\(2015.20162016-2016.20152015=2015.2016.10001-2016.2015.10001=0\)

\(A=2016.20152015-2015.20162016\)

\(=2016.2015.10001-2015.2016.1001\)

\(=0\)

\(A=2016.20152015-2015.20162016\)

\(=2016.2015.10001-2015.2016.10001\)

\(=0\)

\(A=2016\cdot20152015-2015\cdot20162016\)

\(A=2016\cdot2015\cdot10001-2015\cdot2016\cdot10001\)

\(A=0\)

A>B like nha

Lan Yêu Nghi THôn 1

Lan Đơ

Tính nhanh :

A = \(2016.20152015-2015.20162016\)

= \(2016.2015.10001-2015.2016.1001\)

=0

\(A=2016.20152015-2015.20162016\)

\(=2016.2015.10001-2015.2016.10001\)

\(=0\)

Tính :

\(\dfrac{1993+1993.1994}{1992.1995+1995}\)= \(\dfrac{1993.1+1993.1994}{1992.1995+1995.1}\)=\(\dfrac{1993\left(1+1994\right)}{1995\left(1992+1\right)}\)=\(\dfrac{1993.1995}{1995.1993}=1\)

a, \(A=2015.20162016-2016.20152015\)

\(A=2015.\left(2016.10001\right)-2016.20152015\)

\(A=\left(2015.10001\right).2016-20152015.2016\)

\(A=20152015.2016-20152015.2016\)

\(A=0\)

Vậy A = 0

b, \(B=\left(3.4.2^{16}\right)^2\div11.2^{13}.4^{11}-16^9\)

\(B=3^2.2^4.2^{32}\div11.2^{13}.\left(2^2\right)^{11}-\left(2^4\right)^9\)

\(B=3^2.2^4.2^{32}\div11.2^{13}.2^{22}-2^{36}\)

\(B=3^2.2^{36}\div11.2^{35}-2^{36}\)

\(B=3^2.2^{35}.2\div11.2^{35}-2.2^{35}\)

\(B=3^2.2\div9=9.2\div9=2\)

Vậy B = 2

c, \(C=2^{10}.13+2^{10}.65\div2^8.104\)

\(C=2^{10}.\left(13+65\right)\div2^8.104\)

\(C=2^{10}.78\div2^8.104\)

\(C=2^{10}.39\div2^8.13\)

\(C=39\div13=3\)

Vậy C = 3

Đề bài câu c sai mk sửa nhé là 2⁸ ms tính đc k nó dư lắm !!!

2015.20162016-2016.20152015

=2015.2016.1001-2016.2015.1001

=0

\(\dfrac{1}{1\cdot2}+\dfrac{1}{2\cdot3}+\dfrac{1}{3\cdot4}+.......+\dfrac{1}{x\cdot\left(x+1\right)}=\dfrac{122}{123}\)

\(\Leftrightarrow1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+......+\dfrac{1}{x}-\dfrac{1}{x+1}=\dfrac{122}{123}\)

\(\Leftrightarrow1-\dfrac{1}{x+1}=\dfrac{122}{123}\)

\(\Leftrightarrow\dfrac{1}{x+1}=\dfrac{1}{123}\)

\(\Leftrightarrow x=122\)

\(445-52+155+452\\ =\left(445+155\right)+\left(452-52\right)\\ =600+4000\\ =1000\\ 102\cdot55-102\cdot73+51\cdot36\\ =102\cdot\left(55-73\right)+51\cdot36\\ =102\cdot\left(-18\right)+102\cdot18\\ =0\\ 4\cdot5\cdot2\cdot25\cdot5-1000\\ =5000-1000\\ =4000\\ 8782-291\cdot13\\ =4999\\ 254+\left\{38\cdot\left[\left(42-16\right):2\right]\right\}\\ =254+\left[38\cdot\left(26:2\right)\right]\\ =254+\left(38\cdot13\right)\\ =748\\ \left(2791\cdot34+7882:14\right)\cdot0+1510-510:2\\ =1510-255\\ =1255\)

a. \(445-52+155+452=\left(445+155\right)+\left(452-52\right)=600+400=1000\)

b. \(102\cdot55-102\cdot73+51\cdot36=102\left(55-73+18\right)=102\cdot0=0\)

c.\(4\cdot5\cdot2\cdot25\cdot5-1000=4\cdot25\cdot5\cdot5\cdot2-1000=100\cdot50-1000=5000-1000=4000\)

d. \(8782-291\cdot13=8782-3783=4999\)

e. \(254+\left\{38\left[\left(42-16\right)\div2\right]\right\}=254+\left\{30\cdot13\right\}=254+494=748\)

f. \(\left(2791\cdot34+7882\div14\right)\cdot0+1510-510\div2=0+1510-255=1255\)\

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