I/ 1C 2C 3B 4D 5d

II/ 1c 2a 3d 4b

I:

1.D    2.D  3.B   4.D   5.D

II:

1.C   2.C   3.D   4.A

C

c

\(\Rightarrow x=\dfrac{5}{12}-\dfrac{1}{4}=\dfrac{1}{6}\)

\(0,25+x=\dfrac{5}{12}\Rightarrow\dfrac{1}{4}+x=\dfrac{5}{12}\)

\(\Rightarrow x=\dfrac{5}{12}-\dfrac{1}{4}=\dfrac{5-1.3}{12}=\dfrac{2}{12}=\dfrac{1}{6}\)

x=1/6

\(a,\left(2x-1\right)^2-25=0.\\ \Leftrightarrow\left(2x-1\right)^2=25.\\ \Leftrightarrow\left[{}\begin{matrix}2x-1=5.\\2x-1=-5.\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=3.\\x=-2.\end{matrix}\right.\) 

\(b,\left(x-3\right)\left(5-2x\right)=0.\\ \Leftrightarrow\left[{}\begin{matrix}x-3=0.\\5-2x=0.\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=3.\\x=\dfrac{5}{2}.\end{matrix}\right.\)

\(c,\dfrac{x+1}{x-2}+\dfrac{x-1}{x+2}-\dfrac{2\left(x^2+2\right)}{x^2-4}=0.\)

\(\left(x\ne\pm2\right).\)

\(\Leftrightarrow\dfrac{\left(x+1\right)\left(x+2\right)+\left(x-1\right)\left(x-2\right)-2x^2-4}{\left(x-2\right)\left(x+2\right)}=0.\)

\(\Rightarrow\left(x+1\right)\left(x+2\right)+\left(x-1\right)\left(x-2\right)-2x^2-4=0.\)

\(\Leftrightarrow x^2+3x+2+x^2-3x+2-2x^2-4=0.\)

\(\Leftrightarrow0=0\) (luôn đúng).

\(\dfrac{6}{5}\)

6/5

6/5

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hép cái j đây

26 different

27 pronunciation

28 comfortable

29 performers

30 windy

31 unhealthy

32 childhood

33 

34 flight

35 suddenly

IV.

26. different

27. pronunciation

28. comfortable

29. performers

30. windy

31. unhealthy

32. childhood

33. successfully

34. flights

35. suddenly

V.

36. am looking

37. will move

38. is going to rain

39. Does the film begin

40. will telephone

41. produced

42. sat

43. is becoming

44 + 45. knows / hasn't learned