a) 23.125+78.125-125

= (23+78-1).125

= 100.125

= 12500

b) 37.46+18.54-17.46+54.2

= (37-17).46+(18+2).54

= 20.46+20.54

= 20.(46+54)

= 20.100

= 2000

c) 3.2²-2³:2+2²

= 3.2²-2²+2²

= 3.2²

= 3.4

= 12

d) 7³.9+3².7⁴-45.539

= 7³.9+9.7⁴-5.9.7².11

= 9.(7³+7⁴)-5.9.7².11

=9.2744-9.2695

= 9.(2744-2695)

= 9.49

= 441

a/

=125(23+78-1)=125.100=12500

b/

=46(37-17)+54(18+2)

=20(46+54)=20.100=2000

c/

=3.2²-2²+2²=3.4=12

d/

=7³.3²+3².7⁴-5.3².7².11=

=3².7²(7+7²-55)=3².7²=441

a)

  23.125 + 78.125 -125

=125.(23+78-1)

=125.100

=12500

b)

  37.46+18.54-17.46+54.2

=46.(37-17)+54.(18+2)

=46.20+54.20

=(46+54).20

=100.20

=2000

c)

  3.2²-2³:2+2²

=3.2²-2²+2²

=3.2²-(2²-2²)

=3.2²

=3.4

=12

d)

  7³.9+3².7⁴-45.539

=7³.9+9.7³.7-9.5.7².11

=9.7³.(1+7)-9.7².(5.11)

=9.7².7.8-9.7².55

=9.7².(7.8-55)

=9.49.(56-55)

=441.1

=441

\(a,23\cdot125+78\cdot125-125\\ =125\cdot\left(23+78-1\right)\\ =125\cdot100\\ =12500\\ b,37\cdot46+18\cdot54-17\cdot46+54\cdot2\\ =46\cdot\left(37-17\right)+54\cdot\left(18+2\right)\\ =46\cdot20+54\cdot20\\ =20\cdot\left(46+54\right)\\ =20\cdot100\\ =2000\\ b,3\cdot2^2-2^3:2+2^2\\ =3\cdot4-4+4\\ =12\\ d,7^3\cdot9+3^2\cdot7^4\\ =7^3\cdot9+7^4\cdot9\\ =7^3\cdot9\cdot\left(1+7\right)\\ =343\cdot9\cdot8\\ =24696\)

a) \(23\cdot125+78\cdot125-125\)

\(=125\cdot\left(23+78-1\right)\)

\(=125\cdot100\)

\(=12500\)

b) \(37\cdot46+18\cdot54-17\cdot46+54\cdot2\)

\(=54\cdot\left(18+2\right)+46\cdot\left(37-17\right)\)

\(=54\cdot20+46\cdot20\)

\(=54\cdot\left(20+46\right)\)

\(=20\cdot100\)

\(=2000\)

c) \(3\cdot2^2-2^3:2+2^2\)

\(=3\cdot2^2-2^2+2^2\)

\(=3\cdot2^2\)

\(=3\cdot4\)

\(=12\)

d) \(7^3\cdot9+3^2\cdot7^4\)

\(=7^3\cdot3^2+3^2\cdot7^4\)

\(=7^3\cdot3^2\cdot\left(1+7\right)\)

\(=24696\)

1/1.2 + 1/2.3 + 1/3.4 + ... + 1/73.74 + 1/74.75

= 1-1/2+1/2-1/3+1/3-1/4+...+1/73-1/74+1/74-1/75

= 1 - 1/75

= 74/75

Nhấn đúng cho mk nha!!!!!!!!!!!

\(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{73.74}+\frac{1}{74.75}\)

\(=\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{73}-\frac{1}{74}+\frac{1}{74}-\frac{1}{75}\)

\(=1-\frac{1}{75}\)

\(=\frac{74}{75}\)

\(\frac{1}{1\cdot2}+\frac{1}{2\cdot3}+\frac{1}{3\cdot4}+...+\frac{1}{73\cdot74}+\frac{1}{74\cdot75}\)

\(=\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{73}-\frac{1}{74}+\frac{1}{74}-\frac{1}{75}\)

\(=\frac{1}{1}-\frac{1}{75}\)

\(=\frac{75}{75}-\frac{1}{75}\)

\(=\frac{74}{75}\)

b) 7³.9+ 3².7⁴- 45.539

=343.9+9.2401-45.539

=9.(343+2401)-45.539

=9.2744-24355

=24696-24355

=341

a) 132- (116-(132-128²))

=132- ( 116-(132-16384))

=132-(116+16252)

=132-16368

=16236

C. 73 . 74 = 77 là Sai

C. 73 x 74 = 77 là sai.

khẳng định nào sau đây sai 

A 24 là bội của 6    B0 là ước nguyên của 2023      C 73.74=77    D ước nguyên của 15 và 3 và 5

=(-259+259)+[(-74)+(-26)]+(-81+581)

=0+(-100)+500

=400

= -259 + 259 - 74 - 26 + 581 + 259 - 81
= 0 - 100 + 840 - 81
= 659

Mình bị nhầm :(( Tại bấm thêm số 259

\(1\frac{13}{15}.0,75-\left(\frac{104}{195}+25\%\right).\frac{24}{47}-3\frac{12}{13}:3\)

\(=\frac{28}{15}.\frac{3}{4}-\left(\frac{8}{15}+\frac{1}{4}\right).\frac{8}{9}-\frac{51}{13}.\frac{1}{3}\)

\(=\frac{7}{5}-\left(\frac{32}{60}+\frac{15}{60}\right).\frac{8}{9}-\frac{17}{13}\)

\(=\frac{7}{5}-\frac{47}{60}.\frac{8}{9}-\frac{17}{13}\)

\(=\frac{7}{5}-\frac{94}{135}-\frac{17}{13}\)

\(=\frac{-212}{351}\)

Tự quy đồng

\(2\frac{3}{4}.\left(-0,4\right)-1\frac{3}{5}.2,75+\left(-1,2\right):\frac{4}{11}\)

\(=\frac{11}{4}.\frac{-2}{5}-\frac{8}{5}.\frac{11}{4}-\frac{6}{5}.\frac{11}{4}\)

\(=\frac{11}{4}.\left(\frac{-2}{5}-\frac{8}{5}-\frac{6}{5}\right)\)

\(=\frac{11}{4}.\frac{-16}{5}\)

\(=\frac{-44}{5}=-8\frac{4}{5}\)

\(=2.6\cdot\left(-2\right):2=2.6\cdot\left(-1\right)=-2.6\)