Đáp án: 

\(\dfrac{\left(7x-1\right).5}{6.5}+\dfrac{2x.30}{30}=\dfrac{\left(16-x\right).6}{5.6}\)

khử mẫu

=>(7x-1).5+60x=(16-x).6

=>35x-5+60x=96-6x

=>35x-5+60x-96+6x=0

=>101x-101=0

=>x=1

=>

=>5(7x-1)+60x=6(16-x)

=>35x-5+60x-96+6x=0

=>101x=101

hay x=1

\(\dfrac{7x-1}{6}+2x=\dfrac{16-x}{5}\)

\(\Leftrightarrow\dfrac{5\left(7x-1\right)}{30}+\dfrac{60x}{30}=\dfrac{6\left(16-x\right)}{30}\)

\(\Leftrightarrow5\left(7x-1\right)+60x=6\left(16-x\right)\)

\(\Leftrightarrow35x-5+60x=96-6x\)

\(\Leftrightarrow95x-5-96+6x=0\)

\(\Leftrightarrow101x-101=0\\ \Leftrightarrow101x=101\\ \Leftrightarrow x=1\)

\(\dfrac{7x-1}{6}+2x=\dfrac{16-x}{5}\)

\(\Leftrightarrow\dfrac{5\left(7x-1\right)}{30}+\dfrac{60x}{30}=\dfrac{6\left(16-x\right)}{30}\)

\(\Leftrightarrow5\left(7x-1\right)+60x=6\left(16-x\right)\)

\(\Leftrightarrow35x-5+60x=96-6x\)

\(\Leftrightarrow101x=101\)

\(\Leftrightarrow x=1\)

Vậy: Phương trình có tập nghiệm \(S=\left\{1\right\}\)

20) -5-(x + 3) = 2 - 5x ⇔ -5 - x - 3 = 2 -5x ⇔ 4x = 10 ⇔ x = \(\frac{5}{2}\)

Vậy...

1) 16 - 8x = 0 ⇔ 8(2 - x) = 0⇔ 2 - x = 0 ⇔ x = 2

Vậy phương trình có nghiệm là x = 2

  `[ 7x - 1 ] / 6 + 2x >= [ 16 - x ] / 5`

`<=> [ 5 ( 7x - 1 ) + 60x ] / 30 >= [ 6 ( 16 - x ) ] / 30`

`<=> 35x - 5 + 60x >= 96 - 6x`

`<=>101x >= 101`

`<=> x >= 1`

Vậy `S = { x | x >= 1 }`

có dấu  mk vik bị lộn nha

a) \(\dfrac{2x+3}{-4}\)≥\(\dfrac{4-x}{-3}\)

=> 3(2x+3)≥4(4-x)

<=> 6x+9≥16-4x

<=> 10x ≥ 7

<=> x ≥\(\dfrac{7}{10}\)

a, 3y-2y=2y-3

    3y-2y-2y=3

    -y=3

     y=-3

b, 3-4x+24+6x=x+27+3x

   -4x+6x-x-3x =27-3-24

   -2x              =0

      x             =0

c, 5-(6-x)=4.(3-2x)

   5-6+x =12-8x

   x+8x  =12+6-5

  9x      =13

   x       =13/9

d, 4.(x+3)=-7x+17

   4x+12  =-7x+17

4x+7x     =17-12

11x         =5

  x          =5/11

 A)  \(3y-2y=2y-3\)     \(\Leftrightarrow y-2y=-3\) \(\Leftrightarrow y=3\)

B)  \(3-4x+24+6x=x+27-3x\)\(\Leftrightarrow3-4x+24+6x-x-27-3x=0\)

\(\Leftrightarrow-2x=0\)\(\Leftrightarrow x=0\)

C)   \(5-\left(6-x\right)=4\left(3-2x\right)\)\(\Leftrightarrow5-6x+x-12+8x=0\)\(\Leftrightarrow9x-13=0\)\(\Leftrightarrow x=\frac{13}{9}\)

D)   \(4\left(x+3\right)=-7x+17\) \(\Leftrightarrow4x+12+7x-17=0\)\(\Leftrightarrow11x-5=0\)\(\Leftrightarrow x=\frac{5}{11}\)

E)  \(11x+42-2x=100-9x-22\)\(\Leftrightarrow11x+42-2x-100+9x+22=0\)

\(\Leftrightarrow18x-36=0\)\(\Leftrightarrow x=2\)

 F)  \(5x+\frac{3}{12}=1+\frac{2x}{9}\)\(\Leftrightarrow180x+9-36-8x=0\)\(\Leftrightarrow172x-27=0\)\(\Leftrightarrow x=\frac{27}{172}\)

TK nka !!! Mk giải tiếp !!

\(\frac{7x-1}{6}+2x=\frac{16-x}{5}\)

=> \(\frac{5.\left(7x-1\right)}{30}+\frac{60x}{30}=\frac{6.\left(16-x\right)}{30}\)

=> \(5.\left(7x-1\right)+60x=6.\left(16-x\right)\)

=> \(35x-5+60x=96-6x\)

=> \(35x+6x+60x=5+96\)

=> \(101x=101\)

=> \(x=101:101\)

=>\(x=1\)

\(\frac{5\left(7x+1\right)}{30}\)+\(\frac{60x}{30}\)=\(\frac{6\left(16-X\right)}{30}\)

=> 35X+5+60X=96-6X

=> Bạn tự tính tha!!! Dễ rồi.

c , d giải nốt:

c) 2x + 3/6 = 7x - 13/15

=> (2x + 3) . 15 = (7x - 13) x 6

=> 30x +45 = 42x - 78

=> 30x - 42x = -78 - 45

=> -12x = -123

=> x = 41/4

d) 2-x/4 = 3x - 1/ - 3

=> (2-x) . -3 = 4. (3x - 1)

=> -6 - (-3x) = 12x - 4

(-6) + 4 = 12x - - (-3x)

=> -2 = 9x

=> x = -2/9