c/m dang thuc : (x^2 +3xy)/(x^2 - 9y^2) + (2x^2 -5xy-3y^2)/(x^2-6xy+9y^2)= (3x^2 +2xy+3xz +6yz)/(xz -3yz +z^2-3xy)
c/m dang thuc : (x^2 +3xy)/(x^2 - 9y^2) + (2x^2 -5xy-3y^2)/(x^2-6xy+9y^2)= (3x^2 +2xy+3xz +6yz)/(xz -3yz +z^2-3xy)
\(\dfrac{x^2+3xy}{x^2-9y^2}+\dfrac{2x^2-5xy-3y^2}{x^2-6xy+9y^2}=\dfrac{3x^2+2xy+3xz+6yz}{x^2-3yz+xz-3xy}\)
Chứng minh đẳng thức trên
xin hỏi bạn có viết lộn không, vế trái không có Z mà tại sao vế phải lại xuất hiện Z vậy
(2xy: x^2 - y^2 + x-y : 2x + 2y) : x+y:2x + y:y-x
x^2+3xy: x^2 - 9y^2 + 2x^2 - 5xy- 3y^2 : 6xy - x^2- 9y^2 - x^2+ xz + xy + yz: 3yz - x^2 - xz + 3xy
chứng minh đẳng thức sau
a,\(\frac{x^2+3xy}{x^2-9y^2}+\frac{2x^2-5xy-3y^2}{6xy-x^2-9y^2}=\frac{x^2+xz+xy+yz}{3yz-x^2-xz+3xy}\)
b,\(\frac{y-z}{\left(x-y\right)\left(x-z\right)}+\frac{z-x}{\left(y-z\right)\left(y-x\right)}+\frac{x-y}{\left(z-x\right)\left(z-y\right)}=\frac{2}{x-y}+\frac{2}{y-z}+\frac{2}{z-x}\)
Phân tích đa thức sau thành nhân tử
9y^3-y
8y^3-2y(1-2y)^2
2x^3-8x^2+8x
2x^4-6x^3+6x^2-2x
x^3-6x^2y+9xy^2-x
5x^4-15x^3y+15x^2y^2-5xy^3-5x
3x^2+3xy-x-y
6xy-x^2-y^2+25
7m-7n-m^2+2mn-n^2
3xy-3xz+2xyz-xy^2-xz^2
a)\(9y^3-y\)
\(=y\left(9y^2-1\right)\)
\(=y\left(3y-1\right)\left(3y+1\right)\)
\(9y^3-y=y\left(9y^2-1\right)=y\left(3y+1\right)\left(3y-1\right)\)
\(8y^3-2y\left(1-2y\right)^2=2y\left[\left(2y\right)^2-\left(1-2y\right)^2\right]=2y\left(4y-1\right)\)
\(2x^3-8x^2+8x=2x\left(x^2-4x+4\right)=2x\left(x-2\right)^2\)
\(2x^4-6x^3+6x^2-2x=2x\left(x^3-3x^2+3x-1\right)=2x\left(x-1\right)^3\)\(x^3-8x^2+8x=x\left(x^2-8x+8\right)\)
\(5x^4-15x^3y+15x^2y^2-5xy^3-5x=5x\left(x^3-3x^2y+3xy^2-y^3-1\right)=5x\left[\left(x-y\right)^3-1\right]=5x\left(x-y-1\right)\left(x^2-2xy+y^2+x-y+1\right)\)
a,x^2+2xy^3-3z+4xy-5xy^2+2xy-5z
b,(x-3y).x^2-3xy+9y)
c,(2x-y).(2x+y)
d,(3x-y).(2y+5)-16x4y
Giúp mình bài này nhé mình đang cần gấp
a) \(x^2+2xy^3-3z+4xy-5xy^2+2xy-5z\)
