\(\dfrac{\left(7x-1\right).5}{6.5}+\dfrac{2x.30}{30}=\dfrac{\left(16-x\right).6}{5.6}\)
khử mẫu
=>(7x-1).5+60x=(16-x).6
=>35x-5+60x=96-6x
=>35x-5+60x-96+6x=0
=>101x-101=0
=>x=1
=>
\(\dfrac{5\left(7x-1\right)}{30}+\dfrac{60x}{30}=\dfrac{6\left(16-x\right)}{30}\\\Rightarrow35x-5+60x=96-6x\\ \Leftrightarrow35x+60x+6x=96+5\\ \Leftrightarrow101x=101\\ \Leftrightarrow x=1 \)