\(=\left(x^2+y^2-5\right)^2-4\left(xy-2\right)^2=\left(x^2+y^2-5+2xy-4\right)\left(x^2+y^2-5-2xy+4\right)\)
\(=\left(\left(x+y\right)^2-9\right)\left(\left(x-y\right)^2-1\right)=\left(x+y-3\right)\left(x+y+3\right)\left(x-y+1\right)\left(x-y-1\right)\)

(x^2+y^2-5)^2 - 4x^2y^2 - 16xy -16
= (x^2 + y^2 - 5)^2 - (4x^2y^2 + 16xy + 16)
= (x^2 + y^2 - 5)^2 - (2xy + 4)^2
= (x^2 + y^2 - 5 - 2xy - 4)(x^2 + y^2 - 5 + 2xy + 4)
= [(x - y)^2 - 9][(x + y)^2 - 1]
=(x-y-3)(x-y+3)(x+y-1)(x+y+1)

(x²+y²−5)²−4x²y²−16xy−16

= (x²+y²−5)²− (4x²y²+16xy+16)

= (x²+y²−5)²− (2²x²y²+16xy+4²)

=(x²+y²−5)²− ((2xy)²+16xy+4²)

=(x²+y²−5)²− (2xy+4)²

= (x²+y²−5+2xy+4)( x²+y²−5−2xy−4)

= (( x+y)²−1)((x−y)²−9)

= (x+y+1)(x+y−1)(x−y+3)(x−y−3)

Viết liền thế ai mà đọc được

câu a nek

(4x^2 -7x-50)^2 -4x^2 (4x^2+14x+49/4)

= (4x^2 -7x-50)^2 -(2x)^2 (2x+7/2)^2

= (4x^2 -7x-50)^2 - (4x^2+7x)^2

= (4x^2 -7x-50 +4x^2+7x) (4x^2 -7x-50-4x^2-7x)

= (8x^2-50) (-14x-50)

=2(4x^2-25)* (-2)(7x+25)

=-4 (2x-5)(2x+5)(7x+25)

\(1,=x\left(x^2-2x+1-y^2\right)=x\left[\left(x-1\right)^2-y^2\right]=x\left(x-y-1\right)\left(x+y-1\right)\\ 2,=\left(x+y\right)^3\\ 3,=\left(2y-z\right)\left(4x+7y\right)\\ 4,=\left(x+2\right)^2\\ 5,Sửa:x\left(x-2\right)-x+2=0\\ \Leftrightarrow\left(x-2\right)\left(x-1\right)=0\Leftrightarrow\left[{}\begin{matrix}x=1\\x=2\end{matrix}\right.\)

Đề sai rồi bạn

x⁶+3x⁴y²-8x³y³+3x²y⁴+y⁶= x⁶+3x⁴y²+3x²y⁴+y⁶-8x³y³=(x²+y²)³-(2xy)³

= (x²+y²-2xy)[(x²+y²)²+2xy(x²+y²)+(2xy)²]= (x-y)²(x⁴+6x²y²+y⁴+2x³y+2xy³)

(x²+y²-5)²-4x²y²-16xy-16=(x²+y²-5)²-(4x²y²+16xy+16)=(x²+y²-5)²-(2xy+4)²

=(x²+y²-5+2xy+4)(x²+y²-5-2xy-4)=(x²+2xy+y²-1)(x²-2xy+y²-9)=[(x+y)²-1][(x-y)²-3²]=(x+y-1)(x+y+1)(x-y-3)(x-y+3)

x⁴+324=x⁴+36x²+324-36x²=(x²+18)²-(6x)²=(x²+18-6x)(x²+18+6x)