3 , 5 : − 3 2 = 35 10 : − 3 2 = 7 2 . − 2 3 = 7. ( − 2 ) 2.3 = − 7 3 = − 2 1 3

a) Gọi số cần tìm là: `x`   \(\left(x\in Q;x\ne0\right)\)

Ta có: \(-\dfrac{25}{16}=\dfrac{-5}{12}x\)

`=>` \(x=-\dfrac{25}{16}\div\dfrac{-5}{12}=\dfrac{15}{4}\)

Vậy \(-\dfrac{25}{16}=\dfrac{15}{4}.\dfrac{-5}{12}\).

b) Gọi số cần tìm là: \(y\)   \(\left(y\in Q;y\ne0\right)\)

Ta có: \(-\dfrac{25}{16}=-\dfrac{4}{5}\div y\)

\(\Rightarrow y=-\dfrac{4}{5}\div\dfrac{-25}{16}=\dfrac{64}{125}\)

Vậy \(-\dfrac{25}{16}=-\dfrac{4}{5}\div\dfrac{64}{125}\).

a) Gọi số cần tìm là: x=−2516÷−512=154

Vậy 

−2516=−45÷64125

.

\(15^8.2^4=\left(15^2\right)^4.2^4=225^4.2^4=\left(225.2\right)^4=450^4\\ 27^5:32^3=\left(3^3\right)^5:\left(2^5\right)^3=3^{15}:2^{15}=\left(\dfrac{3}{2}\right)^{15}\)

A. 16/35 x -7/10= -8/25

B.12/5 : -15/2 = -8/25

a: \(-\dfrac{8}{25}=\dfrac{-7}{10}\cdot\dfrac{16}{35}\)

b: \(-\dfrac{8}{25}=\dfrac{12}{5}:\dfrac{-15}{2}\)

a) \(-\frac{15}{32}=-\frac{1}{4}+\left(-\frac{7}{32}\right)\)

b) \(-\frac{15}{32}=\frac{1}{32}-\frac{1}{2}\)

\(a.\dfrac{-25}{16}=-\dfrac{5}{12}.\dfrac{15}{4}\\ b.-\dfrac{25}{16}=-\dfrac{4}{5}:\dfrac{64}{125}\)

a) \(\dfrac{-25}{16}=\dfrac{-5}{12}\cdot\dfrac{15}{4}\)

b) \(\dfrac{-4}{5}:\dfrac{64}{125}=-\dfrac{25}{16}\)

                                                             Giải

a) Ta có : \(\frac{-25}{16}=\frac{-5}{12}.\frac{15}{4}\)

b) Ta có : \(\frac{-25}{16}=\frac{-4}{5}.\frac{64}{125}\)

\(a,\dfrac{-3}{35}=\dfrac{-5}{7}\cdot\dfrac{3}{25}\\ b,\dfrac{-3}{35}=\dfrac{-2}{5}:\dfrac{14}{3}\)

a: \(\dfrac{-3}{35}=\dfrac{-5}{7}\cdot\dfrac{3}{25}\)

b: \(-\dfrac{3}{35}=\dfrac{-2}{5}:\dfrac{14}{3}\)

a: −335=−25:143