Question

1.cho M =4x-5/8 +2;=6-x/2 với x=? thì giá trị của M=2/3 giá trị N

2.tìm x để ?

59-x/19 +58-x/18 = 57-x/17+ 56-x/16

Answer 1

2) Ta có: \(\dfrac{59-x}{19}+\dfrac{58-x}{18}=\dfrac{57-x}{17}+\dfrac{56-x}{16}\)

\(\Leftrightarrow\dfrac{59-x}{19}-1+\dfrac{58-x}{18}-1=\dfrac{57-x}{17}-1=\dfrac{56-x}{16}-1\)

\(\Leftrightarrow\dfrac{40-x}{19}+\dfrac{40-x}{18}-\dfrac{40-x}{17}-\dfrac{40-x}{16}=0\)

\(\Leftrightarrow\left(40-x\right)\left(\dfrac{1}{19}+\dfrac{1}{18}-\dfrac{1}{17}-\dfrac{1}{16}\right)=0\)

mà \(\dfrac{1}{19}+\dfrac{1}{18}-\dfrac{1}{17}-\dfrac{1}{16}\ne0\)

nên 40-x=0

hay x=40

Vậy: x=40

Answer 2

cho mk hỏi 4x-  5/8 hay (4x-5)/8   =6-x/2 phải ko