\(=x^2+2xy^3-5xy^2-\left(3z+5z\right)+\left(4xy+2xy\right)\)
\(=x^2+2xy^3-5xy^2-8z+6xy\)
b) \(\left(x-3y\right)\left(x^2-3xy+9y^2\right)\)
\(=\left(x-3y\right)\left[x^2-x\cdot3y+\left(3y\right)^2\right]\)
\(=x^3-\left(3y\right)^3\)
\(=x^3-27y^3\)
c) \(\left(2x-y\right)\left(2x+y\right)\)
\(=\left(2x\right)^2-y^2\)
\(=4x^2-y^2\)
d) \(\left(3x-y\right)\left(2y+5\right)-16x4y\)
\(=6xy+15x-2y^2-5y-64xy\)
\(=-58xy+15x-2y^2-5y\)
a) x^2+2xy+y^2-16
b) 3x^2+5x-3xy-5y
c) 4x^2-6x^3y-2x^2+8x
d) x^2-4-2xy+y^2
e) x^3-4x^2-12x+27
g) 3x^2-18x+27
h) x^2-y^2-z^2-2yz
k) 4x^2(x-6)+9y^2(6-x)
l)6xy+5x-5y-3x^2-3y^2
a) x^2+2xy+y^2-16
=(x+y)2-16
=(x+y-4)(x+y+4)
b) 3x^2+5x-3xy-5y
=(3x2-3xy)+(5x-5y)
=3x(x-y)+5(x-y)
=(x-y)(3x+5)
c) 4x^2-6x^3y-2x^2+8x
ko bik hoặc sai đề
d) x^2-4-2xy+y^2
=(x-y)2-4
=(x-y+2)(x-y-2)
e) x^3-4x^2-12x+27
=sai đề
g) 3x^2-18x+27
=3(x2-6x+9)
=3(x-3)2
h) x^2-y^2-z^2-2yz
=x2-(y2+z2+2yx)
=x2-(y+z)2
=(x-y-z)(x+y+z)
k) 4x^2(x-6)+9y^2(6-x)
=4x2(x-6)-9y2(x-6)
=(x-6)(4x2-9y2)
=(x-6)(2x-3y)(2x+3y)
l)6xy+5x-5y-3x^2-3y^2
=(5x-5y)+(-3x2+6xy-3y2)
=5(x-y)-3(x2-2xy+y2)
=5(x-y)-3(x-y)2
=(x-y)(5-3(x-y))
=(x-y)(5-3x+3y)
Phân tích đa thức thành nhân tử
1, x\(^2\)-xy+x-y
2, xz+yz-5x-5y
3, 3x\(^2\)-3xy-5x+5y
4, x\(^2\)-2xy+y\(^2\)-xz+yz
5, 3x\(^2\)+6xy+3y\(^2\)-3z\(^2\)
6, 45+x\(^{^{ }3}\)-5x\(^2\)-9x
7, x\(^2\)-6x+5
8,x\(^2\)+7x+12
9, 2x\(^2\)-7x+3
10, 3x\(^2\)-12y\(^2\)
11, 5xy\(^2\)-10xyz+5xz\(^2\)
12,x\(^2\)-y\(^2\)-x+y
13, a\(^3\)x-ab+b-x
14, (1+x\(^2\))-4x(1-x\(^2\))
CÁC CẬU GIẢI CHI TIẾT GIÚP MÌNH VỚI Ạ
13: =x(a^3-1)-b(a-1)
=x(a-1)(a^2+a+1)-b(a-1)
=(a-1)(a^2x+a*x+x-b)
12: =(x-y)(x+y)-(x-y)
=(x-y)(x+y-1)
10: =3(x^2-4y^2)
=3(x-2y)*(x+2y)
7: =x^2-x-5x+5=(x-1)(x-5)
8: =x^2+3x+4x+12=(x+3)(x+4)
9: =2x^2-6x-x+3=(x-3)(2x-1)
bai 1: thuc hiem phep tinh.
a,(3x^3y-1/2x^2+1/5xy).6xy^3
b, 2/3x^2y.(3xy-x^2+y)
c, (xy-1).(xy+5)
d, (x^2y^2-1/2xy+2xy)x-2y
c) (xy-1).(xy+5)
= x2y2+5xy-xy-5
=x2y2+4xy-5
a) b) d) bạn có thể ghi rõ được ko