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50%*x+3/4*x+0,25*x+1/2*x=2015

=1/2*x+3/4*x+1/4*x+1/2*x=2015

=(1/2+3/4+1/4+1/2)*x       =2015

=           2*x                       =2015

=              x                       =2015:2

                x                       =  1007,5.

TÌM X:

a) 2x - 3 = \(\frac{1}{2}\)

2x = \(\frac{1}{2}+3\)

2x = \(\frac{7}{2}\)

x = 2 : \(\frac{7}{2}\)

x = 2 . \(\frac{2}{7}\)

x = \(\frac{4}{7}\)

b) /x+1/ = 0.25

/x+1/ = \(\frac{1}{4}\)

\(\orbr{\begin{cases}x+1=\frac{1}{4}\\x+1=-\frac{1}{4}\end{cases}}\)

\(\orbr{\begin{cases}x=\frac{1}{4}-1\\x=-\frac{1}{4}-1\end{cases}}\)

\(\orbr{\begin{cases}x=-\frac{3}{4}\\x=-\frac{5}{4}\end{cases}}\)

c) 32 : 2x = 2

\(2x=32:2\)

\(2x=16\)

\(x=16:2\)

\(x=8\)

~GOOD STUDY~

a) 2x-3=1/2

=> 2x=1/2+3

=> 2x=7/2

=> x=7/2:2

=> x=7/4

b) |x+1|=0.25

=> \(\orbr{\begin{cases}x+1=0,25\\x+1=-0,25\end{cases}}\)=>\(\orbr{\begin{cases}x=0,25-1\\x=-0,25-1\end{cases}}\)=>\(\orbr{\begin{cases}x=-0,75\\x=-1,25\end{cases}}\)

\(=\left(\frac{75}{100}+\frac{65}{100}+\frac{1}{4}+\frac{35}{100}\right)\left(\frac{1}{4}.2+\frac{25}{100}.3+\frac{25}{100}.5\right)\)

\(=\left(\frac{3}{4}+\frac{13}{20}+\frac{1}{4}+\frac{7}{20}\right)\left(\frac{2}{4}+\frac{3}{4}+\frac{5}{4}\right)\)

\(=\left(1+1\right).\frac{10}{4}\)

\(=2.\frac{5}{2}\)

\(=5\)

0,25 X x = 0,75+0,25

0,25 X x = 1

            x = 1:0,25

            x = 4

x : 1.25 =1/4 - 0,25

x : 1,25 =  0,75

        x   = 0,75 x 1,25

        x   = 0,9375

0,25 X x = 0,75+0,25

0,25 X x = 1

            x = 1:0,25

            x = 4

0,25 x x = 0,75+0,25

0,25x x = 1

          x = 1 : 0,25

          x = 4

x : 1,25 =\(\frac{1}{4}\) -  0,25

x : 1,25 = \(\frac{1}{4}-\frac{25}{100}\)

x : 1,25 = \(\frac{1}{4}-\frac{1}{4}\)

x : 1,25 = 0

          x = 0 x 1,25

          x = 0

0,25 x x = 0,75+0,25

0,25x x = 1

          x = 1 : 0,25

          x = 4

a) \(0,25\times x=0,75+0,25\)

     \(0,25\times x=1\)

                    \(x=1:0,25\)

                     \(x=4\)

Vậy \(x=4\)

b) \(x:1,25=\frac{1}{4}-0,25\)

\(x:1,25=0,25-0,25\)

\(x:1,25=0\)

\(x=0\times1,25\)

 \(x=0\)

Vậy \(x=0\)

c) \(0,25\times x=0,75+0,25\)

      \(0,25\times x=1\)

                      \(x=1:0,25\)

                       \(x=4\)

  Vậy \(x=4\)

Chúc bạn học tốt !!!

