(x-2)2 - (x-1)2
Những câu hỏi liên quan
$$ \frac{x^4-(x-1)^2}{(x^2+1)^2-x^2}+\frac{x^2-(x^2-1)^2}{x^2*(x+1)^2-1}+\frac{x^2*(x-1)^2-1}{x^4-(x+1)^2} $$
giải phương trình:
a) 2/x+1 - 1/x-3= 3x-11/x^2-2x-3
b) 3/x-2 +1/x=-2/x.(x-2)
c) x-3/x+3 - 2/x-3=3x+1/9-x^2
d) 2/x+1 - 1/x-2=3x-5/x^2-x-2
e) x-2/x+2 + 3/x-2=x^2-11/x^2-4
f) x+3/x+1 + x-2/x=2
g) x+5/x-5 - x-5/x+5=20/x^2-25
h) x+4/x+1 + x/x-1=2x^2/x^2-1
i) x+1/x-1 - 1/x+1=x^2+2/x^2-1
B1:tìm x biết a, (-2+x^2)(x^2-2)(x^2-2)(x^2-2)(x^2-2)=1 b, (2x+3)(x-4)+(x-5)(x-2)=(3x-5)(x-4) c,(8x-3)(3x+2)-(4x+7)(x+4)=(4x+1)(5x-1) d, 2x^2+3(x-1)(x+1)=5x(x+1) e, (8-5x)(x+2)+4(x-2)(x+1)=(2+x)(2-x) f, 4(x-1)(x+5)-(x+2)(x+5)=3(x-1)(x+2)
Bạn nên viết lại đề bài cho sáng sủa, rõ ràng để người đọc dễ hiểu hơn.
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f: =>4(x^2+4x-5)-x^2-7x-10=3(x^2+x-2)
=>4x^2+16x-20-x^2-7x-10-3x^2-3x+6=0
=>6x-24=0
=>x=4
e: =>8x+16-5x^2-10x+4(x^2-x-2)=4-x^2
=>-5x^2-2x+16+4x^2-4x-8=4-x^2
=>-6x+8=4
=>-6x=-4
=>x=2/3
d: =>2x^2+3x^2-3=5x^2+5x
=>5x=-3
=>x=-3/5
b: =>2x^2-8x+3x-12+x^2-7x+10=3x^2-12x-5x+20
=>-12x-2=-17x+20
=>5x=22
=>x=22/5
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Chúng ta sẽ giải từng phương trình một:
a. Đặt , ta có:
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Bài 1:
a, (-2+x\(^2\))(x\(^2\)-2)(x\(^2\)-2)(x\(^2\)-2)(x\(^2\)-2)=1
b, (2x+3)(x-4)+(x-5)(x-2)=(3x-5)(x-4)
c, (8x-3)(3x+2)-(4x+7)(x+4)=(4x+1)(5x-1)
d,2x\(^2\)+3(x-1)(x+1)=5x(x+1)
e,(8-5x)(x+2)+4(x-2)(x+1)=(2+x)(2-x)
f, 4(x-1)(x+5)-(x+2)(x+5)=3(x-1)(x+2)
b: =>2x^2-8x+3x-12+x^2-7x+10=3x^2-17x+20
=>-12x-2=-17x+20
=>5x=22
=>x=22/5
c: =>24x^2+16x-9x-6-4x^2-16x-7x-28=20x^2-4x+5x-1
=>-16x-34=x-1
=>-17x=33
=>x=-33/17
d: =>2x^2+3x^2-3=5x^2+5x
=>5x=-3
=>x=-3/5
e: =>8x+16-5x^2-10x+4x^2-4x-8=4-x^2
=>-6x+8=4
=>-6x=-4
=>x=2/3
f: =>4(x^2+4x-5)-x^2-7x-10=3x^2+3x-6
=>4x^2+16x-20-4x^2-10x+4=0
=>6x=16
=>x=8/3
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giải phương trình:
a, 2x-5/x+5=3
b, 2/x-1=6/x+1
c, 2x+1/x-1=5(x-1)/x+1
d, x/x-1 - 2x/x2-1=0
e, 1/x-2 + 3=x-3/2-x
f, x+1/x-2 + x-1/x+2= 2(x2+2)/x2-4
