\(\frac{51.125-51.42-17.150}{3+6+9+...+99}\)=\(\frac{51.125-51.42-17.3.50}{1683}\)=\(\frac{51.125-51.42-71.50}{1683}\)=\(\frac{51\left(125-42-50\right)}{1683}=\frac{51.33}{51.33}=1\)

Tính tử: \(51.125-51.42-17.150\)

\(=51.125-51.42-17.3.50\)

\(=51.125-51.42-51.50\)

\(=51.\left(125-42-50\right)=51.33\)

Tính mẫu: 

Số các số hạng: \(\left(99-3\right):3+1=33\)

Mẫu = \(33.\left(\dfrac{99+3}{2}\right)=33.51\)

\(B=1\)

Bài 1: Thực hiện các phép tính sau:

\(a)\)Chưa rỏ đề

\(b)\)\(5025\div5-25\div5\)

\(=\)\(1005-5\)

\(=\)\(1000\)

\(c)\)\(218-180\div2\div9\)

\(=\)\(218-10\)

\(=\)\(208\)

\(d)\)\(\left(328-8\right)\div32\)

\(=\)\(320\div32\)

\(=\)\(10\)

Bài 1:

a) ( Tôi không nhìn rõ đầu bài )

b) 5025  :  5  -  25  :  5

=  ( 5025  -  25 )  :  5

=        5000   :   5

=       1000

c)   218  -  180  :  2  :  9

=     218   -    180  :  (  2  .  9 )

=      218    -    180   :  18

=       218    -    10

=       208

d)   (  328  -  8  )  :  32

=      320   :   32

=     10 

Bài 2: Thực hiện phép tính:

\(a)\)\(27.75+25.27-150\)

\(=\)\(27.\left(75+25\right)-150\)

\(=\)\(27.100-150\)

\(=\)\(2700-150\)

\(=\)\(2550\)

\(b)\)\(12\div\left\{400\div\left[500-\left(125+25.7\right)\right]\right\}\)

\(=\)\(12\div\left\{400\div\left[500-\left(125+175\right)\right]\right\}\)

\(=\)\(12\div\left\{400\div\left[500-300\right]\right\}\)

\(=\)\(12\div\left\{400\div200\right\}\)

\(=\)\(12\div2\)

\(=\)\(6\)

\(c)\)\(13.17-256\div16+14\div7-1\)

\(=\)\(221-16+2-1\)

\(=\)\(206\)

\(d)\)\(18\div3+182+3.\left(51\div17\right)\)

\(=\)\(6+182+3.3\)

\(=\)\(6+182+9\)

\(=\)\(197\)

a) Viết thương của mỗi phép chia sau dưới dạng phân số (theo mẫu).

13 : 17 = \(\dfrac{13}{17}\)

 21 : 11 = \(\dfrac{22}{11}\)      

40 : 51 = \(\dfrac{40}{51}\)       

72 : 25 = \(\dfrac{72}{25}\)

b) Viết (theo mẫu)

