(12.5^4-7.5^4):5^3-(18.7-5.18):3
Tim số nguyên x thỏa mãn: 5 ^ (2x - 3) + 7.5 ^ 2 = 12.5 ^ 2
5(\(2x-3\)) + 7.52 = 12.52
5(2\(x\) - 3) = 12.52 - 7.52
5(2\(x\) - 3) = 52.(12 - 7)
5(2\(x-3\)) = 52.5
5(\(2x-3\)) = 53
2\(x-3\) = 3
2\(x\) = 3 + 3
2\(x\) = 6
\(x\) = 6 : 2
\(x\) = 3
5²ˣ⁻³ + 7.5² = 12.5²
5²ˣ⁻³ = 12.5² - 7.5²
5²ˣ⁻³ = 5².(12 - 7)
5²ˣ⁻³ = 5².5
5²ˣ⁻³ = 5³
2x - 3 = 3
2x = 3 + 3
2x = 6
x = 6 : 2
x = 3
tính (2/5)^7.5^7+(9/4)^3:(3/6)^13/2^7.5^2+5^12
\(\frac{6^8.2^4-4^5.18^4}{27^3.8^4-3^9.2^{13}}\)
\(\frac{6^8.2^4-4^5.18^4}{27^3.8^4-3^9.2^{13}}\\ =\frac{2^8.3^8.2^4-2^{2.5}.3^{2.4}.2^4}{3^{3.3}.2^{3.4}-3^9.2^{13}}\\ =\frac{2^{12}.3^8-2^{14}.3^8}{3^9.2^{12}-3^9.2^{13}}\\ =\frac{2^{12}.3^8\left(1-2^2\right)}{3^9.2^{12}.\left(1-2\right)}\\ =\frac{3^8.\left(-3\right)}{3.\left(-1\right)}=3^8\)
Tính P= 16^7.5^4 -16^7.5^3/ 16^7.25^2 -16^7. 5^3
Tính:
a) \(\dfrac{3^6.45^4-15^{13}.5^{\cdot-9}}{27^4.25^3+45^6}\)
b) \(\dfrac{\left(\dfrac{2}{5}\right)^7.5^7+\left(\dfrac{9}{4}\right)^3:\left(\dfrac{3}{16}\right)^3}{2^7.5^2+512}\)
\(a,=\dfrac{3^6\cdot5^4\cdot9^4-5^{13}\cdot3^{13}\cdot5^{-9}}{3^{12}\cdot5^6+9^6\cdot5^6}=\dfrac{3^{14}\cdot5^4-5^4\cdot3^{13}}{3^{12}\cdot5^6+3^{12}\cdot5^6}\\ =\dfrac{3^{13}\cdot5^4\cdot2}{2\cdot3^{12}\cdot5^6}=\dfrac{3}{5^2}=\dfrac{3}{25}\)
\(b,=\dfrac{\left(\dfrac{2}{5}\cdot5\right)^7+\left(\dfrac{9}{4}\cdot\dfrac{16}{3}\right)^3}{2^7\cdot5^2+2^9}=\dfrac{2^7+12^3}{2^7\left(5^2+2^2\right)}=\dfrac{2^7+4^3\cdot3^3}{2^7\cdot29}=\dfrac{2^6\left(2+3^3\right)}{2^7\cdot29}=\dfrac{1}{2}\)
a) \(\dfrac{3^6\cdot3^8\cdot5^4-5^{13}\cdot3^{13}\cdot5^{-9}}{3^{12}\cdot5^6+3^{12}\cdot5^6}=\dfrac{3^{14}\cdot5^4-3^{13}\cdot5^4}{3^{12}\cdot5^6\cdot2}=\dfrac{3^{12}\cdot5^4\left(3^2-3\right)}{3^{12}\cdot5^6\cdot2}=\dfrac{3^2-3}{5^2\cdot2}=\dfrac{6}{50}=\dfrac{3}{25}\)
Tính (2/5)^7.5^7+(9/4)^3:(3/16)^3 phần 2^7.5^2+512
Tính P=16^7.5^4-16^7 .5^3 / 16^7. 25^2- 16^7.5^3
\(P=\dfrac{16^7\cdot5^3\left(5-1\right)}{16^7\cdot\left(25^2-5^3\right)}=\dfrac{5^3\cdot2^2}{5^4-5^3}=\dfrac{5^3\cdot2^2}{5^3\cdot\left(5-1\right)}=1\)
12.5 . -5/7 + 9 3/4 - 1.5 . 5/7
12.5 . -5/7 + 9 3/4 - 1.5 . 5/7
\(=\frac{5}{7}.\left(-60\right)+\frac{39}{4}-5.\frac{5}{7}\)
\(=\frac{5}{7}.\left[\left(-60\right)-5\right]+\frac{39}{4}\)
\(=\frac{5}{7}.\left(-65\right)+\frac{39}{4}\)
\(=\frac{-325}{7}+\frac{39}{4}=\frac{-1027}{28}\)
học tốt
= 25/2 . -5/7+ 39/4 + -3/2 . 5/7 = -125/14 + 39/4 + -15/14 = ( -125/14 + -15/14 ) + 39/4 = -10 + 39/4 = -1/4
Tính : \(\dfrac{\left(\dfrac{2}{5}\right)^7.5^7+\left(\dfrac{9}{4}\right)^3:\left(\dfrac{3}{16}\right)^3}{2^7.5^2+512}\)
\(A=\dfrac{\left(\dfrac{2}{5}\right)^7.5^7+\left(\dfrac{9}{4}\right)^3:\left(\dfrac{3}{16}\right)^3}{2^7.5^2+512}\\ A=\dfrac{128+1728}{153+512}\\ A=\dfrac{1856}{665}=2\dfrac{526}{665}\)
Chúc bạn học tốt!!!
\(\dfrac{\left(\dfrac{2}{5}\right)^7\cdot5^7+\left(\dfrac{9}{4}\right)^3:\left(\dfrac{3}{16}\right)^3}{2^7+5^2+512}\)