870 - x : 11 x 87 = 261
         x : 11 x 87 = 870 - 261
         x : 11 x 87 =      609
         x : 11         = 609 : 87
         x : 11         =       7
         x                = 7 x 11
         x                =    77
x : 0.25 x 2.3 = 6.9
x : 0.25          = 6.9 : 2.3
x : 0.25          =      3
x                    = 3 x 0.25
x                    =     0.75
2 x (y + y) = 8.16
      y + y   = 8.16 : 2
      y x 2   =     4.08
      y         = 4.08 : 2
      y         =     2.04
y x 1.5 + y + y x 7.5 = 59.8
y x (1.5 + 1 + 7.5)    = 59.8
y x        10                = 59.8
y                               = 59.8 : 10
y                               =      5.98

m : 1/6 + m : 0.25 = 152
m : 1/6 + m : 1/4   = 152 
m x 6 + m x 4       = 152
m x (6 + 4)            = 152
m x     10               = 152
m                           = 152 : 10
m                           =       15.2

m : 1/3 + m : 0.25 = 1.4
m : 1/3 + m : 1/4   = 1.4
m x 3 + m x 4        = 1.4
m x (3 + 4)             = 1.4
m x     7                 = 1.4
m                           = 1.4 : 7
m                           = 0.2   

\(\dfrac{3}{2}x+\dfrac{3}{7}=-\dfrac{4}{5}\)

\(\Leftrightarrow\dfrac{3}{2}x=-\dfrac{43}{35}\)

\(\Leftrightarrow x=-\dfrac{86}{105}\)

Vậy \(x=-\dfrac{86}{105}\)

\(-\dfrac{11}{12}x+0,25=\dfrac{5}{6}\)

\(\Leftrightarrow-\dfrac{11}{12}x+\dfrac{1}{4}=\dfrac{5}{6}\)

\(\Leftrightarrow-\dfrac{11}{12}x=\dfrac{7}{12}\)

\(\Leftrightarrow x=-\dfrac{7}{11}\)

Vậy \(x=-\dfrac{7}{11}\)

\(\left(x-2\right)^2=1\)

\(\Leftrightarrow\left(x-2\right)^2-1=0\)

\(\Leftrightarrow\left(x-2-1\right)\left(x-2+1\right)=0\)

\(\Leftrightarrow\left(x-3\right)\left(x-1\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x-3=0\\x-1=0\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}x=3\\x=1\end{matrix}\right.\)

Vậy x = {3; 1}\(\left(2x-1\right)^3=-8\)

\(\Leftrightarrow2x-1=-2\)

\(\Leftrightarrow2x=-1\)

\(\Leftrightarrow x=-\dfrac{1}{2}\)

Vậy \(x=-\dfrac{1}{2}\)

       (x - 2)² = 1

<=>\(\left[{}\begin{matrix}x-2=1\\x-2=-1\end{matrix}\right.< =>\left[{}\begin{matrix}x=3\\x=1\end{matrix}\right.\)

Vậy x = 3; 1

(2x - 1)³ = -8

<=> 2x - 1 = -2

<=> 2x = -1

<=> x = \(\dfrac{-1}{2}\)

Vậy x = \(\dfrac{-1}{2}\)

\(|\) 2,5 - x\(|\) = 1,3

1,6- \(|\)x - 0,2 \(|\)= 0

13^x = 169

\(\dfrac{-2}{x}\)=\(\dfrac{-x}{8\dfrac{ }{25}}\)

\(\dfrac{x}{-15}\)=\(\dfrac{-60}{x}\)

\(|\)x\(|\)+0,573=2

b) Ta có: \(3+\left(x-5\right)=2\left(3x-2\right)\)

\(\Leftrightarrow3+x-5=6x-4\)

\(\Leftrightarrow x-2-6x+4=0\)

\(\Leftrightarrow-5x+2=0\)

\(\Leftrightarrow-5x=-2\)

\(\Leftrightarrow x=\dfrac{2}{5}\)

Vậy: \(S=\left\{\dfrac{2}{5}\right\}\)

c) Ta có: \(2\left(x-0.5\right)+3=0.25\left(4x-1\right)\)

\(\Leftrightarrow2x-1+3=x-\dfrac{1}{4}\)

\(\Leftrightarrow2x+2-x+\dfrac{1}{4}=0\)

