\(\frac{56-x}{34}=\frac{144}{96}=\frac{3}{2}\)

\(\Rightarrow\left(56-x\right)2=34\cdot3=102\)

\(\Rightarrow56-x=102\div2\)

\(\Rightarrow56-x=51\)

\(\Rightarrow x=56-51\)

\(\Rightarrow x=5\)

\(56-\frac{x}{34}=\frac{144}{96}\)

\(\Rightarrow\frac{x}{34}=56-\frac{144}{96}\)

\(\Rightarrow\frac{x}{34}=\frac{109}{2}\)

\(\Rightarrow2x=109\cdot34=3706\)

\(\Rightarrow x=3706\div2\)

\(\Rightarrow x=1853\)

\(56-\frac{x}{34}=\frac{144}{96}=\frac{3}{2}\)

\(\Rightarrow\frac{x}{34}=56-\frac{3}{2}\)

\(\Rightarrow\frac{x}{34}=\frac{109}{2}\)

\(\Rightarrow2x=109\cdot34=3706\)

\(\Rightarrow x=3706\div2=1853\)

giả giúp mình nhé

Sửa đề xí nha:

\(56-\frac{x}{34}=\frac{144}{96}\)

\(\Rightarrow\frac{x}{34}=56-\frac{144}{96}\)

\(\Rightarrow\frac{x}{34}=\frac{109}{2}\)

\(\Rightarrow\frac{x}{34}=\frac{3706}{34}\Rightarrow x=3706\)

◥ὦɧ◤ŤŔầŃ VăŃ ĤùŃĞ™​ sai đáp số rồi kìa

\(56-\frac{x}{34}=\frac{144}{96}\)

\(\Rightarrow\frac{x}{34}=56-\frac{144}{96}\)

\(\Rightarrow\frac{x}{34}=56-\frac{3}{2}\)

\(\Rightarrow\frac{x}{34}=\frac{56\cdot2-3}{2}\)

\(\Rightarrow\frac{x}{34}=\frac{109}{2}\)

\(\Rightarrow2x=109\cdot34\)

\(\Rightarrow2x=3706\)

\(\Rightarrow x=3706:2=1853\)

Vậy x = 1853

1/109

2/1.6029411764705882352941176470588

1/ 109

1/109 nha bạn

Ta có : 

    56-x/34=144/96

=>     x/34=56-144/96

=>    x/34=109/2

Áp dụng tích chất 2 phân số bằng nhau thì 2 tích chéo bằng nhau ta có:

   x/34=109/2 <=> x.2=34.109

                     => x.2 =3706

                    => x     =3706:2

                   => x      =1853

Vậy x=1853

x là 1853

         x/34 = 56 - 144/96

         x/34 = 109/2

         x/34 = 1853/34

=> x = 1853

X/34=56-144/96

x/34=109/2

x=109x34:2=1853

\(\frac{56-x}{34}=\frac{144}{96}\)

\(=\frac{56-x}{34}=\frac{3}{2}\)

\(=\frac{56-x}{34}=\frac{51}{34}\)

\(\Rightarrow56-x=51\)

\(=-x=51-56\)

\(\Rightarrow x=5\)

x bang 2

56-x.96=34.144

 x= 56 *96 / 34 * 144

x=5376/4896

5 nha e

giúp mik k lun nhé cả cách làm và đáp số

a) \(96-7\left(x+1\right)=14^4:14^3\)

\(\Rightarrow96-7\left(x+1\right)=14^{4-3}\)

\(\Rightarrow96-7\left(x+1\right)=14\)

\(\Rightarrow7\left(x+1\right)=96-14\)

\(\Rightarrow7\left(x+1\right)=82\)

\(\Rightarrow x+1=\dfrac{82}{7}\)

\(\Rightarrow x=\dfrac{82}{7}-1\)

\(\Rightarrow x=\dfrac{75}{7}\)

b) \(\left(5x+3^4\right)\cdot2^4=2^6\cdot7^2\)

\(\Rightarrow5x\cdot2^4+3^4\cdot2^4=2^6\cdot7^2\)

\(\Rightarrow5x\cdot2^4+6^4=\left(2^3\cdot7\right)^2\)

\(\Rightarrow80x+1296=3136\)

\(\Rightarrow80x=1840\)

\(\Rightarrow x=\dfrac{1840}{80}\)

\(\Rightarrow x=23\)

a: =>96-7(x+1)=14

=>7(x+1)=82

=>x+1=82/7

=>x=75/7

b =>5x+81=2^2*7^2=196

=>5x=115

=>x=23

a) \(96-7\left(x+1\right)=14^4:14^3\\ \Leftrightarrow96-7\left(x+1\right)=14\\ \Leftrightarrow7\left(x+1\right)=82\\ \Leftrightarrow x+1=\dfrac{82}{7}\\ \Leftrightarrow x=\dfrac{75}{7}\)

b) \(\left(5x+3^4\right)\cdot2^4=2^6\cdot7^2\\\Leftrightarrow5x+81=196\\ \Leftrightarrow5x=115\\ \Leftrightarrow x=23 \)

2) Ta có: \(\dfrac{59-x}{19}+\dfrac{58-x}{18}=\dfrac{57-x}{17}+\dfrac{56-x}{16}\)

\(\Leftrightarrow\dfrac{59-x}{19}-1+\dfrac{58-x}{18}-1=\dfrac{57-x}{17}-1=\dfrac{56-x}{16}-1\)

\(\Leftrightarrow\dfrac{40-x}{19}+\dfrac{40-x}{18}-\dfrac{40-x}{17}-\dfrac{40-x}{16}=0\)

\(\Leftrightarrow\left(40-x\right)\left(\dfrac{1}{19}+\dfrac{1}{18}-\dfrac{1}{17}-\dfrac{1}{16}\right)=0\)

mà \(\dfrac{1}{19}+\dfrac{1}{18}-\dfrac{1}{17}-\dfrac{1}{16}\ne0\)

nên 40-x=0

hay x=40

Vậy: x=40

cho mk hỏi 4x-  5/8 hay (4x-5)/8   =6-x/2 phải ko