\(\Leftrightarrow5x=40\\ \Leftrightarrow x=8\)

x=8

Ai giúp mình với ạ

5^x+1 = 125
5^x+1 = 5³
⇒ x + 1 = 3
    x = 3 - 1

    x = 2

Vậy x = 2

5^x+1=125

=>5^x. 5=5³

=>5^x=5²

=>x=2

Lời giải:

$5^{x+1}=125=5^3$

$x+1=3$

$x=2$

\(125:5^x+5^2=26\)

\(\Rightarrow125:5^x+25=26\)

\(\Rightarrow125:5^x=26-25\)

\(\Rightarrow125:5^x=1\)

\(\Rightarrow5^x=125:1\)

\(\Rightarrow5^x=125\)

\(\Rightarrow5^x=5^3\)

\(\Rightarrow x=3\)

\(\left(1,25-\dfrac{4}{5}x\right)^3=-125\)

\(=>1,25-\dfrac{4}{5}x=-5\)

\(x=\left(1,25+5\right):\dfrac{4}{5}=6,25:\dfrac{4}{5}=\dfrac{125}{16}\)

Cậu thử tham khảo ạ

https://hoctap.coccoc.com/toan?query=(1.25-4%2F5x)%5E3%3D-125

Ta có : 125 : 5^x = 5 

 => 5^x = 125 : 5 => 5^x = 25

 => 5^x = 5² => x = 2

Ta có : 125 : 5x = 5 

 => 5x = 125 : 5 => 5x = 25

 => 5x = 52 => x = 2

\(\left(15-5x\right)^3=-125\)

\(\Rightarrow\left(15-3x\right)^3=\left(-5\right)^3\)

\(\Rightarrow15-3x=-5\)

\(\Rightarrow3x=20\)

\(\Rightarrow x=\frac{20}{3}\)

Vậy\(x=\frac{20}{3}\)

\(\left(15-5x\right)^3=-125\)

=> \(\left[5\left(3-x\right)\right]^3=\left(-5\right)^3\)

=> \(5\left(3-x\right)=-5\)

=> \(3-x=-1\)

=> \(x=4\)

(15-5x)^3=-5^3

15-5x      =-5

5x           =20

x             =4

10 : (-125) = 8 : (-5x)

-2/25 = 8/-5x

=> -2.(-5x) = 25.8

=> 10x= 200

=> x= 200:10

x= 20

Vậy...

x=20 nha!

Đáp án đúng : C

a) 16635

b)7x=49 x=7

c)125(y+z)=125

y+z=1

cậu cho tớ cách giải đi