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Ta có : 8 > 7 => -8 < -7 =>\(\dfrac{-8}{9}< \dfrac{-7}{9}\)

Ta có: 1<2=>-1>-2=>\(\dfrac{-1}{3}>\dfrac{-2}{3}\)

Ta có:3+6>0=>3>-6=>\(\dfrac{3}{7}>\dfrac{-6}{7}\)

Ta có: 0<0+3=>-3<0=>\(\dfrac{-3}{11}< \dfrac{0}{11}\)

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x:5=900 - 865

x;5=135

x=135x5

x=675

vậy x = 675

865+x:5=900

        x:5 = 900 - 865

        x:5 = 35

          x  = 35:5

          x  = 7

Vậy x = 7

x:5=900 - 865

x;5=135

x=135x5

x=675

1 cách

Chia 3 giảng viên cho 3 sinh viên mỗi người 1 giảng viên hướng dẫn 1 sinh viên.

Mk nghĩ v

`<=> x(y - 2) + y - 2 + 3 = 0`

`<=> (x+1)(y-2) + 3 = 0`

`<=> (x+1)(y - 2) = -3`

`=> x + 1 in Ư(3)`

Đến đây chắc bạn tự làm được rồi ha, xét các ước của `x` và `y`.

a: Ta có: \(\cot\widehat{B}=2.4\)

\(\Leftrightarrow\dfrac{AB}{AC}=\dfrac{12}{5}\)

\(\Leftrightarrow AB=12\left(cm\right)\)

Áp dụng định lí Pytago vào ΔABC vuông tại A, ta được:

\(BC^2=AB^2+AC^2\)

\(\Leftrightarrow BC^2=5^2+12^2=169\)

hay BC=13cm