g, x+2/x-2 + 1/x+2=x(x-5)/x2-4
h, 1/x+1 - 5/x+2=15/(x+1)(2-x)
i, x-1/x+2 - x/x-2= 5x-2/4-x2
a,\(2x-5=3x+15\)
\(3x-2x=-5-15\)
\(x=-20\)
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b,\(\frac{2}{x-1}=\frac{6}{x+1}\)
\(2x+2=6x-6\)
\(4x=8\)
\(x=2\)
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\(\frac{2x+1}{x-1}=\frac{5.\left(x-1\right)}{x+1}\)
\(\frac{2x+1}{x-1}=\frac{5x-5}{x+1}\)
\(2x^2+3x+1=5x^2-10+5\)
\(3x^2-3x=10-5+1=6\)
\(3x.\left(x-1\right)=6\)
\(x.\left(x-1\right)=3\)
Lập bảng
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Xem thêm câu trả lời
a, (2+x/2-x - 4x^2/x^2-4 - 2-x/2+x):x^2-3x/2x^2-x^3
a, 2x-1/2x+1 :(2x-1+2-4x/2x+1)
b,(1/1-x -1) : (x- 1-2x/1-x +1)
c,(1/x + x-2/x^2 -4 -2+x/x^2+2x):(x^2+2x+1)/x^2
d,{1/x^2 + 1/y^2 + 2/ x+y.(1/x + 1/y )} : x^3+y^3/x^2+y^2
đề là thực hiện phép tính
a: \(=\left(\dfrac{-\left(x+2\right)}{x-2}-\dfrac{4x^2}{\left(x-2\right)\left(x+2\right)}+\dfrac{x-2}{x+2}\right)\cdot\dfrac{2x^2-x^3}{x^2-3x}\)
\(=\dfrac{-x^2-4x-4-4x^2+x^2-4x+4}{\left(x-2\right)\left(x+2\right)}\cdot\dfrac{x^2\left(2-x\right)}{x\left(x-3\right)}\)
\(=\dfrac{-4x^2-8x}{x+2}\cdot\dfrac{-x}{x-3}\)
\(=\dfrac{-4x\left(x+2\right)}{x+2}\cdot\dfrac{-x}{x-3}=\dfrac{4x^2}{x-3}\)
b: \(=\dfrac{2x-1}{2x+1}:\left(2x-1+\dfrac{2-4x}{2x+1}\right)\)
\(=\dfrac{2x-1}{2x+1}:\dfrac{4x^2-1+2-4x}{2x+1}\)
\(=\dfrac{2x-1}{4x^2-4x+1}=\dfrac{1}{2x-1}\)
c: \(=\left(\dfrac{1}{1-x}-1\right):\left(x+1-\dfrac{2x-1}{x-1}\right)\)
\(=\dfrac{1-1+x}{1-x}:\dfrac{x^2-1-2x+1}{x-1}\)
\(=\dfrac{-x}{x-1}\cdot\dfrac{x-1}{x\left(x-2\right)}=\dfrac{-1}{x-2}\)
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Bài 1:Tìm x,biết:a,(x-2)(x+2)-(x-3)^29b,(x-1)(x^2+1)-(x+1)(x^2-x+1)x(2-x)c,(x-3)(x^2+3x+9)+x(x+2)(2-x)1d,(x+1)^3-(x-1)^{^{ }3}-6(x-1)^2-19Bài 2:Viết về dạng bình phương hoặc dạng tích:a,dfrac{1}{27}x^3+x^2+9x+27b,8u^3-60u^2v+150uv^2-125v^3c,x^3+3x^2+3x+1+3(x^2+2x+1)y+3xy^2+3y^3+y^3
Đọc tiếp
Bài 1:Tìm x,biết:
a,(x-2)(x+2)-(x-3)\(^2\)=9
b,(x-1)(x\(^2\)+1)-(x+1)(x\(^2\)-x+1)=x(2-x)
c,(x-3)(x\(^2\)+3x+9)+x(x+2)(2-x)=1
