C

C

Bài 27: Ta có: \(CP=\frac13\times CA\)

=>\(S_{BPC}=\frac13\times S_{CBA}\)

Ta có: \(S_{BPA}+S_{BPC}=S_{ABC}\)

=>\(S_{BPA}=S_{ABC}-S_{BPC}=S_{ABC}-\frac13\times S_{ABC}=\frac23\times S_{ABC}\)

Ta có: \(AN=NP=\frac12\times AP\)

=>\(S_{BNA}=\frac12\times S_{BAP}=\frac12\times\frac23\times S_{ABC}=\frac13\times S_{ABC}\)

Ta có: \(MA=MB=\frac12\times AB\)

=>\(S_{AMN}=\frac12\times S_{ABN}=\frac12\times\frac13\times S_{ABC}=\frac16\times S_{ABC}\)

Ta có: \(S_{AMN}+S_{BMNP}=S_{ABP}\)

=>\(S_{BMNP}=S_{ABP}-S_{AMN}=\frac23\times S_{ABC}-\frac16\times S_{ABC}=\frac12\times S_{ABC}\)

=>\(S_{ABC}=12:\frac12=24\left(\operatorname{cm}^2\right)\)

1............to work by car everyday

2 ........Khanh does morning exercise, he won't keep fit

3......has a small garden

4 .....has to go to school on time

5 ......she doesn't go to bed early, she will be late for class

6 .......go to the movie tonight

\(\text{⩷!⨙┏⇴⨗⨜}\)

a) \(\Rightarrow\left|\dfrac{3}{4}+x\right|=0\Rightarrow\dfrac{3}{4}+x=0\Rightarrow x=-\dfrac{3}{4}\)

b) \(\Rightarrow x+0,4=\dfrac{4}{9}:\dfrac{2}{3}=\dfrac{2}{3}\Rightarrow x=\dfrac{2}{3}-0,4=\dfrac{4}{15}\)

Kiểu này là thi òi:)

Mik thi như này nhìu nên bít:>

a: 

Input: a=20

Output: a*a

Câu e,d à bạn