34 : 17 = \(\dfrac{34}{17}\) = 2

20 : 5 =\(\dfrac{20}{5}\) = 4

42 : 42 = \(\dfrac{42}{42}\) = 1         

0 : 6 = \(\dfrac{0}{6}\) = 0

a. = 1

b. = 2/15

c. = 1

d. = 1

a,=17/17=1

b,=7-4-1/15=2/15

c,=9+11+31/51=51/51=1

d,9-1-3/5=5/5=1

a) 11/17 + 6/17 = 1

b) 7/15 - 4/15 - 1/15 = 2/15

c) 9/51 + 11/51 + 31/51 = 1

d) 9/5 - 1/5 - 3/5 = 1

# Học tốt # k mình nha mn

`@` `\text {Ans}`

`\downarrow`

`2023 \times 14 + 2023 \times 83+97`

`= 2023 \times (14+83) + 97`

`= 2023 \times 97 + 97`

`= 196231 +97`

`= 196328`

`78 \times 31+78 \times 24+78 \times 17+78 \times 22 \times 72`

`= 78 \times (31+24+17+22 \times 72)`

`= 78 \times (31+24+17+1584)`

`= 78 \times 1656`

`= 129168`

`371 \times 69+371 \times 14+629 \times 83`

`= 371 \times (69+14) + 629 \times 83`

`= 371 \times 83 + 629 \times 83`

`= 83 \times (371+629)`

`= 83 \times 1000`

`= 83000`

`91 \times 51+49 \times 163-49 \times 72`

`= 91 \times 51 + 49 \times (163-72)`

`= 91 \times 51+49 \times 91`

`= 91 \times (51+49)`

`= 91 \times 100`

`= 9100`

`3 \times 12 \times 17 + 4 \times 9 \times 81 + 2 \times 6 \times 6`

`= 9 \times 4 \times 17 + 4 \times 9 \times 81 + 4 \times 9 \times 2`

`= 9 \times 4 \times (17+81+2)`

`= 36 \times 100` 

`= 3600`

`42 \times 17 + 58 \times 83 \times 42 \times 83 + 42 \times 83 + 17`

`= 17 \times (42+58) + 42 \times 83 \times (58 \times 83 +1)`

`= 17 \times 100 + 3486 \times 4815`

`= 1700 + 16785090`

`= 16786790`

575-[6x+60]=25

       [6x+60]=575-25

       [6x+60]=550

suy ra:

6x+60=550          hoặc          6x+60=-550

6x       =550-60                      6x      =-550-60

6x        =490                           6x     =-610

vậy...

[x+32]-17.2=42

[x+32]-17   =42:2

[x+32]-17   =21

[x+32]         =21+17

[x+32]         =28

suy ra:       

x+32=28            hoặc            x+32=-28

x      =28-32                           x      =-28-32

x      =-4                                x       =-60

315+[125-x]=435

        [125-x]=435-315

        [125-x]=120

suy ra:

125-x=120          hoặc          125-x=-120

       x=125-120                            x=125-(-120)

       x=5                                       x=245

vậy...

a) \(\left(-48\right)+127+\left(-52\right)+73\)

\(=\left(-48-52\right)+\left(127+73\right)\)

\(=-100+200\)

\(=100\)

b) \(\left(-38\right)\cdot45+\left(-38\right)\cdot55\)

\(=\left(-38\right)\cdot\left(45+55\right)\)

\(=\left(-38\right)\cdot100\)

\(=-3800\)

c) \(\left(-125\right)+371+\left(-875\right)+629+150\)

\(=\left(-125-875\right)+\left(371+629\right)+150\)

\(=-1000+1000+150\)

\(=150\)

d) \(271+\left(-392\right)+729+\left(-608\right)+\left(-123\right)\)

\(=\left(271+729\right)+\left(-392-608\right)-123\)

\(=1000-1000-123\)

\(=-123\)

e) \(\left(-48\right)\cdot25+25\cdot\left(-52\right)\)

\(=25\cdot\left(-48-52\right)\)

\(=25\cdot-100\)

\(=-2500\)

f) \(47\cdot\left(-11\right)+47\)

\(=47\cdot\left(-11+1\right)\)

\(=47\cdot-10\)

\(=-470\)

g) \(56-7\cdot8+11\)

\(=56-56+11\)

\(=0+11\)

\(=11\)

h) \(-42+51+2+\left(-11\right)+40\)

\(=\left(-42+2\right)+\left(51-11\right)+40\)

\(=-40+40+40\)

\(=0+40\)

\(=40\)

a: =-48-52+127+73

=200-100

=100

b; \(=-38\left(45+55\right)=-38\cdot100=-3800\)

c: \(=-125-875+371+629+150\)

=-1000+1000+150

=150

d: =271+729-392-608-123

=1000-1000-123

=-123

e: =25(-48-52)

=25*(-100)

=-2500

f: =47(-11+1)

=47(-10)

=-470

g: =56-56+11

=11

h: =-42+2+51-11+40

=-40+40+40

=40