a: \(=167\cdot\dfrac{67}{1000}+167\cdot\dfrac{33}{1000}=167\cdot\dfrac{1}{10}=\dfrac{167}{10}\)

\(x+x+x\times1+x\times6=120\\ x\times\left(1+1+1+6\right)=120\\ x\times9=120\\ x=\dfrac{120}{9}\\ x=\dfrac{40}{3}\)

\(x+x+x\text{×}1+x\text{×}6=120\)

\(x\text{×}\left(1+1+1\right)+x\text{×}6=120\)

\(x\text{×}3+x\text{×}6=120\)

\(x\text{×}\left(3+6\right)=120\)

\(x\text{×}9=120\)

\(x=\dfrac{120}{9}\)

x+x+x×1+x×6=120x×(1+1+1+6)=120x×9=120x=1209x=403

x-3/-9 = -4/x-3

(x-3)^2=-9.-4=36

=>TH1 x-3= 6

   TH2  x-3 = -6

=> TH1: X= 9

     TH2: X=-3

=>(x-3)^2=36

=>x-3=6 hoặc x-3=-6

=>x=-3; x=9

`x/2+x+x/3+x+x+x/4=5 3/4`

`=>3x+x/2+x/3+x/4=23/4`

`=>49/12x=23/4`

`=>x=69/49`

Vậy `x=69/49`

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100000

=4,3(4,6+3.5+2,9-1)

=4,3*10=43

\(A=4.3\cdot4.6+3.5\cdot4.3+4.3\cdot2.9-4.3\)

\(A=4.3\cdot4.6+3.5\cdot4.3+4.3-2.9-4.3\cdot1\)

\(A=4.3\cdot\left(4.6+3.5+2.9-1\right)\)

\(A=4.3\cdot10\)

\(A=43\)

9:(x+2)²+9=9,25

⇒9:(x+2)²+9=9,25

⇒9:(x+2)²+9=9,25

⇒9:(x+2)²=0,25

⇒(x+2)²=36

⇒hoặc x+2=√36⇒x+2=6⇒x=4

           x+2=-√36⇒x+2=-6⇒x=-8

vậy x={4;-8}

Ta có: \(\dfrac{9}{\left(x+2\right)^2}+9=9.25\)

\(\Leftrightarrow\dfrac{9}{\left(x+2\right)^2}=0.25\)

\(\Leftrightarrow\left(x+2\right)^2=36\)

\(\Leftrightarrow\left[{}\begin{matrix}x+2=6\\x+2=-6\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=4\\x=-8\end{matrix}\right.\)