a ) x - 5 \(\in\)B ( 6 )

\(\Rightarrow\)x - 5 \(\in\){ 0 ; 6 ; 12 ; 18 ; 24 ; 30 ; 36 ; 42 ; 48 ; ..... }

\(\Rightarrow\)x \(\in\){ 5 ; 11 ; 17 ; 23 ; 29 ; 35 ; 41 ; 47 ; 53 ; .... }

b ) x - 1 \(⋮\)4

\(\Rightarrow\)x - 1 \(\in\)B ( 4 )

\(\Rightarrow\)x - 1 \(\in\){ 0 ; 4 ; 8 ; 12 ; 16 ; 20 ; 24 ; 28 ; 32 ; 36 ; 40 ; ..... }

\(\Rightarrow\)x \(\in\){ 1 ; 5 ; 9 ; 13 ; 17 ; 21 ; 25 ; 29 ; 33 ; 37 ; 41 ; .... }

Thanks bạn nhìu nhé ~!

a, 10 + 2x = 45 ÷ 43

10 + 2x = 45/43

2x = 45/43 - 10

2x = -385/43

x = -385/43 ÷ 2

x = -385/86

b, 2x - 138 = 23.32

2x - 138 = 736

2x = 736 + 138

2x = 874

x = 874 ÷ 2

x = 437

c, 231 - ( x - 6 ) = 1339 ÷ 13

231 - ( x - 6 ) = 103

x - 6 = 231 - 103

x - 6 = 128

x = 128 + 6

x = 134

d, x + 5.2 - ( 32 + 16.3 ÷ 6 - 15 ) = 0

x + 10 - 25 = 0

x + 10 = 0 + 25

x + 10 = 25

x = 25 - 10

x = 15

a) 10 + 2 . x = 45 : 43

            2 . x = 45/43 -10

            2 . x = -385/43

                 x = -385/43 : 2

                 x = -385/86

b) 2 . x - 138 = 23 . 32

    2 . x - 138 = 736

             2 . x = 736+138

             2 . x = 874

                  x = 874 : 2

                  x = 437

c) 231 - (x -6) = 1339 : 13

    231 - (x -6) = 103

               x - 6 = 231 -103

               x - 6 = 98

                    x = 98 +6

                    x = 104

d) x + 5 . 2 - (32 +16 . 3 : 6 - 15) = 0

        x + 5 . 2 - (32 + 48 : 6 - 15) = 0

               x + 5 . 2 - (32 + 8 - 15) = 0

                               x + 5 . 2 - 25 = 0

                               x + 10 - 25 = 0

                                      x + 10 = 0 + 25

                                      x + 10 = 25

                                              x = 25 - 10

                                              x = 15

TL
 

= 3  ( tính phát ra luôn là cách tính nha )

HT

13/32 + 3/21 + 1/4 + 19/32 + 18/21 + 45/60 

= ( 13/32 + 19/32 ) + ( 3/21 + 18/21 ) + ( 1/4+ 45/60 ) 

= 32/32 + 21/21  + (1/4+3/4)

= 1+1+4/4

=1+1+1

=3 

Chúc bạn học tốt :333

À MINH TRẢ LỜI LẠI

= (13/32+19/32)+(3/21+18/21)+(1/4+54/60)

= 1 + 1 + (1/4 + 3/4)

= 1+1+1

= 3

MONG BẠN K CHO MIK

KO CẦN ĐỌC TIẾP NX

đag thi à?

=>x-3=16

hay x=19

\(2^2.\left(x-3\right)=2^6\\ \Rightarrow x-3=16\\ \Rightarrow x=19\)

2²x(x-3)=2⁶

x-3=2⁶:2²

x-3=2^6-2

x-3=2⁴

x-3=16

x=16+3

x=19

`@` `\text {Ans}`

`\downarrow`

`j)`

\(x^{17}\div x^{12}=x^{17-12}=x^5\)

`k)`

\(x^8\div x^5=x^{8-5}=x^3\)

`r)`

\(a^5\div a^5=a^{5-5}=a^0=1\)

`l)`

\(x^4\div x=x^{4-1}=x^3\)

`m)`

\(x^7\div x^6=x^{7-6}=x\)

`n)`

\(x^9\div x^9=x^{9-9}=x^0=1\)

`o)`

\(a^{12}\div a^5=a^{12-5}=a^7\)

`p)`

\(a^8\div a^6=a^{8-6}=a^2\)

`q)`

\(a^{10}\div a^7=a^{10-7}=a^3\)

`r(2),`

\(1024\div4=2^{10}\div2^2=2^8\)

`t)`

\(512\div2^3=2^9\div2^3=2^6\)

