậy x = - 7
a) 5x - 16 = 41 + x
5x - x = 41 + 16
4x = 57
x = 57 : 4
x =\(\frac{57}{4}\)
Vậy x =\(\frac{57}{4}\)
b) 4x - 1 = 15 - x
4x + x = 15 + 1
5x = 16
x = 16 : 5
x =\(\frac{16}{5}\)
Vậy x =\(\frac{16}{5}\)
c) x - 15 = 6 + 4x
x - 4x = 15 + 6
-3x = 21
x = 21 : ( -3 )
x = -7
Vậy x = -7
Chúc bạn học tốt !!!
Tìm x
1) 5x - 16 = 40 + x
2) 4x - 10 = 15 - x
3) 3x - 6 = 5x + 2
4) 15 - x = 4x - 5
5) x - 15 = 6 + 4x
6) -12 + x = 5x - 20
7) 7x - 4 = 20 + 3x
8) 5x - 7 = -21 - 2x
9) x + 15 = 20 - 4x
10) 17 - x = 7 - 6x
Bài2: a)5x-16=40+x
b)4x-10=15-x
c) x+15=20-4x
d)17x=7-6x
Áp dụng theo quy tắc chuyển vế
a) 5x - 16 = 40 + x
x - 5x = -16 - 40
-4x = -56
x = 14
b) 4x - 10 = 15 - x
-x - 4x = -10 - 15
-5x = -25
x = 5
c) x + 15 = 20 - 4x
-4x - x = 15 - 20
-5 x = -5
x= 1
d) 17x = 7 - 6x
-6x - 17x = -7
-23x = -7
x = 7/23
câu 1: tìm x biết:
a, (4x-15)^2016=(4x-15)^2015
b,2^x+2^x+1+2^x+2+2^x+3-480=0
a) => (4x-15).(4x-15)2015=(4x-15)2015
=> 4x-15=1
=> x=4
b) => 4.2x+6-480= 0
=> 4.2x-474=0
=> 4.2x=474
=> 2x= 118,5
ko có gt x thoả mãn đề bài
chả biết câu b trình bày đúng hay sai, hay là đầu bài chép nhầm nữa. Nếu sai ai đó chữa lại hộ cái nhé
_HẾT_
b, 2x+2x+1+2x+2+2x+3-480=0
2^x.1+2^x.2+2^x.2^2+2^x.2^3=480
2^x.(1+2+2^2+2^3)=480
2^x.15=480
2^x=32
2^x=2^5
x=5