\(\Leftrightarrow x+\dfrac{9}{4}=0\)

\(\Leftrightarrow x=-\dfrac{9}{4}\)

Vậy: \(S=\left\{-\dfrac{9}{4}\right\}\)

d) Ta có: \(2\left(x-\dfrac{1}{4}\right)-4=-6\left(-\dfrac{1}{3}x+0.5\right)+2\)

\(\Leftrightarrow2x-\dfrac{1}{2}-4=2x-3+2\)

\(\Leftrightarrow2x-\dfrac{9}{2}=2x-1\)

\(\Leftrightarrow2x-2x=-1+\dfrac{9}{2}\)

\(\Leftrightarrow0x=\dfrac{7}{2}\)(vô lý)

Vậy: \(S=\varnothing\)

b. 

→ -2 + x = 6x - 4

→ -2 + 4 = 6x - x

→ 2 = 5x

→ x = \(\dfrac{2}{5}\) 

Vậy, phương trình có tập nghiệm S = {\(\dfrac{2}{5}\)}

Ta có :3|1/4 - x²| - 0,25 = |x² - 1/4| + 3/8

=> 3|1/4 - x²| - |x² - 1/4| = 3/8 + 0,25

<=> 3|1/4 - x²| - |1/4 - x²| = 5/8

=> 2|1/4 - x²| = 5/8

=> |1/4 - x²| = 5/16

=> \(\orbr{\begin{cases}\frac{1}{4}-x^2=\frac{5}{16}\\\frac{1}{4}-x^2=-\frac{5}{16}\end{cases}}\Rightarrow\orbr{\begin{cases}x^2=\frac{-1}{16}\left(\text{loại}\right)\\x^2=\frac{9}{16}\end{cases}}\Rightarrow x^2=\frac{9}{16}\Rightarrow x^2=\left(\frac{3}{4}\right)^2\Rightarrow x=\pm\frac{3}{4}\)

1) Ta có: \(\left(-\dfrac{2}{3}\right)^2\cdot\dfrac{-9}{8}-25\%\cdot\dfrac{-16}{5}\)

\(=\dfrac{4}{9}\cdot\dfrac{-9}{8}-\dfrac{1}{4}\cdot\dfrac{-16}{5}\)

\(=\dfrac{-1}{2}+\dfrac{4}{5}\)

\(=\dfrac{-5}{10}+\dfrac{8}{10}=\dfrac{3}{10}\)

2) Ta có: \(-1\dfrac{2}{5}\cdot75\%+\dfrac{-7}{5}\cdot25\%\)

\(=\dfrac{-7}{5}\cdot\dfrac{3}{4}+\dfrac{-7}{5}\cdot\dfrac{1}{4}\)

\(=\dfrac{-7}{5}\left(\dfrac{3}{4}+\dfrac{1}{4}\right)=-\dfrac{7}{5}\)

3) Ta có: \(-2\dfrac{3}{7}\cdot\left(-125\%\right)+\dfrac{-17}{7}\cdot25\%\)

\(=\dfrac{-17}{7}\cdot\dfrac{-5}{4}+\dfrac{-17}{7}\cdot\dfrac{1}{4}\)

\(=\dfrac{-17}{7}\cdot\left(\dfrac{-5}{4}+\dfrac{1}{4}\right)\)

\(=\dfrac{17}{7}\)

4) Ta có: \(\left(-2\right)^3\cdot\left(\dfrac{3}{4}\cdot0.25\right):\left(2\dfrac{1}{4}-1\dfrac{1}{6}\right)\)

\(=\left(-8\right)\cdot\left(\dfrac{3}{4}\cdot\dfrac{1}{4}\right):\left(\dfrac{9}{4}-\dfrac{7}{6}\right)\)

\(=\left(-8\right)\cdot\dfrac{3}{16}:\dfrac{54-28}{24}\)

\(=\dfrac{-3}{2}\cdot\dfrac{24}{26}\)

\(=\dfrac{-72}{52}=\dfrac{-18}{13}\)