\(1,2\sqrt{27}+5\sqrt{12}-3\sqrt{48}\\ =2.3\sqrt{3}+5.2\sqrt{3}-3.4\sqrt{3}\\ =6\sqrt{3}+10\sqrt{3}-12\sqrt{3}\\ =4\sqrt{3}\)

\(2,\sqrt{147}+\sqrt{75}-4\sqrt{27}\\ =7\sqrt{3}+5\sqrt{3}-4.3\sqrt{3}\\ =7\sqrt{3}+5\sqrt{3}-12\sqrt{3}\\ =\sqrt{3}\left(7+5-12\right)\\ =0\)

\(3,3\sqrt{2}\left(4-\sqrt{2}\right)+3\left(1-2\sqrt{2}\right)^2\\ =3\sqrt{2}.\left(4-\sqrt{2}\right)+3\left(1-4\sqrt{2}+8\right)\\ =12\sqrt{2}-6+3-12\sqrt{2}+24\\ =21\)

\(4,2\sqrt{5}-\sqrt{125}-\sqrt{80}+\sqrt{605}\\ =2\sqrt{5}-5\sqrt{5}-4\sqrt{5}+11\sqrt{5}\\ =\sqrt{5}\left(2-5-4+11\right)\\ =4\sqrt{5}\)

1: =6căn 3+10căn 3-12căn 3=4căn 3

2: =7căn 3+5căn 3-12căn 3=0

3: =12căn 2-6+3(9-4căn 2)

=12căn 2-6+27-12căn 2=21

4: =2căn 5-5căn 5+4căn 5+9 căn 5

=10căn 5

1. Tìm x

a) 1+2+3+...+x = 210

=> \(\frac{x\left(x+1\right)}{2}=210\)

=> x = 20

b) \(32.3^x=9.3^{10}+5.27^3\)

=>\(32.3^x=9.3^{10}+5.3^9\)(\(27^3=\left(3^3\right)^3=3^9\))

=>\(32.3^x=9.3.3^9+5.3^9\)

=>\(32.3^x=3^9\left(9.3+5\right)\)

=>\(32.3^x=3^9.32\)

=>x = 9

2.

Ta có 2A = 3A - A

=> 2A = \(3\left(1+3+3^2+3^3+....+3^{10}\right)\)\(-\)\(1-3-3^2-3^3-....-3^{10}\)

=> 2A = \(3+3^2+3^3+.....+3^{11}-\)\(1-3-3^2-3^3-...-3^{10}\)

=> 2A = \(3^{11}-1\)

=> 2A+1 = \(3^{11}-1+1\)=\(3^{11}\)

=> n = 11

Ta có : a)1 + 2 + 3 + ... + x = 210

=> \(\frac{x\left(x+1\right)}{2}=210\)

=> x(x + 1) = 420

=> x(x + 1) = 20.21

=> x = 20

1/ 

a) \(1+2+3+...+x=210\)

\(\Rightarrow\frac{x.\left(x+1\right)}{2}=210\)

\(\Rightarrow x.\left(x+1\right)=210.2=420\)

\(\Rightarrow x^2+x=420\)

\(\Rightarrow x^2+x=400+20=20^2+20\Leftrightarrow x=20\)

b) \(32.3^x=9.3^{10}+5.27^3\)

\(\Rightarrow32.3^x=629856\)

\(\Rightarrow3^x=629856:32=19683=3^9\)

\(\Rightarrow x=9\)

2/

\(A=1+3+3^2+3^3+...+3^{10}\)

\(\Rightarrow A=3^0+3^1+3^2+3^3+...+3^{10}\)

\(\Rightarrow A=\frac{3^{10+1}-1}{3-1}=88573\)

Tìm n:

\(2.A+1=3^n\Rightarrow2.88573+1=3^n\)

\(\Rightarrow177147=3^n\Leftrightarrow3^{11}=3^n\Leftrightarrow n=11\)

4 cách điều chế NaOH :

Pt : \(2Na+2H_2O\rightarrow2NaOH+H_2\)

       \(Na_2O+H_2O\rightarrow2NaOH\)

        \(2NaCl+H_2O\xrightarrow[có.màng.ngăn]{điện.phân}2NaOH+H_2+Cl_2\)

         \(Ba\left(OH\right)_2+Na_2SO_4\rightarrow BaSO_4+2NaOH\)

  Chúc bạn học tốt

Mik viết PTHH nhé:

\(-2NaCl+2H_2O\xrightarrow[có.màng.ngăn]{điện.phân}Cl_2+H_2+2NaOH\)

\(-2Na+2H_2O--->2NaOH+H_2\)

\(-Na_2O+H_2O--->2NaOH\)

\(-Ca\left(OH\right)_2+2NaHCO_3--->CaCO_3\downarrow+2NaOH+H_2O\)