d,(x+1)\(^3\)-(x-1)\(^{^{ }3}\)-6(x-1)\(^2\)=-19
Bài 2:Viết về dạng bình phương hoặc dạng tích:
a,\(\dfrac{1}{27}\)x\(^3\)+x\(^2\)+9x+27
b,8u\(^3\)-60u\(^2\)v+150uv\(^2\)-125v\(^3\)
c,x^3+3x^2+3x+1+3(x^2+2x+1)y+3xy^2+3y^3+y^3
a. (x - 2)(x + 2) - (x - 3)2 = 9
<=> x2 - 22 - (x - 3)2 = 32
<=> x - 2 - (x - 3) = 3
<=> x - 2 - x + 3 = 3
<=> x - x = 3 - 3 + 2
<=> 0 = 2 (Vô lí)
Vậy nghiệm của PT là S = \(\varnothing\)
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b: Ta có: \(\left(x-1\right)\left(x^2+1\right)-\left(x+1\right)\left(x^2-x+1\right)=x\left(2-x\right)\)
\(\Leftrightarrow x^3+x-x^2-1-x^3-1=2x-x^2\)
\(\Leftrightarrow-x^2+x-2-2x+x^2=0\)
\(\Leftrightarrow-x=2\)
hay x=-2
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Xem thêm câu trả lời
2*(x+1/x)^2 +(x^2+1/x^2)^2 -(x^2+1/x^2)*(x+1/x)^2=(x+1)^2
1.Tìm xa) (x - 5)(x + 5) - (x + 3)^2 + 3 (x - 2)^2 (x + 1)^2 - (x + 4)(x - 4) +3x^2b) (2x + 3)^2 + (x - 1)(x + 1) 5 (x + 2)^2 - (x - 5)(x + 1) + (x + 4)^2c) (-x + 5)(x - 2) + (x - 7)(x + 7) (3x + 1)^2 - (3x - 2)(3x + 2)d) (5x - 1)(x + 1) - 2(x - 3)^2 (x + 2)(3x - 1) - (x + 4)^2 + (x^2 - x)2.Rút gọn :a) A 3 (x - 1)^2 - (x + 1)^2 + 2(x - 3)(x + 3) - (2x + 3)^2 - (5 - 20x)b) B 5x (x - 7)(x + 7) - x (2x - 1)^2 - (x^3 + 4x^2 - 246x) - 175c) C -2x (3x + 2)^2 + (4x + 1)^2 + 2 (x^3 + 8x + 3x - 2 )...
Đọc tiếp
1.Tìm x
a) (x - 5)(x + 5) - (x + 3)^2 + 3 (x - 2)^2 = (x + 1)^2 - (x + 4)(x - 4) +3x^2
b) (2x + 3)^2 + (x - 1)(x + 1) = 5 (x + 2)^2 - (x - 5)(x + 1) + (x + 4)^2
c) (-x + 5)(x - 2) + (x - 7)(x + 7) = (3x + 1)^2 - (3x - 2)(3x + 2)
d) (5x - 1)(x + 1) - 2(x - 3)^2 = (x + 2)(3x - 1) - (x + 4)^2 + (x^2 - x)
2.Rút gọn :
a) A= 3 (x - 1)^2 - (x + 1)^2 + 2(x - 3)(x + 3) - (2x + 3)^2 - (5 - 20x)
b) B= 5x (x - 7)(x + 7) - x (2x - 1)^2 - (x^3 + 4x^2 - 246x) - 175
c) C = -2x (3x + 2)^2 + (4x + 1)^2 + 2 (x^3 + 8x + 3x - 2 ) - (5 - x)
Quy đồng mẫu các phân thức:
1) 7x-1/2x^2+6x; 3-2x/x^2-9
2) 2x-1/x-x^2; x+1/2-4x+2x^2
3) x-1/x^3+1; 2x/x^2-x+1; 2/x+1
4) 7/5x; 4/x-2y; x-y/8y^2-2x^2
5) x/x^3-1; x+1/x^2-x; x-1/x^2+x+1
6) x/x^2-2ax+a^2; x+a/x^2-ax