\(\dfrac{3}{9}=\dfrac{3:3}{9:3}=\dfrac{1}{3}\)

\(\dfrac{15}{27}=\dfrac{15:3}{27:3}=\dfrac{5}{9}\)

\(\dfrac{28}{20}=\dfrac{28:4}{20:4}=\dfrac{7}{5}\)

\(\dfrac{5}{105}=\dfrac{5:5}{105:5}=\dfrac{1}{21}\)

\(\dfrac{24}{39}=\dfrac{24:3}{39:3}=\dfrac{8}{13}\)

3/9=.....1/3

15/27=.....5/9

28/20=....7/5

5/105=.....1/21

24/39=.....8/13

1/3

5/9

7/5

1/21

8/13

3/6=1/2

3/6 = 3:3/6:3=1/2

a: \(=\dfrac{2^{12}\cdot3^{14}}{3^{12}\cdot2^{12}}=3^2=9\)

b: \(=\dfrac{7^3\cdot2\cdot5^3}{5^2\cdot7^2\cdot6}=7\cdot5\cdot\dfrac{1}{3}=\dfrac{35}{3}\)

d: =2^5(2^8+1)/2^2(2^8+1)=2^3=8

c: \(=\dfrac{5^3\cdot3^6\cdot2^8\cdot5^4\cdot3^4\cdot2^2}{2^{10}\cdot3^{10}\cdot5^5}=5^2\)

Câu 3:

a) \(\dfrac{12}{36}=\dfrac{12:12}{36:12}=\dfrac{1}{3}\)

\(\dfrac{-16}{20}=\dfrac{-16:4}{20:4}=\dfrac{-4}{5}\)

b) \(\dfrac{21}{105}=\dfrac{21:21}{105:21}=\dfrac{1}{5}\)

\(\dfrac{35}{150}=\dfrac{35:5}{150:5}=\dfrac{7}{30}\)

Câu 4: 

a) \(\dfrac{3}{10}+\dfrac{5}{10}=\dfrac{3+5}{10}=\dfrac{8}{10}=\dfrac{4}{5}\)

b) Ta có: \(\left(-27\right)\cdot36+64\cdot\left(-27\right)+23\cdot\left(-100\right)\)

\(=\left(-27\right)\cdot\left(64+36\right)+23\cdot\left(-100\right)\)

\(=-27\cdot100-23\cdot100\)

\(=100\left(-27-23\right)\)

\(=-50\cdot100=-5000\)

c) \(\dfrac{5}{8}+\dfrac{3}{12}=\dfrac{15}{24}+\dfrac{6}{24}=\dfrac{21}{24}=\dfrac{7}{8}\)

d) Ta có: \(\dfrac{-2}{17}+\dfrac{3}{19}+\dfrac{-15}{17}+\dfrac{16}{19}+\dfrac{5}{6}\)

\(=\left(-\dfrac{2}{17}+\dfrac{-15}{17}\right)+\left(\dfrac{3}{19}+\dfrac{16}{19}\right)+\dfrac{5}{6}\)

\(=-1+1+\dfrac{5}{6}\)

\(=\dfrac{5}{6}\)

`a) ((-14).15)/(21.(-10))`

`=(-7.3.5.3)/(7.3.(-2).5)`

`=3/2`

`b) ((-7).12)/((-16).(-14))`

`=(-7.3.2.2)/(-2.2.2.(-7).2)`

`=(-3)/4`

`c) ((-11).(-5))/(15.22) `

`=(-11.(-5))/(3.5.11.2)`

`=1/6`

`d) ((-10).(-18))/((-6).25.7)`

`=(-5.2.-2.3.3)/(-2.3.5.5.7)`

`=6/35`

`e) (5.7-7.9)/(7.2+6.7)`

`=(7.(5-9))/(7.(2+6))`

`=-4/8`

`=-1/2`

`f) (11.9-22.3)/(33.2)`

`=(33.(3-2))/(33.2)`

`=1/2`

\(\frac{2.5^{22}-9.5^{21}}{25^{10}}=\frac{2.5^2.5^{20}-9.5.5^{20}}{\left[\left(5\right)^2\right]^{10}}=\frac{5^{20}\left(2.5^2-9.5\right)}{5^{20}}=2.5^2-9.5=5\left(10-9\right)=5.1=5\)

\(\frac{2\cdot5^{22}-9\cdot5^{21}}{25^{10}}=\frac{\left(2\cdot5-9\right)\cdot5^{21}}{25^{10}}=\frac{5^{21}}{5^{20}}=5\)

\(\frac{3^{10}.\left(-5\right)^{21}}{\left(-5\right)^{20}.3^{12}}=\frac{3^{10}.\left(-5\right)^{20}.\left(-5\right)}{\left(-5\right)^{20}.3^{10}.3^2}=\frac{-5}{3^2}\)

CHÚC BẠN HỌC TỐT!!!!

`4/7` giữ nguyên

`15/21=(15:3)/(21:3)=5/7`

`----`

`12/36 =(12:12)/(36:12)=1/3`

`5/12` giữ nguyên

`----`

`12/28=(12:4)/(28:4)=3/7`

`6/7` giữ nguyên

Ảnh hơi mờ 

\(\frac{3^{10}.\left(-5\right)^{21}}{\left(-5\right)^{20}.3^{12}}=\frac{3^{10}.\left(-5\right)^{20}.\left(-5\right)}{\left(-5\right)^{20}.3^{10}.3^2}=\frac{-5}{3^2}=-\frac{5}{9}\)

(-5)/9