Bài 1: 

a) \(4^8\cdot2^{20}=\left(2^2\right)^8\cdot2^{20}=2^{36}\)

 \(64^3\cdot4^5=\left(2^6\right)^3\cdot\left(2^2\right)^5=2^{18}\cdot2^{10}=2^{28}\)

\(y\cdot y^7=y^{1+7}=y^8\)

\(a^n\cdot a^2=a^{n+2}\)

Bài 1:

b) \(10^8:2^8=5^8\)

\(17^8:17^5=17^3\)

\(2^{25}:32^4=2^{25}:2^{20}=2^5\)

\(19^4:9^4=\left(\dfrac{19}{9}\right)^4\)

Bài 2: 

a) Ta có: \(2^x\cdot4=128\)

nên \(2^x=32\)

hay x=5

b) Ta có: \(3^x=81\)

nên \(3^x=3^4\)

hay x=4

Lời giải:

$2520.1254=3160080^1$

5.p.p.5.p.2.q.q = 5².p³.q².2 

\(5.p.p.5.p^2.q.4.q=\left(5.5.4\right).\left(p.p.p^2\right).\left(q.q\right)=100p^4.q^2\)

5.p.p.5.p².q.4.q

= 5².p⁴.2².q²

= 10².p⁴.q²

-4^3.(-5)^2

4^3.4^7 = 4^3+7 = 4^10

ta có :

\(3^3.7^3=\left(3.7\right)^3=21^3\)

3³7³=(3.7)³

\(a,5\cdot p\cdot5\cdot p\cdot2q\cdot4q\)

\(=5^2\cdot p^2\cdot2\cdot q\cdot2^2\cdot q\)

\(=5^2\cdot2^3\cdot p^2\cdot q^2\)

\(b,a\cdot a+b\cdot b+c\cdot c\cdot c+d\cdot d\cdot d\cdot d\)

\(=a^2+b^2+c^3+d^4\)

#Urushi

2.5².5³

2.5².5³

Lê Hoàng Minh trả lời sai rồi.

Mình lỡ bấm nhầm.

Đáp án là 2.5.[5 mũ 3]