câu1

(3x-1).(1/2x5)=0

=>3x-1=0               hoặc  1/2x5=0

=>x=1/3                            =>x=0

câu2

1/4+1/3 :(2x-1)=5

=> 1/3:(2x-1)=19/4

=>2x-1       =57/4

=>2x=61/4

=>x=61/8

còn hai câu sau bn ghi đề mik ko hỉu

1.

a)(3x-1)(1/2x5)=0

=>3x-1=0 hoặc 1/2x5=0

3x=0+1               x=0:1/2:5

x=1/3                  x=0

Vậy x=1/3 hoặc x=0

b)1/4+1/3:(2x-1)=5

1/3:(2x-1)=5-1/4=20/4-1/4=19/4

2x-1=1/3:19/4=1/3*4/19=4/57

2x=4/57+1=4/57+57/57=61/57

x=61/57:2=61/57*1/2=61/114

Vậy x=61/114

c)(2x+2/5)^2-9/25=0=0^2-9/25

=>2x+2/5=0

2x=0-2/5

x=-2/5:2=-2/5*1/2

x=-1/5

Vậy x=-1/5

d)(3x-1/2)^3+1/9=0=0^3+1/9

=>3x-1/2=0

3x=0+1/2

x=1/2:3=1/2*1/3

x=1/6

Vậy x=1/6

Làm nhiêu đó chết người đó bạn , đề nhiều số nữa

\(a)4(15-18)-(3-5).(-3)^2\)

\(=4.\left(-3\right)-2.9\)

\(=6\)

\(b)(-4-11):(-3)\)

\(=-15:\left(-3\right)\)

\(=5\)

\(c)143-(-57)-(-2)^3.(-3)^0\)

\(=143+57+8.1\)

\(=208\)

\(d,\left(-5\right).\left[\left(90-2.5\right)-10^2+10:\left|-2\right|\right]\)

\(=-5.\left[80-100+10:2\right]\)

\(=-5.-15\)

\(=75\)

a. ….= 50 : 10 = 5

Hoặc…= 50 : 2 : 5 = 25 : 5 = 5

Hoặc…= 50 : 5 : 2 = 10 : 2 = 5

b. Kết quả: 1

c. Kết quả: 2

2:

=>x^3-1-2x^3-4x^6+4x^6+4x=6

=>-x^3+4x-7=0

=>x=-2,59

4: =>8x-24x^2+2-6x+24x^2-60x-4x+10=-50

=>-62x+12=-50

=>x=1

\(2x^3-50=0\)

\(\Rightarrow2\left(x^3-25\right)=0\)

\(\Rightarrow x^3-25=0\Rightarrow x^3=25\)

\(\Rightarrow x=\sqrt[3]{25}\)

\(x^2-5x=-6\)

\(\Rightarrow x\left(x-5\right)=-6\)

Xét ước

\(\left(2x-1\right)^2-\left(3x+5\right)=0\)

\(\Rightarrow4x^2-4x+1-3x-5=0\)

\(\Rightarrow4x^2-4-7x=0\)

\(\Rightarrow4x^2-7x=4\)

\(\Rightarrow x\left(4x-7\right)=4\)

Xét ước

\(4x^2-20x+25=0\)

\(\Rightarrow\left(2x-5\right)^2=0\)

\(\Rightarrow2x=5\Rightarrow x=\dfrac{5}{2}\)

\(\left(3x-1\right)^2-\left(x-2\right)^2=0\)

\(\Rightarrow\left(3x-1\right)^2=\left(x-2\right)^2\)

\(\Rightarrow\left|3x-1\right|=\left|x-2\right|\)

Xét dấu:v

b: ta có: \(x^2-5x=-6\)

\(\Leftrightarrow x^2-5x+6=0\)

=>(x-2)(x-3)=0

=>x=2 hoặc x=3

c: Sửa đề:  \(\left(2x-1\right)^2-\left(3x+5\right)^2=0\)

\(\Leftrightarrow\left(2x-1-3x-5\right)\left(2x-1+3x+5\right)=0\)

\(\Leftrightarrow\left(-x-6\right)\left(5x+4\right)=0\)

=>x=-6 hoặc x=-4/5

d: ta có: \(4x^2-20x+25=0\)

\(\Leftrightarrow\left(2x-5\right)^2=0\)

=>2x-5=0

hay x=5/2

e: \(\Leftrightarrow\left(3x-1-x+2\right)\left(3x-1+x-2\right)=0\)

\(\Leftrightarrow\left(2x+1\right)\left(4x-3\right)=0\)

hay \(x\in\left\{-\dfrac{1}{2};\dfrac{3}{4}\right\}\)

a: =>x-3/4=1/6-1/2=1/6-3/6=-2/6=-1/3

=>x=-1/3+3/4=-4/12+9/12=5/12

b: =>x(1/2-5/6)=7/2

=>-1/3x=7/2

hay x=-21/2

c: (4-x)(3x+5)=0

=>4-x=0 hoặc 3x+5=0

=>x=4 hoặc x=-5/3

d: x/16=50/32

=>x/16=25/16

hay x=25

e: =>2x-3=-1/4-3/2=-1/4-6/4=-7/4

=>2x=-7/4+3=5/4

hay x=5/8

a/ (3x - 1).(1/2.5) = 0 => 3x - 1 = 0 => 3x = 1 => x = 1/3

b/ 1/4 + 1/3 : (2x - 1) = 5 => 1/3 : (2x - 1) = 19/4 => 2x - 1 = 4/57 => 2x = 61/57 => x = 61/114

c/ (2x + 2/5)² - 9/25 = 0 => (2x + 2/5)² = 9/25 => 2x + 2/5 = 3/5 => 2x = 1/5 => x = 1/10 

                                                         hoặc             2x + 2/5 = -3/5 => 2x = -1 => x = -1/2

     Vậy x = {1/10 ; -1/2}

d/ (3x - 1/2)³ + 1/9 = 0 => (3x - 1/2)³ = -1/9 => 3x - 1/2 = -1/3 => 3x = 1/6 => x = 1/18

bạn viết rõ hơn được không

la sao bn

b: \(\Leftrightarrow\dfrac{7x+10}{x+1}\left(x^2-x-2-2x^2+3x+5\right)=0\)

\(\Leftrightarrow\left(7x+10\right)\left(-x^2+2x+3\right)=0\)

\(\Leftrightarrow\left(7x+10\right)\left(x^2-2x-3\right)=0\)

=>(7x+10)(x-3)=0

hay \(x\in\left\{-\dfrac{10}{7};3\right\}\)

d: \(\Leftrightarrow\dfrac{13}{2x^2+7x-6x-21}+\dfrac{1}{2x+7}-\dfrac{6}{\left(x-3\right)\left(x+3\right)}=0\)

\(\Leftrightarrow\dfrac{13}{\left(2x+7\right)\left(x-3\right)}+\dfrac{1}{\left(2x+7\right)}-\dfrac{6}{\left(x-3\right)\left(x+3\right)}=0\)

\(\Leftrightarrow26x+91+x^2-9-12x-14=0\)

\(\Leftrightarrow x^2+14x+68=0\)

hay \(x\in\varnothing\)