Xúc xích bonitanwg 88%cặc

a. \(4ab.\frac{1}{3}ac-2aca-9a^2.\frac{1}{2}b+10a^2.\frac{1}{5}c+a^2b-a^2bc\)

\(=\left(4.\frac{1}{3}\right)\left(a.a\right).bc-2a^2c-\left(9.\frac{1}{2}\right)a^2b+\left(10.\frac{1}{5}\right)a^2c+a^2b-a^2bc\)

\(=\frac{4}{3}a^2bc-2a^2c-\frac{9}{2}a^2b+2a^2c+a^2b-a^2bc\)

\(=\left(\frac{4}{3}a^2bc-a^2bc\right)+\left(-2a^2c+2a^2c\right)+\left(-\frac{9}{2}a^2b+a^2b\right)\)

\(=\frac{1}{3}a^2bc+\left(-\frac{7}{2}a^2b\right)\)

b. \(2ab-2bc.c+ab+\frac{1}{2}c^2b-4cb^2+2bcb\)

\(=2ab-2bc^2+ab+\frac{1}{2}c^2b-4cb^2+2b^2c\)

\(=\left(2ab+ab\right)+\left(-2bc^2+\frac{1}{2}c^2b\right)+\left(-4cb^2+2b^2c\right)\)

\(=3ab+-\frac{3}{2}bc^2+-2b^2c\)

\(=b\left(3a-\frac{3}{2}c^2-2bc\right)\)

=>3(x-2)=4(x+5)

=>4x+20=3x-6

=>x=-26

\(\dfrac{x-2}{4}=\dfrac{5+x}{3}\\ =>3\times\left(x-2\right)=4\times\left(5+x\right)\\ =>3x-6=20+4x\\ =>3x-4x=20+6\\ =>-x=26\\ =>x=-26\)

`(x-2):4 = (5+x) :3`

`(x-2)*3 = 4*(5+x)`

`3x -6 = 20 +4x`

`3x -4x = 20 +6`

`-x =26`

`x=-26`

a: =>x=5/4-5/14=25/28

b: =>x=6/7:2/3=6/7*3/2=18/14=9/7

a) \(\dfrac{35}{28}-x=\dfrac{5}{14}\)

\(\dfrac{35}{28}-x=\dfrac{10}{28}\)

\(x=\dfrac{35}{28}-\dfrac{10}{28}\)

\(x=\dfrac{25}{28}\)

b) \(\dfrac{6}{7}:x=\dfrac{2}{3}\)

\(x=\dfrac{6}{7}:\dfrac{2}{3}=\dfrac{6}{7}\times\dfrac{3}{2}\)

\(x=\dfrac{9}{7}\)

ĐK: \(x>0\)

PT trở thành:

\(x+2=3\sqrt{x}\\ \Leftrightarrow x-3\sqrt{x}+2=0\\ \Leftrightarrow x-2\sqrt{x}-\sqrt{x}+2=0\\ \Leftrightarrow\sqrt{x}\left(\sqrt{x}-2\right)-\left(\sqrt{x}-2\right)=0\\ \Leftrightarrow\left(\sqrt{x}-2\right)\left(\sqrt{x}-1\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}\sqrt{x}-2=0\\\sqrt{x}-1=0\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=4\left(tm\right)\\x=1\left(tm\right)\end{matrix}\right.\)

Vậy PT có nghiệm `x=4` hoặc `x=1`

\(\dfrac{x+2}{\sqrt{x}}=3\) (ĐKXĐ: x > 0)

\(\Leftrightarrow x+2=3\sqrt{x}\)

\(\Leftrightarrow x-3\sqrt{x} +2=0\)

\(\Leftrightarrow x-\sqrt{x}-2\sqrt{x}+2=0\)

\(\Leftrightarrow\sqrt{x}\left(\sqrt{x}-1\right)-2\left(\sqrt{x}-1\right)=0\)

\(\Leftrightarrow\left(\sqrt{x}-2\right)\left(\sqrt{x}-1\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}\sqrt{x}-2=0\\\sqrt{x}-1=0\end{matrix}\right.\)            \(\Leftrightarrow\left[{}\begin{matrix}x=4\\x=1\end{matrix}\right.\) (tm)

#Ayumu

x+2√x=3

x+2=3√x

⇔x−3√x+2=0

⇔x−2√x−√x+2=0

⇔√x(√x−2)−(√x−2)=0

⇔(√x−2)(√x−1)=0

⇔[√x−2=0

    [√x−1=0

⇔[x=4(tm)

    [x=1(tm)

mình ko ngoăcj được hai dòng mong bn thông cảm

2*AB-3MN-K+P^2=C^2

=>2*(-20)x^4y^4-3*2x^4y^4+25x^4y^4-9x^4y^4=K

=>K=-30x^4y^4